\(\frac{2006x125+1000}{126x2006-1006}=\frac{2006x125+1000}{125x2006-2006-1006}=\frac{2006x125+1000}{125x2006+1000}=1\)

=\(\frac{2006x125+1000}{125x2006+2006-1006}\)

=\(\frac{2006x125+1000}{125x2006+1000}\)

=1

\(\frac{2006\cdot125+1000}{126\cdot2006-1006}=\frac{2006\cdot\left(126-1\right)+1000}{126\cdot2006-1006}\)

\(=\frac{2006\cdot126-2006+1000}{126\cdot2006-1006}\)

\(=\frac{2006\cdot126-1006}{126\cdot2006-1006}\)

\(=1\)

\(\frac{2006x125+1000}{126x2006-1006}\)

\(=\frac{2006x125+1000}{\left(125+1\right)x2006-1006}\)

\(=\frac{2006x125+1000}{125x2006+1x2006-1006}\)

\(=\frac{2006x125+1000}{125x2006+2006-1006}\)

\(=\frac{2006x125+1000}{125x2006+1000}\)

\(=1\)

a:2006x125+1000=250750+1000

                             =251750

b:126x2006-1006=252756-1006

                            =251750

Ta có:

\(\frac{2006\times125-1000}{126\times2006-1000}\)

Ta thấy:

Cả tử và mẫu đều có - 1000 và 2006 

Nên ta đơn giản đi bớt và phân số chỉ còn lại \(\frac{125}{126}\)

a. 

(1 + 3 + 5 + ... + 2007 + 2009 + 2011) x (125125 x 127 - 127127 x 125)

= (1 + 3 + 5 + ... + 2007 + 2009 + 2011) x 0

= 0

b.

\(\frac{2006\times125+1000}{126\times2006-1006}=\frac{2006\times125+1000}{125\times2006+1\times2006-1006}=\frac{2006\times125+1000}{125\times2006+1000}=1\)

a, 

( 1+3+5+7+…+2003+2005) x (125 125 x 127 – 127 127 x 125)

= ( 1+3+5+7+…+2003+2005) x (125 x 1001 x 127 – 127 x 1001x 125)

=  ( 1+3+5+7+…+2003+2005) x                   0  =    0

A = 0

B= 2006

C= 1993

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