\(\frac{18,7}{x}=3,11\left(6\right)\)

\(\Rightarrow\frac{18,7}{x}=\frac{187}{60}\)

\(\Rightarrow x=\frac{18,7\cdot60}{187}=\frac{187\cdot6}{187}=6\)

18,7:x=3,11(6) mà 3,11(6)=\(\frac{187}{60}\)

nên 18,7:x=\(\frac{187}{60}\)Suy ra x=\(\frac{187}{10}\):\(\frac{187}{60}\)=6

xin lỗi chị nha! em mới học lớp 6 thôi. nên em chỉ cho chị đáp số thôi nhé!x=227

0,1(6):x=0,(33)

=>[0,1+0,0(6)]:x=33/99=1/3

=>(1/10+1/15):1/3=x

=>1/6.3=x

=>x=3/6=1/2=0,5

nhớ tick nhé

Ta có: \(0,1\left(6\right)=0,1+0,0\left(6\right)=0,1+\frac{1}{10}.0,\left(6\right)=0,1+\frac{1}{10}.6.0,\left(1\right)=0,1+\frac{1}{10}.6.\frac{1}{9}=\frac{1}{6}\)\(0,\left(33\right)=33.0,\left(01\right)=33.\frac{1}{99}=\frac{1}{3}\)

\(\Rightarrow\frac{1}{6}:x=\frac{1}{3}\Rightarrow x=\frac{1}{6}:\frac{1}{3}=\frac{1}{2}\)

\(1,\Leftrightarrow x^2-10x+25=0\Leftrightarrow\left(x-5\right)^2=0\Leftrightarrow x=5\left(B\right)\\ 2,Giống.1\\ 3,=5x^2\left(B\right)\\ 4,x^3=x\Leftrightarrow x^3-x=0\\ \Leftrightarrow x\left(x^2-1\right)=0\\ \Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\\ \Leftrightarrow A\)