26 + 10 + 2019 =?
Bài 1. Tính nhanh các tổng sau
a)
( -26) +13+ 10+ 26
b)
17+ 33+ ( -27)+ ( -33)
c)
( -12) +( -250)+ (-8) +250
d)
( -19)+ ( -11) +31 +( -1)
e)
(2019- 96)- 2019
a)( -26) +13+ 10+ 26
=(-26+26)+(13+10)
=0+23
=23
b)17+ 33+ ( -27)+ ( -33)
=[33+(-33)]+[17+(-27)]
=0+(-10)
=-10
c)( -12) +( -250)+ (-8) +250
=[-12+(-8)]+[-250+250]
=-20+0
=-20
d)( -19)+ ( -11) +31 +( -1)
=[-19+(-1)]+[-11+31]
=-20+20
=0
e)(2019- 96)- 2019
=2019-96-2019
=(2019-2019)-96
=0-96
=-96
Bài 1. Tính nhanh các tổng sau
a) (-26) +13 + 10+ 26
= [(-26) + 26] + (13 + 10)
= 0 + 23
= 23
b) 17 + 33 + (-27) + (-33)
= [17 + (-27)] + [33 + (-33)]
= -10 + 0
= -10
c) (-12) + (-250) + (-8) + 250
= [(-12) + (-8)] + [(-250) + 250]
= -20 + 0
= -20
d) (-19) + (-11) + 31 +(-1)
= [(-19) + (-11)] + [31 +(-1)]
= -30 + 30
= 0
e) (2019 - 96) - 2019
= 2019 - 96 - 2019
= (2019 - 2019) - 96
=0 - 96
#học tốt
&YOUTUBER&
a)(-26)+13+10+26
=[(-26)+26]+13+10
=0+13+10
=23
b)17+33+(-27)+(-33)
=[17+(-27)]+[33+(-33)]
=-10+0
=-10
c) (-12)+(-250)+(-8)+250
=(-12)+(-8)+[250+(-250)]
=(-12)+(-8)+0
=-20
d-19+11+31+-1
=(-19+-11)+(31+-1)
=-30+30
=0
e)(2019-96)-2019
=2019-96-2019
=2019-2019-96
=0-96
=-96
So sánh (26^2018+3^2018)^2019 và (26^2019+3^2019)2018
Giải nhanh mình tick cho nha
So sánh :\(\left(26^{2018}+3^{2018}\right)^{2019}\)và \(\left(26^{2019}+3^{2019}\right)^{2018}\)
So sánh : \(\left(26^{2018}+3^{2018}\right)^{2019}\) và \(\left(26^{2019}+3^{2019}\right)^{2018}\)
\(A=\left(26^{2018}+3^{2018}\right)^{2019}\)
\(B=\left(26^{2019}+3^{2019}\right)^{2018}\)
\(B=\left(26^{2018}.26+3.3^{2018}\right)^{2018}< \left(26^{2018}.26+3^{2018}.26\right)^{2018}\)
\(B< \left(26^{2018}+3^{2018}\right)^{2018}.26^{2018}< \left(26^{2018}+3^{2018}\right)^{2018}.\left(26^{2018}+3^{2018}\right)\)
\(\Rightarrow B< \left(26^{2018}+3^{2018}\right)^{2019}\Rightarrow B< A\)
so sanh \(\left(26^{2018}+3^{2018}\right)^{2019}\)
và \(\left(26^{2019}+3^{2019}\right)^{2018}\)
Ta có: \(\left(26^{2018}+3^{2018}\right)^{2019}=26^{2018\cdot2019}+3^{2018\cdot2019}\left(1\right)\)
\(\left(26^{2019}+3^{2019}\right)^{2018}=26^{2019\cdot2018}+3^{2019\cdot2018}\left(2\right)\)
Từ (1) và (2) \(\Rightarrow\left(26^{2018}+3^{2018}\right)^{2019}=\left(26^{2019}+3^{2019}\right)^{2018}\)
( 262018 + 32018 )2019 và ( 262019 + 32019 )2018
mình ấn thiếu đề bài nha đề bài là : so sánh 2 số sau . giải giúp mình với
1. So sánh: \(\left(26^{2018}+3^{2018}\right)^{2019}\)và \(\left(26^{2019}+3^{2019}\right)^{2018}\)
2. Tìm hai số \(a,b\inℕ^∗\)sao cho: \(a+2⋮b;b+3⋮a\)
So sánh (262018+32018)2019 và (262019+32019)2018
+
1)2*17*9+18*540+29*18
2)5*{26-[3*(5+2*5)+15]/15}
3)(2018*2019+2019*2020)*(45*120-15*360)*(1+5+9+13+17+...+2015+2019)
1) 2*17*9+18*540+29*18
= 18*17+18*540+29*18
= 18*(17+540+29)
= 18*586
= 10548
2) 5*{26-[3*(5+2*5)+15]/15}
= 5*{26-[3*(5+10)+15]/15}
= 5*{26-[3*15+15]/15}
= 5*{26-[45+15]/15}
= 5*{26-60/15}
= 5*{26-4}
=5*22
=110
3) (2018*2019+2019*2020)*(45*120-15*360)*(1+5+9+13+17+...+2015+2019)
= (2018*2019+2019*2020)*(15*3*120-15*120*3)*(1+5+9+13+17+...+2015+2019)
= (2018*2019+2019*2020)*0*(1+5+9+13+17+...+2015+2019)
= 0