Trả lời:

\(2018\times\left(\frac{1212}{1212}\div\frac{2424}{2424}\right)\)

\(=2018\times\left(1\div1\right)\)

\(=2018\times1\)

\(=2018\)

Tính nhanh

\(2018\times\left\{\frac{1212}{1212}\div\frac{2424}{2424}\right\}\)

\(=2018\times1\)

\(=2018\)

2018×(1212/1212×2424/2424)

2018×1

2018

\(\frac{121212}{141414}\times\frac{1313}{1212}\times\frac{2424}{2424}\)

\(=\frac{6}{7}\times\frac{13}{12}\times1\)

\(=\frac{13}{14}\)

~ Hok tốt ~

kết quả là ; 1313/141414

sau nhắc mik

=12. 10101/ 14.10101 .   13.101/12.101.   1

rút gọn ta được: 13/14

hok tốt

kt

=2018

Chi tiết

2018X(1/2+1212/2424)

Rút gon 1212/2424 còn 1/2

1/2+1/2=1

Vậy 2018x1=2018

\(=2018\) x \(\left(\dfrac{1}{2}+\dfrac{1}{2}\right)\)

\(=2018\) x \(1=2018\)

= 2018

a, \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) : 7 + \(\dfrac{6}{5}\)

= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{1}{7}\) + \(\dfrac{6}{5}\)

= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{6}{7}\) + \(\dfrac{1}{7}\)) + \(\dfrac{6}{5}\)

= \(\dfrac{3}{5}\) + \(\dfrac{6}{5}\)

= \(\dfrac{9}{5}\) 

b, 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1212}{2424}\))

= 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\))

= 2018 \(\times\)1

= 2018

a) 3/5 x 6/7 + 3/5 x 1/7 + 6/5

3/5 x ( 6/7 + 1/7 ) + 6/5

3/5 x 7/7 + 6/5 

3/5 x 1 + 6/5

3/5 + 6/5 

9/5

b) 2018 x ( 1/2 + 1212/ 2424 )

2018 x ( 1/2 + 12/24 )

2018 x ( 1/2 + 1/2 )

2018 x 2/2

2018 x 1

2018

Học tốt

Ta có:

  \(\frac{1212}{2424}=\frac{1}{2}\)

\(\Rightarrow2018.\left(\frac{1}{2}+\frac{1}{2}\right)=2018.1=2018\)

chia 101/101 để ra được 1/2

\(2018.\frac{1212}{2424}=2018.\frac{1212:1212}{2424:1212}=2018.\frac{1}{2}=1009\)

~Study well~

#ARMY_BLINK#

Trả lời:

2018 * ( 1212/2424 )

= 2018 * 1/2

= 1009

~~GOD~~

\(2018x\frac{1212}{2424}=2018x\frac{1212:1212}{2424:2424}=2018x\frac{1}{2}=1009\)

MAGCIEPCNIL

HÃY LUÔN ;-)

Toan lop 5 ha ma

rút gọn

\(\frac{1010+1111+1212+1313+1414+1515+1616+1717}{2020+2121+2222+2323+2424+2525+2626+2727}\)

\(=\frac{101.10+101.11+...+101.17}{101.20+101.21+...+101.27}\)

\(=\frac{101.\left(10+11+...+17\right)}{101.\left(20+21+...+27\right)}\)

\(=\frac{108}{188}\)

\(=\frac{27}{47}\)

\(2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{4}{96}\right)\cdot5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{1}{24}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{20}{120}+\frac{16}{120}+\frac{9}{120}+\frac{5}{120}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{5}{12}:5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{1}{12}.y>\frac{5}{6}\)

Đặt :\(\frac{1}{12}.y=2\Rightarrow y=2:\frac{1}{12}=24\)

\(\frac{1}{12}.y=\frac{5}{6}\Rightarrow y=\frac{5}{6}:\frac{1}{12}=10\)

\(\Rightarrow24>y>10\)

\(\Rightarrow y\in\left\{11;12;...;23\right\}\)

ko biết

I am sorry

Kb nhé