rút gọn
a, \(\frac{-2(x^2\times y)^5}{(y^6\times x)^2}\)
b, \(\frac{(x+1)^2}{(x-1)\times(x+1)}\)
tìm x,
a, \(\frac{1}{9}=\frac{5}{3x-5}=0\)
Những câu hỏi liên quan
Tìm x , y thỏa mãn :
a) \(\frac{1}{2}\times(\frac{3}{4}x-\frac{1}{2})^{2018}+\frac{2017}{2018}\times/\frac{4}{5}y+\frac{6}{25}/\le0\)0
b) \(2017\times/2x-y/+2018\times(y-4)^{2017}\le0\)
rút gọn :
a,\(\frac{x^5y}{\left(xy^4\right)}\)
b, \(\frac{3\times x^2\times y^5}{9\times x\times y^4}\)
c, \(\frac{\left(3\times x\times y^2\right)^4}{27\times x^5y^3}\)
\(\frac{x^5y}{xy^4}=\frac{x^4}{y^3}\)
\(\frac{3\times x^2\times y^5}{9\times x\times y^4}=\frac{xy}{3}\)
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Rút gọn \(B=\left(x^4-x+\frac{x-3}{x^3+1}\times\frac{\left(x^3-2x^2+2x-1\right)\left(x+1\right)}{x^9+x^7-3x^2-3}+1-\frac{2\left(x+6\right)}{x^2+1}\right)\times\frac{4x^2+6x+1}{\left(x+3\right)\left(4-x\right)}\)
Rút gọn biểu thức
\(\frac{x^7+3x^2+2}{x^3-1}\times\frac{3x}{x+1}\times\frac{x^2+x+1}{x^7+3x^2+2}\)
\(\frac{x^7+3x^2+2}{x^3-1}\cdot\frac{3x}{x+1}\cdot\frac{x^2+x+1}{x^7+3x^2+2}\)
\(=\frac{3x.\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)\left(x+1\right)}\)
\(=\frac{3x}{x^2-1}\)
bài 1 : tìm x biếta, frac{2}{3}timesleft(x-frac{5}{6}right)+frac{1}{4}frac{22}{9}b, frac{2}{3}:frac{x}{5}frac{10}{21}c, frac{7}{3}:frac{x}{5}frac{14}{15}d, 1-left(5frac{4}{9}times x-7frac{7}{18}right):15frac{3}{4}0bài 2 : tính gtri bta,frac{8}{7}+frac{1}{5}timesfrac{10}{9}b, frac{3}{2}+left(frac{9}{2}+frac{2}{9}right)timesleft(frac{4}{3}-frac{5}{4}right)!_ove
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bài 1 : tìm x biết
a, \(\frac{2}{3}\times\left(x-\frac{5}{6}\right)+\frac{1}{4}=\frac{22}{9}\)
b, \(\frac{2}{3}:\frac{x}{5}=\frac{10}{21}\)
c, \(\frac{7}{3}:\frac{x}{5}=\frac{14}{15}\)
d, \(1-\left(5\frac{4}{9}\times x-7\frac{7}{18}\right):15\frac{3}{4}=0\)
bài 2 : tính gtri bt
a,\(\frac{8}{7}+\frac{1}{5}\times\frac{10}{9}\)
b, \(\frac{3}{2}+\left(\frac{9}{2}+\frac{2}{9}\right)\times\left(\frac{4}{3}-\frac{5}{4}\right)\)
!_ove
a) x = 99/20
b) x = 7
c) x = 2
( chỉ lm đc đến đó thui nk )
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Cho biểu thức A = \(\frac{3x^2+3x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{x}\times\left(\frac{1}{1-x}-1\right)\)
a) Rút gọn biểu thức A
b) Tìm các giá trị nguyên của x để A nhận giá trị nguyên
c) Tìm x sao cho A < 0
a) A = \(\frac{3x^2+3x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{x}\cdot\left(\frac{1}{1-x}-1\right)\)
A = \(\frac{3x^2+3x-3}{x^2+2x-x-2}-\frac{x+1}{x+2}+\frac{x-2}{x}\cdot\left(\frac{1-1+x}{1-x}\right)\)
A = \(\frac{3x^2+3x-3}{\left(x-1\right)\left(x+2\right)}-\frac{x+1}{x+2}+\frac{x-2}{x}\cdot\frac{x}{1-x}\)
