Tim x:
2014./x-12/ + (x-12)^2= 2013.(12-x)
Tim x :
2014.\(\left|x-12\right|\)+(x-12)2=2013.\(\left|12-x\right|\)
\(Do:\left|x-12\right|=\left|12-x\right|\)
⇒2014.|x−12|+(x-12)2=2013.\(\left|x-12\right|\)
⇒2014.\(\left|x-12\right|\)+(x-12)2-2013.\(\left|x-12\right|\)=0
⇒(2014-2013).\(\left|x-12\right|\)+(x-12)2=0
⇒\(\left|x-12\right|+\left(x-12\right)^2\)=0
Do: \(\left|x-12\right|\ge0,\left(x-12\right)^2\ge0\)
⇒x-12=0
⇒x=12
2014.|x-12|+(x-12)^2=2013.|12-x| . Tìm x
Tìm x biết: 2014*/x-12/+[x-12]^2=2013*/12-x/
2014.|x-12|+(x-12)2=2013.(12-x)
Tìm x , biết
2014*|x-12|+(x-12)^2=2013*|12-x|
tìm x biết : 2014./x-12/+ (x-12)2 =2013./12-x/
2014*/x-12/+(x-)^2=2013*/12-x/
Tìm x biết : 2014 /x-12/ + (x-12)2 =2013/12-x/
o:|x−12|=|12−x|Do:|x−12|=|12−x|
⇒2014.|x−12|+(x-12)2=2013.|x−12||x−12|
⇒2014.|x−12||x−12|+(x-12)2-2013.|x−12||x−12|=0
⇒(2014-2013).|x−12||x−12|+(x-12)2=0
⇒|x−12|+(x−12)2|x−12|+(x−12)2=0
Do: |x−12|≥0,(x−12)2≥0|x−12|≥0,(x−12)2≥0
⇒x-12=0
⇒x=12
2014.|x -12|+(x-12)^2=2013.|x-12|
giải giúp mk với nha mn