Find the value of such that
\(\frac{x-2}{\left(a+3\right)\left(5-a\right)}=\frac{1}{2\left(a+3\right)}+\frac{1}{2\left(5-a\right)}\) (\(\left(a\ne-3;a\ne5\right)\)
Find the value of x such that: \(\frac{3\left(x+2\right)}{2x+3}=\frac{7}{8},\left(x\ne-\frac{3}{2}\right)\) . Answer: x = ...
( write your answer by decimal in simplest form )
Find the value of x such that
\(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
(a\(\ne\)-7;-1 )
Answer: x=
given 1<x<3., Find the value of \(A=\frac{\left|x-3\right|}{x-3}-\frac{\left|x-1\right|}{1-x} +\left|x-1\right|+\left|3-x\right|\)
Answer:A=...........
Lời giải:
Vì \(1< x< 3\Rightarrow \left\{\begin{matrix}
|x-3|=|3-x|=3-x\\
|x-1|=x-1\end{matrix}\right.\). Khi đó:
\(A=\frac{|x-3|}{x-3}-\frac{|x-1|}{1-x}+|x-1|+|3-x|\)
\(=\frac{3-x}{x-3}-\frac{x-1}{1-x}+x-1+3-x\)
\(=-1-(-1)+2=2\)
Vậy giá trị của $A$ là $2$
Find the value of x such that :
\(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
\(\left(a\ne-7;a\ne-1\right)\)
Answer: x =
( trả lời chứ đừng có mà 8 ở đây nhá mấy má ! )
\(\Rightarrow x+7=a+7-\left(a+1\right)\)
\(\Rightarrow x+7=a+7-a-1\)
\(\Rightarrow x+7=6\)
\(\Rightarrow x=-1\)
let P(x) be a polynomial of degree 3 and x1, x2, x3 are the solutions of P(x)=0. let \(\frac{P\left(\frac{1}{3}\right)-P\left(\frac{-1}{3}\right)}{P\left(0\right)}=8,\frac{P\left(\frac{1}{4}\right)-P\left(\frac{-1}{4}\right)}{P\left(0\right)}=9\)and x1+x2+x3 = 35. find the value of \(\frac{x2+x3}{x1}+\frac{x1+x3}{x2}+\frac{x1+x2}{x3}\)
find the value of x such that (Tìm x biết ) : \(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
( a khác -1; -7 )
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{a+7}{\left(a+1\right)\left(a+7\right)}-\frac{a+1}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)
=>x+7=6
=>x=6-7
=>x=-1
vậy x=-1
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{\left(a+7\right)-\left(a+1\right)}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)=> x + 7 = 6 => x = -1
Tìm x:\(\frac{x-2}{\left(a+3\right)\left(5-a\right)}=\frac{1}{2\left(a+3\right)}+\frac{1}{2\left(5-a\right)}\)\(a\ne-3,a\ne5\)
Tìm x biết:
a,\(\frac{\left|x\right|}{\left(a+3\right)\cdot\left(2-a\right)}=\frac{1}{a+3}+\frac{1}{2-a}\left(a\ne2;a\ne-3\right)\)
b,\(\frac{\left|x\right|-3}{\left(a-1\right)\cdot\left(a-2\right)}=\frac{1}{a-1}-\frac{1}{a-2}\left(a\ne1;a\ne2\right)\)
1.If 2x-y=5 then the value of M=\(\left(x+2y-3\right)^2-\left(6x+2y\right)\left(x+2y-3\right)+9x^2+6xy\)
\(+y^2\)
2.The free coefficient in the following poly nomaial: \(\left(2x-2\right)\left(x+1\right)\left(7-x^2\right)is:\)
3.The greatest integer number x such that \(\frac{2x-1}{x-3}-1< 0\) is:
4.How many of the integer n such that satisfy the inequality \(\left(n-3\right)^2-\left(n-4\right)\left(n+4\right)< =43\) are less than 3?
5.The opposite fraction of \(\frac{x-2}{7-x}\) is: