Biet \(\frac{x}{y}=\frac{4}{3}\). Khi do \(\frac{x-y}{x+y}=\)
Biet \(\frac{x}{y}=\frac{4}{3}\). Khi do \(\frac{x-y}{x+y}=\)?
\(\frac{x-y}{x+y}=\frac{4-3}{4+3}=\frac{1}{7}\)
\(\frac{x}{y}=\frac{4}{3}=>\frac{x}{4}=\frac{y}{3}=\frac{x-y}{4-3}=\frac{x+y}{4+3}=\frac{x-y}{1}=\frac{x+y}{7}\)
=>\(\frac{x-y}{1}=\frac{x+y}{7}=>\frac{x-y}{x+y}=\frac{1}{7}\)
\(\frac{x}{y}=\frac{4}{3}\Leftrightarrow\frac{x}{4}=\frac{y}{3}=\frac{x-y}{4-3}=\frac{x+y}{4+3}\Leftrightarrow\frac{x-y}{x+y}=\frac{4-3}{4+3}=\frac{1}{7}\)
Cho ba so x, y, z biet \(x-y+z=3\)va \(\frac{x}{2}=\frac{y}{1}=\frac{z}{4}\). Khi do y= ?
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{2}=\frac{y}{1}=\frac{z}{4}=\frac{x-y+z}{2-1+4}=\frac{3}{5}\)
Vậy y = 3/5
cho 2 so x,y >0 biet \(\frac{x}{2}=\frac{y}{4}\)va \(^{x^4y^2=16}\).khi do y la
tim x,y,z biet \(\frac{3.X-5.Y}{2}=\frac{5.Y-3.Z}{3}=\frac{3.B}{4};X+Y+Z+17\)=17
Tìm x,y,z biet \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)và x - y + z = 10
x/2=y/3=z/4=(x-y+z)/(2-3+4)=10/3
x/2=10/3 => x=10/3.2=20/3
y/3=10/3=> y=10/3.3=10
z/4=10/3=> z=10/3.4=40/3
Tim cac so nguyen x,y biet
a)\(\frac{x-3}{y-2}\)=\(\frac{3}{2}\)va x - y = 4
b)\(\frac{x+3}{y-1}\)=\(\frac{3}{4}\)va x + y = 5
a, \(\frac{x-3}{y-2}=\frac{3}{2}\)và \(x-y=4\)
Theo bài ra ta có :
\(\frac{x-3}{y-2}=\frac{3}{2}\Leftrightarrow2x-6=3y-6\Leftrightarrow2x=3y\Leftrightarrow\frac{x}{3}=\frac{y}{2}\)
Áps dụng tính chất dãy tỉ số bằng nhau ta đc :
\(\frac{x}{3}=\frac{y}{2}=\frac{x-y}{3-2}=\frac{4}{1}=4\)
\(\frac{x}{3}=4\Leftrightarrow x=12\)
\(\frac{y}{2}=4\Leftrightarrow y=8\)
Tương tự với b thôi bn.
cho x,y,z thoa man \(\frac{x}{2}=\frac{2y}{3}=\frac{3z}{4}\) va x-y=15
Khi do x-y-z=.......................?
\(\frac{x}{12}=\frac{y}{9}=\frac{z}{8}\) => \(\frac{x-y}{12-9}=\frac{15}{3}=5\)=> x = 60 ; y= 45 ; z=40 => x-y-z = 60-45-40 =-25
\(\frac{x}{2}=\frac{2y}{3}=\frac{3z}{4}\Leftrightarrow\frac{x}{2}=\frac{y}{\frac{3}{2}}=\frac{z}{\frac{4}{3}}\)
Áp dụng t/c dãy tỉ số=nhau:
\(\frac{x}{2}=\frac{y}{\frac{3}{2}}=\frac{z}{\frac{4}{3}}=\frac{x-y}{2-\frac{3}{2}}=\frac{15}{\frac{1}{2}}=30\)
=>x/2=30=>x=60
y/3/2=30=>y=30.3/2=45
z/4/3=30=>z=30.4/3=40
Vậy x-y-z=60-45-40=-25
tim cac cap so x,y biet:
\(\frac{x}{2}=\frac{y}{5}\)va x.y =90
\(\frac{3x-y}{x+y}=\frac{3}{4}\)tim\(\frac{x}{y}\)
a) x = 6 ; y = 15.
x = -6 ; y = -15.
b) x = 2 ; y = 2.
x = -2 ; y = -2.
Tim x, y biet
\(x-\frac{3}{5}=\frac{3}{5}\)
\(|x|-\frac{4}{5}=\frac{2}{5}\)
\(\frac{x}{-5}=\frac{24}{15}\)
\(\frac{x}{4}=\frac{y}{5}vax-y=21\)
a)\(x-\frac{3}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{3}{5}+\frac{3}{5}=\frac{6}{5}\)
b)\(|x|-\frac{4}{5}=\frac{2}{3}\\ \Rightarrow|x|=\frac{2}{3}+\frac{4}{5}=\frac{22}{15}\\ \Rightarrow|x|=\frac{22}{15}\\ \Rightarrow x=\frac{22}{15}\)
c)\(\frac{x}{-5}=\frac{24}{15}\\ \Rightarrow x=\frac{-5\cdot24}{15}=-8\)
d)\(\frac{x}{4}=\frac{y}{5} và x-y=21\)
Theo tính chất của dãy tỉ số bằng nhau , ta có :
\(\frac{x}{4}=\frac{y}{5}=\frac{x-y}{4-5}=\frac{21}{-1}=-21\)
Do đó :
\(\frac{x}{4}=-21\Rightarrow x=-84\)
\(\frac{y}{5}=-21\Rightarrow y=-105\)
\(x-\frac{3}{5}=\frac{3}{5}\)
\(x=\frac{3}{5}+\frac{3}{5}\)
\(x=\frac{6}{5}\)
\(\left|x\right|-\frac{4}{5}=\frac{2}{5}\)
\(\left|x\right|=\frac{2}{5}+\frac{4}{5}\)
\(\left|x\right|=\frac{6}{5}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{6}{5}\\x=-\frac{6}{5}\end{cases}}\)
\(\frac{x}{-5}=\frac{24}{15}\)
\(\Rightarrow x.15=\left(-5\right).24\)
\(\Rightarrow x.15=-120\)
\(\Rightarrow x=-120:15\)
\(\Rightarrow x=-8\)
Trong lời giải có mấy dấu \(\\ \)e đừng ghi vào nhé . cái dấu đó giúp cj xuống hàng thôi