\(720\div\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=^{ }2^3.5\)
720 : [41-(2x-5)] = 2^3 . 5
720 : [41-(2x-5) ] =40
=> 41-(2x-5) =18
=> 2x-5 =23
=> 2x =28
=> x=14
720: ( 41-(2x-5) ) = 23 . 5
<=> 720 : ( 41 - ( 2x-5 ) ) = 8.5
<=> 720 : ( 41 - (2x -5 ) ) = 40
<=> ( 41 - ( 2x - 5) ) = 720 : 40 = 18
<=> 2x - 5 = 41 -18 = 23
<=> 2x = 23+5 =28
=> x = 28 : 2 =14
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-2x+5\right]=8.5=40\)
\(720:41-2x+5=40\)
\(41-2x+5=18\)
\(2x+5=23\)
\(2x=18\)
\(x=9\)
Tìm x:\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:40\)
\(41- \left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28:2\)
\(\Rightarrow x=14\)
\(720\div\left[41-\left(2x-5\right)\right]=2^3\times5\)
\(720:\left[41-\left(2x-5\right)\right]=2^3\times5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(\left[41-\left(2x-5\right)\right]=720:40\)
\(2x=23+5\)
\(x=28:2\)
\(x=14\)
Tìm x biết:
\(25+3\left(x-8\right)=106\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
Cách làm
Bài 1: 25 + 3(x - 8) = 106
3(x - 8) = 106 - 25
3(x - 8) = 81
(x - 8) = 81 : 3
(x - 8) = 27
x = 27 + 8
x = 25
Bài 2: 720 : [41 - (2x - 5)] = 23 . 5
720 : [41 - (2x - 5)] = 8 . 5
720 : [41 - (2x - 5)] = 40
[41 - (2x - 5)] = 720 : 40
[41 - (2x - 5)] = 18
(2x - 5) = 41 - 18
(2x - 5) = 23
2x = 23 + 5
2x = 28
x = 28 : 2
x = 14
\(720:\left[41-\left(2.x-5\right)\right]=2^3.5\)
720:(41-(2x-5)) =2\(^3\)x5
720:(41-(2x-5)) =40
41-(2x-5) =720:40=18
2x-5 =41-18=23
2x =23+5=28
=> x =28:2=14
x=14
k nha.đúng 100% đó
bạn ơi bạn có thể giải cụ thể cho mình được ko
Tìm x , biết
a, \(3^2\left(x+14\right)-5^2=5.4\)
b, \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
Ai nhanh minh tick
a, \(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x+14\right)-25=20\)
\(\Rightarrow9x+126=20+25\)
\(\Rightarrow9x+126=45\)
\(\Rightarrow9x=45-126\)
\(\Rightarrow9x=-81\Rightarrow x=-9\)
Vậy x = 9
a,\(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x-14\right)-25=20\)
\(\Rightarrow9\left(x-14\right)=20+25=45\)
\(\Rightarrow x-14=45:9=5\)
\(\Rightarrow x=5+14\)
\(\Rightarrow x=19\)
Vậy x = 19
b,\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-2x+5\right]=40\)
\(\Rightarrow41+5-2x=720:40\)
\(\Rightarrow46-2x=18\)
\(\Rightarrow2x=46-18=28\)
\(\Rightarrow x=28:2\)
\(\Rightarrow x=14\)
Vậy x = 14
~Study well~
b, \(720\div\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Rightarrow720\div\left[41-\left(2x-5\right)\right]=8.5\)
\(\Rightarrow720\div\left[41-\left(2x-5\right)\right]=40\)
\(\Rightarrow41-\left(2x-5\right)=\frac{720}{40}\)
\(\Rightarrow41-\left(2x-5\right)=18\)
\(\Rightarrow2x-5=41-18\)
\(\Rightarrow2x-5=23\)
\(\Rightarrow2x=23+5\)
\(\Rightarrow2x=28\Rightarrow x=\frac{28}{2}=14\)
Vậy x = 14
Help me !
Tìm x thuộc N , biết :
\(720:[41-\left(2x-5\right)]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x-5\right)=720:40\)
\(\Leftrightarrow41-\left(2x-5\right)=18\)
\(\Leftrightarrow2x-5=41-18\)
\(\Leftrightarrow2x-5=23\)
\(\Leftrightarrow2x=28\)
\(\Leftrightarrow x=14\)
Ta có :\(720:\left[41-\left(2X-5\right)\right]=2^3\cdot5\)
\(\Leftrightarrow41-\left(2X-5\right)=18\)
\(\Leftrightarrow2X-5=23\)
\(\Leftrightarrow2X=28\)
\(\Leftrightarrow X=14\)(TMĐK)
Vậy X= 14 là giá trụ cần tìm.
\((x-1)^3=125\)
\(2^{x+2}-2^x=96\)
\(\left(2x+1\right)^3=343\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)\(16^x< 128^4\)
[X-1]^3=125
[x-1]^3=5^3
x-1=5
x=5+1
x=6
Vậy x=6
a) \(\left(x-1\right)^3=125\)
\(\Rightarrow x-1=5\)
\(\Rightarrow x=6\)
b) \(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.2^2-2^x=96\)
\(\Rightarrow2^x.3=96\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
c) \(\left(2x+1\right)^3=343=7^3\)
\(\Rightarrow2x+1=7\)
\(\Rightarrow x=3\)
\(\left(x-1\right)^3=125\)\(\Rightarrow\left(x-1\right)^3=5^3\Rightarrow x-1=5\)
\(\Rightarrow x=5+1=6\)
\(\left(2x+1\right)^3=343\Rightarrow\left(2x+1\right)^3=7^3\Rightarrow2x+1=7\)
\(2x=7-1=6\Rightarrow x=6:2=3\)
\(720:\left[41-\left(2x-5\right)\right]=120\)
\(720:\left[41-\left(2x-5\right)\right]=120\)
\(\Leftrightarrow41-\left(2x-5\right)=6\)
\(\Leftrightarrow2x-5=35\)
\(\Leftrightarrow2x=40\)
\(\Leftrightarrow x=20\)
hok tốt!
720 : [ 41 - ( 2x - 5 ) ] = 120
41 - ( 2x - 5 ) ] = 720 : 120 = 6
2x - 5 = 41 - 6 = 35
2x = 35 + 5 = 40
x = 40 : 2 = 20
Học tốt
720 : [ 41 - ( 2x - 5 ) ] = 120
=> 41 - ( 2x - 5 ) = 720 : 120
=> 41 - ( 2x - 5 ) = 6
=> 2x - 5 = 41 - 6
=> 2x - 5 = 35
=> 2x = 35 + 5
=> 2x = 40
=> x = 40 : 2
=> x = 20
Vậy x = 20