A = \(\frac{3x^2+3x-3}{\left(x-1\right)\left(x+2\right)}-\frac{x+1}{x+2}-\frac{x-2}{x-1}\)
A = \(\frac{3x^2+3x-3}{\left(x-1\right)\left(x+2\right)}-\frac{\left(x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)}-\frac{\left(x-2\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}\)
A = \(\frac{3x^2+3x-3-x^2+1-x^2+4}{\left(x-1\right)\left(x+2\right)}\)
A = \(\frac{x^2+3x+2}{\left(x-1\right)\left(x+2\right)}\)
A = \(\frac{x^2+2x+x+2}{\left(x-1\right)\left(x+2\right)}\)
A = \(\frac{\left(x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}\)
A = \(\frac{x+1}{x-1}\) (Đk: \(x-1\ge0\) => x \(\ge\)1)
b) Ta có: A = \(\frac{x+1}{x-1}=\frac{\left(x-1\right)+2}{x-1}=1+\frac{2}{x-1}\)
Để A \(\in\)Z <=> 2 \(⋮\)x - 1
<=> x - 1 \(\in\)Ư(2) = {1; -1; 2; -2}
<=> x \(\in\){2; 0; 3; -1}
c) Ta có: A < 0
=> \(\frac{x+1}{x-1}< 0\)
=> \(\hept{\begin{cases}x+1< 0\\x-1>0\end{cases}}\) hoặc \(\hept{\begin{cases}x+1>0\\x-1< 0\end{cases}}\)
=> \(\hept{\begin{cases}x< -1\\x>1\end{cases}}\)(loại) hoặc \(\hept{\begin{cases}x>-1\\x< 1\end{cases}}\)
=> -1 < x < 1
Edogawa Conan
Thiếu dòng đầu \(ĐKXĐ:\hept{\begin{cases}x\ne1\\x\ne-2\\x\ne0\end{cases}}\)
ĐKXĐ : \(\) x # +1 ; x # - 1 ; x # -2 ; x # 0 ; x # 2
Ta có: \(A=\frac{3x^2+3x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{x}.\left(\frac{1}{1-x}-1\right)\)
\(=\frac{3x^2+3x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{x}.\frac{x}{1-x}\)
\(=\frac{3x^2+3x-3}{x^2+x-2}-\frac{x+1}{x+2}+\frac{x-2}{1-x}\)
\(=\frac{3x^2+3x-3}{x^2+x-2}-\left(\frac{x+1}{x+2}+\frac{x-2}{x-1}\right)\)
\(=\frac{3x^2+3x-3}{x^2+x-2}-\frac{2x^2-5}{x^2+x-2}\)
\(=\frac{x^2+3x+2}{x^2+x-2}=\frac{\left(x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}\)
\(\frac{x+1}{x-1}\)
b. Ta có: \(A=\frac{x+1}{x-1}=\frac{x-1+2}{x-1}=1+\frac{2}{x-1}\)
Để A nhận giá trị nguyên thì: \(2⋮\left(x-1\right)\Rightarrow\left(x-1\right)\inƯ\left(2\right)\)
+) x - 1 = 1 => x = 2 (loại)
+) x - 1 = 2 => x = 3
+) x - 1 = -1 => x = 0 (loại)
+) x - 1 = -2 => x = -1 (loại)
Vậy x = 3 là giá trị cần tìm.
c. \(A< 0\Leftrightarrow\frac{x+1}{x-1}< 0\)
\(\Leftrightarrow\hept{\begin{cases}x+1>0\\x-1< 0\end{cases}}\) hoặc \(\hept{\begin{cases}x+1< 0\\x-1>0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x>-1\\x< 1\end{cases}}\) hoặc \(\hept{\begin{cases}x< -1\\x>1\end{cases}}\)(vô lý)
Vậy \(-1< x< 1\) và x # 0 là giá trị cần tìm
Tìm x, biết:
a) \(\frac{4}{7}\times x-\frac{2}{3}=\frac{1}{5}\)
b) \(\frac{2}{9}-\frac{7}{8}\times x=\frac{1}{3}\)
c) \(\frac{4}{5}+\frac{5}{7}\div x=\frac{1}{6}\)
\(\frac{4}{7}\times x=\frac{1}{5}+\frac{2}{3}\)
\(\frac{4}{7}x=\frac{13}{15}\)
\(\Rightarrow x=\frac{91}{60}\)
các bài còn lại tương tự nha
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mấy cái này dễ mà toán tìm x này là cơ bản!!
