tim so co co hai chu so, biet rang khi chia so do cho chu so hang don vi ta duoc thuong la chu so hang don vi va so du la chu hang chuc
cho so co 2 chu so ma hang chuc chia het cho chu so hang don vi tim so da cho biet rang khi chia so do cho hieu cua chu so hang chuc va chu so hang don vi thi duoc thuong la 15 va du 2
tim 1 so co 2 chu so biet rang neu dem so do chia cho chu so hang don vi thi duoc thuong la chu so hang don vi con so du la chu so hang chuc
tim so co 2 cs biet khi doi cho cs hang don vi cho hang chuc ta duoc 1 so moi co thuong la chu so hang don vi va so du la cs hang chuc
tim so tu nhien co 2 chu so biet rang neu lay so do do chia cho so hang don vi thi duc thuong la chu so hsng don vi va so du la chu so hang chuc cua so do
Tim so co 2 chu so,biet rang nếu lay so do chia cho hieu cua chu so hang chuc va chu so hang don vi ta co thuong la 26 du 1
Gọi số cần tìm là \(\overline{ab}\) (a < 0)
Do \(\overline{ab}\) chia cho hiệu chữ số hàng chục và hàng đơn vị là 15 dư 2
\(\Rightarrow\overline{ab}=15.\left(a-b\right)+2\)
\(\Rightarrow10a+b=15a-15b+2\)
\(\Rightarrow5a-16b+2=0\)
\(\Rightarrow5a=16b-2\Rightarrow16b>2\Rightarrow b\ge1\)
Do \(a\ge9\Rightarrow5a\ge45\Rightarrow16b-2\le45\Rightarrow16b\le47\Rightarrow b< 3\)
\(\Rightarrow1\le b< 3\)
Ta có 2 trường hợp :
TH1:\(b=1\Rightarrow5a=14\Rightarrow a=\dfrac{14}{5}\) (loại)
TH2:\(b=2\Rightarrow5a=30\Rightarrow a=6\)(thỏa mãn)
Vậy số cần tìm là 62
tim so tu nhien co 2 chu so,biet rang neu lay so do chia cho hieu cua chu so hang chuc va hang don vi, thi ta duoc thuong la 28 du 1
tim so co hai chu so lay chu do chia cho chu so hang don vi thi duoc thuong la chu so hang don vi va so du la chu so hang chuc
nho giai chi tiet nhe
Tim so tu nhien co 2 chu so biet rang neu lay so do chia cho hieu cua chu so hang chuc va hang don vi ta duoc thuong la 28 du1
Cho 1 so co 2 chu so. Biet rang so do gap 7 la chu so hang don vi neu chia so do cho chu so hang chuc cua no duoc thuong la 11 du 2. Tim so da cho.