a, \(\sqrt{1\frac{24}{25}.5\frac{1}{16}.0,01}=\sqrt{\frac{49}{25}.\frac{81}{16}.\frac{1}{100}}\)
b, \(\sqrt{2,25.1,46-2,25.0,02}\)
Những câu hỏi liên quan
Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
a) = \(\frac{7}{2}\)
b) = \(\frac{643}{64}\)
c) = 0
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Rút gọn biểu thức:
a)\(\sqrt{\frac{25}{81}\cdot\frac{16}{49}\cdot\frac{169}{9}}\)
b) \(\sqrt{3\frac{1}{16}\cdot2\frac{14}{25}\cdot2\frac{34}{81}}\)
a) \(\sqrt{\frac{25}{81}\cdot\frac{16}{49}\cdot\frac{169}{9}}\\ =\sqrt{\left(\frac{5}{9}\right)^2\cdot\left(\frac{4}{7}\right)^2\cdot\left(\frac{13}{3}\right)^2}\\ =\sqrt{\left(\frac{5}{9}\cdot\frac{4}{7}\cdot\frac{13}{3}\right)^2}\\ =\frac{5}{9}\cdot\frac{4}{7}\cdot\frac{13}{3}\\ =\frac{260}{189}\)
b) \(\sqrt{3\frac{1}{6}\cdot2\frac{14}{25}\cdot2\frac{34}{81}}\\ =\sqrt{\frac{19}{6}\cdot\frac{64}{25}\cdot\frac{196}{81}}\\ =\sqrt{\frac{19}{6}\cdot\left(\frac{8}{5}\right)^2\cdot\left(\frac{14}{9}\right)^2}\\ =\sqrt{\frac{19}{6}\cdot\left(\frac{8}{5}\cdot\frac{14}{9}\right)^2}\\ =\sqrt{\frac{19}{6}\cdot\frac{112}{45}}\\ =\sqrt{\frac{1064}{135}}\)
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Bổ sung câu b :
\(\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}=\sqrt{\frac{49}{16}.\frac{64}{25}.\frac{196}{81}}=\sqrt{\frac{49}{16}}.\sqrt{\frac{64}{25}}.\sqrt{\frac{196}{81}}=\frac{7}{4}.\frac{8}{5}.\frac{14}{9}=\frac{196}{45}\)
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Bạn kia làm sai nhé :
a) \(\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{169}{9}}=\sqrt{\frac{25}{81}}.\sqrt{\frac{16}{49}}.\sqrt{\frac{169}{9}}=\frac{5}{9}.\frac{4}{7}.\frac{13}{3}=\frac{260}{189}\)
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Cho y=\(\frac{1+\sqrt{x}}{1-\sqrt{x}}\)
Cmr Với mọi x thuộc A=\((\frac{16}{9};\frac{25}{16};\frac{49}{36};\frac{100}{81})\)
thì y thuộc Z
Bài 1 : Tính hợp lý
\(\sqrt{0,36}:\sqrt{\frac{25}{16}}+\frac{1}{4}+\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-\sqrt{\frac{1}{16}}\)
= 0,6 : 5/4 + 1/4 + 2/9 : 5/9 - 1/4
= 3/5 . 4/5 + 2/9 . 9/5
= 12/25 + 2/5
= 22/25
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A = \(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
B = \(\sqrt{4+36+81}\)
C = \(\sqrt{1^{3^{ }}+}2^3\)
E = \(\left(\sqrt{\frac{1}{9}+\sqrt{\frac{25}{36}-\sqrt{\frac{49}{81}}:}\sqrt{\frac{441}{324}}}\right)\)
F = \(-4.\sqrt{\frac{1}{16}+3.\sqrt{\frac{1}{9}}-}5.\sqrt{0,04}\)
Mg các bạn giúp mik ạ
Cảm ơn ạ
\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)
\(\sqrt{4+36+81}\)
\(=\sqrt{121}\)
\(=\pm11\)
\(\sqrt{1^3}+2^3\)
\(=\sqrt{1}+8\)
\(=1+8\)
\(=9\)
Xem thêm câu trả lời
Tìm giá trị các biểu thức sau bằng cách biến đổi, rút gọn thích hợp:
a) \(\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{196}{9}}\) b) \(\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}\)
c) \(\frac{\sqrt{640}.\sqrt{34,3}}{\sqrt{567}}\) d) \(\sqrt{21,6}.\sqrt{810}.\sqrt{11^2-5^2}\)
a)frac{3}{7}+left(-frac{5}{2}right)+left(-frac{3}{5}right)b)frac{4}{5}-left(-frac{2}{7}right)-frac{7}{10}c)3,5-left(-frac{2}{7}right)d)sqrt{left(-7right)^2}+sqrt{frac{25}{16}}-frac{3}{2}e)sqrt{0,36}.sqrt{frac{25}{16}}+frac{1}{4}f)frac{1}{2}.sqrt{100}-sqrt{frac{1}{16}}+left(frac{1}{3}right)^0g)sqrt{frac{4}{81}}:sqrt{frac{25}{81}}-1frac{2}{5}i)frac{21^9.2^{10}}{14^9.3^8}k)frac{10^{11}.21^{12}}{15^{10}.14^{11}}l)0,5.sqrt{100}-sqrt{frac{1}{4}}
Đọc tiếp
a)
\(\frac{3}{7}+\left(-\frac{5}{2}\right)+\left(-\frac{3}{5}\right)\)
b)
\(\frac{4}{5}-\left(-\frac{2}{7}\right)-\frac{7}{10}\)
c)
\(3,5-\left(-\frac{2}{7}\right)\)
d)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\)
e)
\(\sqrt{0,36}.\sqrt{\frac{25}{16}}+\frac{1}{4}\)
f)
\(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)
g)
\(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac{2}{5}\)
i)
\(\frac{21^9.2^{10}}{14^9.3^8}\)
k)
\(\frac{10^{11}.21^{12}}{15^{10}.14^{11}}\)
l)
\(0,5.\sqrt{100}-\sqrt{\frac{1}{4}}\)
a, \(-\frac{187}{70}\)
b,\(\frac{27}{70}\)
c,\(\frac{53}{14}\)
d,\(\frac{27}{4}\)
e,1
f,\(\frac{23}{4}\)
g,-1
i,6
k,315
l,\(\frac{9}{2}\)
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a) sqrt{9}+sqrt{4} b) sqrt{0,25}-sqrt{0,01} c) sqrt{frac{16}{25}}-sqrt{frac{1}{81}} d) 2-sqrt{0,36}2. a) sqrt{64}-sqrt{16}+sqrt{left(-3^2right)} b) sqrt{121}+sqrt{left(-5right)^2}-sqrt{9}c) sqrt{frac{9}{4}}-sqrt{frac{16}{36}}-sqrt{49} d) sqrt{left(-4right)^2}+sqrt{left(-5right)^2}-sqrt{left(-6right)^2}
Đọc tiếp
a) \(\sqrt{9}+\sqrt{4}\) b) \(\sqrt{0,25}-\sqrt{0,01}\) c) \(\sqrt{\frac{16}{25}}-\sqrt{\frac{1}{81}}\) d) \(2-\sqrt{0,36}\)
2. a) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3^2\right)}\) b) \(\sqrt{121}+\sqrt{\left(-5\right)^2}-\sqrt{9}\)
c) \(\sqrt{\frac{9}{4}}-\sqrt{\frac{16}{36}}-\sqrt{49}\) d) \(\sqrt{\left(-4\right)^2}+\sqrt{\left(-5\right)^2}-\sqrt{\left(-6\right)^2}\)
1. a) 3+2=5
b) 0,5-0,1=0,4
c) 4/5-1/9=31/45
d) 2-0,6=1,4
2. a) 8-4+3=7
b) 11+5-3=13
c) 3/2-4/6-7-37/6
d) 4+5-6=3
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TÍNH GIÁ TRỊ CÁC BIỂU THỨC SAU
A,\(\sqrt{0,09}-\sqrt{0,64}\)
B,\(0,1\times\sqrt{225}-\sqrt{\frac{1}{4}}\)
C,\(\sqrt{0,36}\times\sqrt{\frac{25}{16}+\frac{1}{4}}\)
D,\(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}-1\frac{2}{5}}\)
a) \(\sqrt{0,09}-\sqrt{0,64}=\frac{-1}{2}=-0,5\)
b) \(0,1\cdot\sqrt{225}-\sqrt{\frac{1}{4}}=0,1\cdot15-\frac{1}{2}=1\)
c) \(\sqrt{0,36}\cdot\sqrt{\frac{25}{16}+\frac{1}{4}}=\frac{3\sqrt{29}}{20}\)
d) đề baì có sai ko ban?
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