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Trần cẩm vân
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Đào Thị Huyền
9 tháng 5 2016 lúc 21:47

A=1/2+1/6+1/12+1/20+...+1/72+1/90

A=1/1x2+1/2x3+1/3x4+1/4x5+.....+1/8x9+1/9x10

A=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+....+1/8-1/9+1/9-1/10

A=1-1/10

A=9/10

k cho mik nha

ssjs9
9 tháng 5 2016 lúc 21:41

A=1/(1*2)+1/(2*3)+1/(3*4)+.....+1/(9*10)

=1/1-1/2+1/2-1/3+.......+1/9-1/10

=1/1-1/10=9/10

goku
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Ngô Thị Yến
5 tháng 10 2016 lúc 21:06

Ta có

  2+4-6-8+10+12-14-16+18+20-22-24+...-2008

=(2+4-6-8)+(10+12-14-16)+(18+20-22-24)+...+(2002+2004-2006-2008)

=(-8)+(-8)+(-8)+...+(-8)                        (251 số hạng (-8)  )

=(-8).251

=-2008

goku
6 tháng 10 2016 lúc 12:39

sao khong thấy

miss A
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Đỗ Phương Linh
10 tháng 8 2018 lúc 17:23

\(\frac{81}{10}\)

nguyen dinh chi kim
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Phương Linh
19 tháng 1 2016 lúc 18:53

A=-2008 tick cho tớ nhé nguyen dinh chi kim kết bạn rồi nhé 

Bùi Trung Kiên
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Nguyen Ha Phuong
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nguyen hoang le thi
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TFBoys_Châu Anh
1 tháng 5 2016 lúc 17:20

\(S1=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)

\(S1=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+\frac{1}{8\cdot9}+\frac{1}{9\cdot10}\)

\(S1=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(S1=1-\frac{1}{10}\)

\(S1=\frac{9}{10}\)

CHÚC BN HC GIỎI !!!!!!!!!! TỨ DIỆP THẢO

Nguyễn Hưng Phát
1 tháng 5 2016 lúc 17:15

S=\(\frac{1}{1.2}+\frac{1}{2.3}+...............+\frac{1}{9.10}\)

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...............+\frac{1}{9}-\frac{1}{10}\)

=\(1-\frac{1}{10}\)

=\(\frac{9}{10}\)

Nguyễn Kim Thành
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Nguyễn Kim Thành
4 tháng 12 2016 lúc 11:55

xin hãy trả lời

                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                                        
                                                                                                                                                                                            
Nguyễn Kim Thành
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titanic
4 tháng 12 2016 lúc 10:23

Ta có:\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+..+\frac{2}{210}=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+..+\frac{2}{14.15}\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+..+\frac{1}{14}-\frac{1}{15}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{15}\right)\)

\(=1-\frac{2}{15}=\frac{15-2}{15}=\frac{13}{15}\)

Nguyễn Kim Thành
4 tháng 12 2016 lúc 10:25

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