RÚT GỌN
a)\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
b)\(\frac{2929-101}{2.1919+404}\)
Rút gọn:
a, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
b, \(\frac{2929-101}{2.1919+404}\)
Cho 3 phân số:
\(\frac{-5^2-5.3^2}{5^3+5^2.3^2};\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}};\frac{2929-101}{2.1919+404}\)
Rút gọn rồi quy đòng 3 ps trên
Cho 3 phân số :\(\frac{-5^2-5.3^2}{5^3+5^2.3^2}\);\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\);\(\frac{2929-101}{2.1919+404}\)rút gọn rồi qui đồng các phân số đó.
QUY ĐỒNG MẤU SỐ CÁC PHÂN SỐ Sau:a>
\(\frac{4.5+4.11}{8.7+4.3}\);\(\frac{15.8+10.7}{5.6+20.3}\)và \(\frac{2^4.5^2.7}{2^3.5.7^2.11}\)
b> \(\frac{-5^2-5.3^2}{5^3+5^2.3^2}\);\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)và\(\frac{2929-101}{2.1919+404}\)
Nhanh nha, ai trả lời vừa đúng, nhanh, dễ hiểu mk thisck cho
bài 1
A=\(\frac{-5^2-5.3^2}{5^3+5^2.3^2}\)
B=\(\frac{7^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
C=\(\frac{2929-101}{2.1999-404}\)
giúp mik với mik sẽ tích và kb cho
rút gọn phân số
a)\(\dfrac{2727-101}{3.303+404}\) b)\(\dfrac{8.9-4.15}{12.7-180}\) c)\(\dfrac{-19}{3^2.7.11}\) d)\(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
a) \(\dfrac{2727-101}{3.303+404}=\dfrac{2626}{909+404}=\dfrac{2626}{1313}=2\)
b) \(\dfrac{8.9-4.15}{12.7-180}=\dfrac{72-60}{84-180}=\dfrac{12}{-96}=\dfrac{-1}{8}\)
c) \(\dfrac{-19}{3^2.7.11}=\dfrac{-19}{9.7.11}=\dfrac{-19}{63.11}=\dfrac{-19}{693}\)
d) \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{2^{12}.3^{10}+120.6^9}{2^{12}.3^{12}-6^{11}}=\dfrac{2^2.6^{10}+20.6.6^9}{6^{12}-6^{11}}=\dfrac{4.6^{10}+20.6^{10}}{6^{11}\left(6-1\right)}=\dfrac{\left(4+20\right).6^{10}}{5.6^{11}}=\dfrac{24}{30}=\dfrac{4}{5}\)
Rút gọn:
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{15}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}\left(3^5+5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)
cho mk sửa lại xíu:
\(\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}=\frac{2.6}{3.5}=\frac{12}{15}=\frac{4}{5}\)
mk sai xíu. hihi, học tốt nhé !
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(N=\frac{4^6.9^5+6^9.120}{4^8.9^6-6^9.6^2}\)
\(N=\frac{36^5.4+36^4.6.6.20}{36^5.576-36^4.6.6.36}\)
\(N=\frac{36^5.4+36^5.20}{36^5.576-36^5.36}\)
\(N=\frac{36^5.\left(4+20\right)}{36^5.\left(576-36\right)}\)
\(N=\frac{36^5.24}{36^5.540}\)
\(N=\frac{24}{540}\)
\(N=\frac{2}{45}\)
Vậy \(N=\frac{2}{45}\)
Rút gọn biểu thức: \(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
Rút gọn :\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(6-1\right)}=\frac{2.6}{3.5}=\frac{4}{5}\)
\(\frac{\left(2^2\right)^6.\left(3^2\right)^5+2^9.3^9.120}{\left(2^3\right)^4.3^{12}-2^{11}.3^{11}}\)=\(\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}\)=\(\frac{120}{3^2-2^3.3^3}\)=\(\frac{120}{9-8.27}\)=\(\frac{120}{-207}\)=\(\frac{-40}{69}\)
tk cho mk nhe
Ta có:
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.120}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
\(=\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(6-1\right)}\)
\(=\frac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}\)
\(=\frac{2.1.6}{1.3.5}\)
\(=\frac{12}{15}\)
\(=\frac{4}{5}\)
Đúng 100% nhé !