67865785685685785785774677567568568
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\(\frac{4}{7}\times x-\frac{2}{3}=\frac{1}{5}\)
\(\frac{4}{7}\times x=\frac{2}{3}+\frac{1}{5}\)
\(\frac{4}{7}\times x=\frac{13}{15}\)
\(x=\frac{13}{15}\div\frac{4}{7}\)
\(x=\frac{91}{60}\)
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Xem thêm câu trả lời
Các bạn ơi ,giúp mình vớiBài 1:Rút gọna)frac{2^{19}times27^3+15times4^9times9^4}{6^9times2^{10}+12^{10}}b)frac{left(frac{-1}{2}right)^3-left(frac{3}{4}right)^3timesleft(-2right)^2}{2timesleft(-1right)^5+left(frac{3}{4}right)^2-frac{3}{8}}c)frac{45times9^4-2times6^4}{2^{19}times3^8+6^8times20}Bài 2:Tìm xa)5^x+5^{x+2}650b)3^{x-1}+5times3162
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Các bạn ơi ,giúp mình với
Bài 1:Rút gọn
a)\(\frac{2^{19}\times27^3+15\times4^9\times9^4}{6^9\times2^{10}+12^{10}}\)
b)\(\frac{\left(\frac{-1}{2}\right)^3-\left(\frac{3}{4}\right)^3\times\left(-2\right)^2}{2\times\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
c)\(\frac{45\times9^4-2\times6^4}{2^{19}\times3^8+6^8\times20}\)
Bài 2:Tìm x
a)\(5^x+5^{x+2}=650\)
b)\(3^{x-1}+5\times3=162\)
rút gọn:a)left(frac{1}{2+2sqrt{x}}+frac{1}{2-2sqrt{x}}-frac{x^2+1}{1-x^2}right)timesleft(1+frac{1}{x}right)b)left(frac{2sqrt{xy}}{x-y}+frac{sqrt{x}-sqrt{y}}{2sqrt{x}+sqrt{y}}right)timesfrac{2sqrt{x}}{sqrt{x}+sqrt{y}}+frac{sqrt{y}}{sqrt{y}-sqrt{x}}c)left(frac{x-1}{sqrt{x}-1}+frac{xsqrt{x}-1}{1-x}right)divfrac{left(sqrt{x}-1right)^2+sqrt{x}}{sqrt{x}+1}
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rút gọn:
a)\(\left(\frac{1}{2+2\sqrt{x}}+\frac{1}{2-2\sqrt{x}}-\frac{x^2+1}{1-x^2}\right)\times\left(1+\frac{1}{x}\right)\)
b)\(\left(\frac{2\sqrt{xy}}{x-y}+\frac{\sqrt{x}-\sqrt{y}}{2\sqrt{x}+\sqrt{y}}\right)\times\frac{2\sqrt{x}}{\sqrt{x}+\sqrt{y}}+\frac{\sqrt{y}}{\sqrt{y}-\sqrt{x}}\)
c)\(\left(\frac{x-1}{\sqrt{x}-1}+\frac{x\sqrt{x}-1}{1-x}\right)\div\frac{\left(\sqrt{x}-1\right)^2+\sqrt{x}}{\sqrt{x}+1}\)
a, dk \(x\ge0.x\ne1\)
\(\left(\frac{1+\sqrt{x}+1-\sqrt{x}}{2\left(1-x\right)}-\frac{x^2+1}{1-x^2}\right)\left(\frac{x+1}{x}\right)\)=\(\left(\frac{1}{1-x}-\frac{x^2+1}{1-x^2}\right)\left(\frac{x+1}{x}\right)\)
=\(\left(\frac{1+x-x^2-1}{1-x^2}\right)\left(\frac{x+1}{x}\right)=\frac{x\left(1-x\right)\left(x+1\right)}{x\left(1-x\right)\left(1+x\right)}=1\)
phan b,c ban tu lam not nhe dai lam mk ko lam dau mk co vc ban rui
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