ta có :A=8 bé hơn hoặc =|X-1+X-3+X-5+X-7|=|4X-16|

=>X<(8+16)/4=6(1)

X>(-8+16)/4=2(2)TỪ 1 VÀ 2 =>2<x<6

=>x\(\in\)(3;4;5)

Khó mới cần các bạn giúp  

bai toan kho @gmail.com

|x|+1/5=2

=> |x|=2-1/5

=> |x|=9/5

=> x=±9/5

=>|x|=2-1/5

|x|=9/2

=>x=9/2 hoặc x=-9/2

 |x| + 1/5 = 2

|x|= 2 - 1/5

|x|= 10/5 - 1/5

|x|= 9/5

  Suy ra:

Trường hợp 1 : x= 9/5

Trường hợp 2 : x= -9/5

bằng 1 bạn nhé

Trả lời :

Bằng 1 Nhé ^^

Hok tốt

K cho mik đc ko? 

svbxcshbcvgachgdxdsdcsxzsxxhszlgufwshgfedef

uxckhxlkcxcxkcx,búlolasjaddcgusugycxjhsacjhhcskjcdsdcscfsdsshgucsjdhdwscfva

cau b ta co9;(x+x+.....+x)-(1+2+....+100)=4950

                   100x           -  5050              =4950

                               100x                        =4950+5050

                                       100x                   =10000

                                              x=10000 ;100

                                              x=100

Bài 1:

<=>7[3(-x)]-12(x-5)=-3(11x-20)

=>-3(11x-20)=5

=>-33x=-55

=>-11.3x=-11.5 (rút gọn -11)

=>3x=5

\(\Rightarrow x=\frac{5}{3}\)

Đã duyệt

bài 1:

<=>7[3(-x)]-12(x-5)=-3(11x-20)

=>-3(11x-20)=5

=>-33x=-55

=>-11.3x=-11.5 (rút gọn -11)

=>3x=5

=>x=\(\frac{5}{3}\)

bài 1:

<=>7[3(-x)]-12(x-5)=-3(11x-20)

=>-3(11x-20)=5

=>-33x=-55

=>-11.3x=-11.5 (rút gọn -11)

=>3x=5

=>x=\(\frac{5}{3}\)

đậu phộng thằng Phan Bá Lộc chép bài ông

[3x-1]⁵=[3x-1]⁸

=>[3x-1]⁸-[3x-1]⁵⁼⁰

   [3x-1]⁵.[[3x-1]³-1]=0

=>[3x-1]⁵ =0​ hoặc [3x-1]³-1=0

=>3x-1=0 hoặc3x-1 =1

=>x=1/3 hoac x=2/3

Vay....

=>

a) 2 hoặc -8

b)khó lắm

b) 2(x-5)-3(x-4)=-6+15.(-3)

2(x-5)-3(x-4)=-6+(-45)

2(x-5)-3(x-4)=-51ban tu lam not nha

=2.(x-5)-3.(x-4)=-6+(-45)

=2.(x-5)-3.(x-4)=-51

=2x- 10-3x-12=-51

=2x-10-3x=-39

=2x-3x-10=-39

=2x-3x=-29

x(2-3)=-29

x.(-1)=-29 

=>x=29

kick cho mình nhé 

A=\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2014}{2015}.\frac{2015}{2016}\)

A=\(\frac{1.2.3.4...2015}{2.3.4...2016}=\frac{1}{2016}\)

Hok tốt

A = \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2015}\right).\left(1-\frac{1}{2016}\right)\)

= \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2014}{2015}.\frac{2015}{2016}\)

= \(\frac{1}{2016}\)

Vậy ...

\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)......\left(1-\frac{1}{2015}\right)\left(1-\frac{1}{2016}\right)\)

\(\Rightarrow A=\frac{1.2.3.4....2015}{2.3.4....2016}\)

\(\Rightarrow A=\frac{1}{2016}\)

#hok tốt