a) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
M.n giup em vs mai em nop r
\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{12}{14}\)
\(70:\frac{4x+720}{x}=\frac{1}{2}\)
M.n giup em vs mai em nop r
\(70:\frac{4x+720}{x}=\frac{1}{2}\)
\(\frac{4x+720}{x}=70:\frac{1}{2}\)
\(\frac{4x+720}{x}=140\)
\(4x+720=140x\)
\(4x-140x=-720\)
\(-136x=-720\)
\(x=\frac{-720}{-136}\)
\(x=\frac{90}{17}\)
\(\frac{70x}{4x+720}=\frac{1}{2}\)
\(140x=4x+720\)
\(136x=720\)
\(x=720:136\)
\(x=\frac{90}{17}\)
\(70\div\frac{4x+720}{x}=\frac{1}{2}\)
=> \(70\cdot\frac{x}{4x+720}=\frac{1}{2}\)
=> \(\frac{70x}{4x+720}=\frac{1}{2}\)
=> \(70x\cdot2=4x+720\)
=> \(140x=4x+720\)
=> \(140x-4x=720\)
=> \(136x=720\)
=> \(x=\frac{720}{136}=\frac{90}{17}\)
tính:
a) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
b) \(\frac{3}{14}:\frac{1}{28}-\frac{13}{21}:\frac{1}{28}+\frac{29}{42}:\frac{1}{28}-8\)
Tính HƠPJ LÝ
a> \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
b>\(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
__CÒN NỮA
\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
\(=\frac{11}{125}-\left(\frac{17}{18}-\frac{8}{18}\right)+\left(\frac{17}{14}-\frac{10}{14}\right)\)
\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)
\(=\frac{11}{125}+\left(\frac{1}{2}-\frac{1}{2}\right)\)= \(\frac{11}{125}\)
b) \(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=\left(6-5-3\right)+\left(\frac{7}{3}-\frac{5}{3}-\frac{2}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2+0+\frac{-1}{2}\)
= \(-2-\frac{-1}{2}=-\left(2+\frac{1}{2}\right)=-2\frac{1}{2}\)
ấy chỗ b) thiếu bước đầu mở ngoặc r mới nhóm nhé :))
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
M.n giup em vs mai em nop r em cam on
\(\left|x+\frac{4}{15}\right|-\left|-3.75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-\frac{15}{4}=-\frac{43}{20}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-\frac{43}{20}+\frac{15}{4}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=1,6\)
=> \(x+\frac{4}{15}=1,6\) hoặc \(x+\frac{4}{15}=-1,6\)
=> \(x=\frac{4}{3}\) hoặc \(x=\frac{-28}{15}\)
Vậy..
=> x + 4/15 - 3,75 = -2,15
=> x +4/15 =-2,15 + 3,75
=> x+4/15 = 1,6
=> x = 1,6-4/15
=> x = 4/3
Tính hợp lý:
a) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
b)\(1-\frac{1}{2}+2-\frac{2}{3}+3-\frac{3}{4}+4-\frac{1}{4}-3-\frac{1}{3}-2-\frac{1}{2}-1\)
Giúp mình với!!!
trong câu hỏi tương tự có một bài giốngđè và được giải rồi, bạn xem thử đi
3/ Thực hiện phép tính bằng cách hợp lí:
a) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
b) \(1-\frac{1}{2}+2-\frac{2}{3}+3-\frac{3}{4}+4-\frac{1}{4}-3-\frac{1}{3}-2-\frac{1}{2}-1\)
mh biết làm bài này rùi bn có cần mi2h đang cho bn ko?
1. Thực hiện phép tính bằng cách hợp lí :
a, \(\frac{11}{125}\) - \(\frac{17}{18}\) -\(\frac{5}{7}\) + \(\frac{4}{9}\) + \(\frac{17}{14}\)
a)\(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{14}\)
\(=\dfrac{11}{125}-\left(\dfrac{17}{18}-\dfrac{4}{9}\right)-\left(\dfrac{5}{7}-\dfrac{17}{14}\right)\)
\(=\dfrac{11}{125}-\dfrac{5}{18}-\dfrac{-7}{14}=\dfrac{11}{125}-\dfrac{5}{18}+\dfrac{1}{2}\)
\(=\dfrac{11}{125}-\left(\dfrac{5}{18}-\dfrac{1}{2}\right)=\dfrac{11}{125}-\dfrac{-4}{18}=\dfrac{11}{125}+\dfrac{2}{9}\)
Tính nhanh a) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
b) \(1-\frac{1}{2}+2-\frac{2}{3}+3-\frac{3}{4}+4-\frac{1}{5}-3-\frac{1}{3}-2-\frac{1}{2}-1\)
a)\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{7}{14}\)
=\(\frac{11}{125}-\left(\frac{17}{18}-\frac{4}{9}\right)+\left(\frac{17}{14}-\frac{5}{7}\right)\)
=\(\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)
=\(\frac{11}{125}+\left(\frac{1}{2}-\frac{1}{2}\right)\)
=\(\frac{11}{125}\)
b)................................đề bài......................................................
= ( 1 - 1 ) + ( 2 - 2 ) + ( 3 - 3 ) + ( -1/2 + -1/2 ) + ( -2/3 + -1/3) + ( -3/4 + -1/4) + 4
= 0 + 0 + 0 + (-1) + (-1) + (-1) + 4
= 1