Tìm số nguyên x, biết:
1+ \(\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}\)
Ai đúng mk k nha!!!
Những câu hỏi liên quan
Tìm x thuộc Z, biết: \(1+\frac{-1}{60}+\frac{19}{120}
tìm x thuộc z biết 1 +\(\frac{1}{60}\)+ \(\frac{19}{120}< \frac{x}{36}+\frac{-1}{60}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
Tim x biet
\(1+\frac{-1}{60}+\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
\(1+\frac{-1}{60}+\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
=> \(\frac{137}{120}< \frac{x}{36}< \frac{521}{360}\)
=> \(\frac{411}{360}< \frac{10x}{360}< \frac{521}{360}\)
=> 411 < 10x < 521
=> x \(\in\){ 42,43,44,...,52}
tìm \(x\in Z\)
\(1+\frac{-1}{60}+\frac{19}{120}<\frac{x}{36}+\frac{-1}{60}<\frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
Tìm x\(\in\) Z biết 1+\(\frac{-1}{60}\)+\(\frac{19}{120}\)<\(\frac{x}{36}\)+\(\frac{-1}{60}<\frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
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Tìm x
a) \(1+\frac{-1}{60}\)\(+\frac{19}{120}\)<\(\frac{x}{36}\)\(+\frac{-1}{60}\)<\(\frac{58}{90}\)\(+\frac{59}{72}\)\(+\frac{-1}{60}\)
tìm x, biết: 1+-1/60+19/120<x/36<58/90+59/72+-1/60
tìm x biết :
1+\(\dfrac{-1}{60}\)+\(\dfrac{19}{120}\)<\(\dfrac{x}{36}\)<\(\dfrac{58}{90}\)+\(\dfrac{59}{72}\)+\(\dfrac{-1}{60}\)
tìm x biết
1+ -1/60+19/120<x/36<58/90+59/72+ -1/60