Rút gọn:
\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{4}}\)
Những câu hỏi liên quan
Tính \(M=\frac{\frac{7}{2012}+\frac{7}{9}+\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
\(\frac{\frac{7}{2012}+\frac{7}{9}+\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}=\left(\frac{7}{2012}+\frac{7}{9}+\frac{1}{4}\right):\left(\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}\right)\)
\(=\frac{9337}{9054}:\frac{97}{18108}=\frac{9337}{9054}.\frac{18108}{97}=\frac{18674}{97}\)
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tính:
B=\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
Tính:
\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
bài 1 :a) Tính M:\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
b) So sánh A và B biết A =\(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2010}\);;; B =\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+....+\frac{1}{17}\)
tính M
M = \(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
so sánh A và B biết
A = \(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2010}\)
B = \(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{17}\)
\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\) các bạn giúp mình nhé mình đang cần gấp
\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{1}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
\(=\left(\frac{7}{2012}+\frac{7}{9}-1\right):\left(\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}\right)\)
\(=\frac{-3961}{18108}:\frac{979}{18108}=\frac{-3961}{18108}\cdot\frac{18108}{979}\)
\(=\frac{-3961}{979}\)
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Thực hiện phép tính( tính hợp lí nếu có thể )
\(M=\)\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
GIÚP MÌNH VỚI, MÌNH CẦN GẤP, MÌNH ĐỘI ƠN NHÌU
bài 1 So sánha)Afrac{3}{8^3}+frac{7}{8^4} ; Bfrac{7}{8^3}+frac{3}{8^4}b)Afrac{10^{1992}+1}{10^{1991}+1};Bfrac{10^{1993}+1}{10^{1992}+1}c)Afrac{10^7+5}{10^4-8};Bfrac{10^8+6}{10^8-7}d)Afrac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};Bfrac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}e)Afrac{2011}{2012}+frac{2012}{2013};Bfrac{2011+2012}{2012+2013}
Đọc tiếp
bài 1 So sánh
a)\(A=\frac{3}{8^3}+\frac{7}{8^4}\) ; \(B=\frac{7}{8^3}+\frac{3}{8^4}\)
b)\(A=\frac{10^{1992}+1}{10^{1991}+1};B=\frac{10^{1993}+1}{10^{1992}+1}\)
c)\(A=\frac{10^7+5}{10^4-8};B=\frac{10^8+6}{10^8-7}\)
d)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
e)\(A=\frac{2011}{2012}+\frac{2012}{2013};B=\frac{2011+2012}{2012+2013}\)