lop 1 moi la la do

Toán lớp 6 mới đúng

ai thấy đúng **** cho mk

\(\Leftrightarrow\left(x-7\right)^{x+1}\left[1-\left(x-7\right)^{10}\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^{x+1}=0\\\left(x-7\right)^{10}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\end{matrix}\right.\)

( x - 7 )^x+1 - ( x - 7 )^x+11 = 0

( x - 7 )^x+1 . [ 1 - ( x - 7 )¹⁰ ] = 0

\(\Leftrightarrow\orbr{\begin{cases}x-7=0\\\left(x-7\right)^{10}=1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=7\\x-7=1\text{ hoặc }-1\end{cases}}\)

\(\Leftrightarrow x\in\left\{6,7,8\right\}\)

x là 1 trong 3 số 6,7,8

\(x\in\left\{6;7;8\right\}\)

k mik nhé

\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)

=> (x-7)^x . (x-7) - (x-7)^x . (x-7)¹¹ = 0

=> \(\left(x-7\right)^x.\left[\left(x-7\right)-\left(x-7\right)^{11}\right]=0\)

=> [(x-7) - (x-7)¹¹ ] = 0

=> \(\left\{\left(x-7\right).\left[1-\left(x-7\right)^{10}\right]\right\}=0\)

\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)^{10}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=7\\\left(x-7\right)^{10}=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=7\\\left(x-7\right)^{10}=\left(-1\right)^{10}=1^{10}\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=7\\x-7=1\\x-7=-1\end{cases}}\Rightarrow\hept{\begin{cases}x=7\\x=8\\x=6\end{cases}}\)

Vậy x thuộc { 6,7,8}

cố đúng k vậy bạn được bn phần trăn ạ

(x - 7)^x + 1 - (x - 7)^x + 11 = 0

(x - 7)^x . (x - 7) - (x - 7)^x . (x - 7)^11 = 0

(x - 7)^x . [(x - 7) - (x - 7)^11] = 0

=> (x - 7)^x = 0 hoặc [(x - 7) - (x - 7)^11] = 0

* TH1: (x - 7)^x = 0

=> x - 7 = 0

=> x = 0 + 7

=> x = 7

* TH2: [(x - 7) - (x - 7)^11] = 0

=> x - 7 = (x -7)^11

=> x - 7 = 1 hoặc x  - 7 = 0

x - 7 = 1

=> x = 1 + 7

     x = 8

x - 7 = 0 (TH1)

Vậy x = 7 hoặc x = 8.

\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)

\(\Leftrightarrow\left(x-7\right)\left(x-7\right)^x-\left(x-7\right)\left(x-7\right)^x\left(x-7\right)^{10}=0\)

\(\Leftrightarrow\left(x-7\right)\left(x-7\right)^x\left[1-\left(x-7\right)^{10}\right]=0\)

\(\Leftrightarrow\left[\begin{matrix}x-7=0\left(1\right)\\\left(x-7\right)^x=0\left(2\right)\\1-\left(x-7\right)^{10}=0\left(3\right)\end{matrix}\right.\)

(1) và (2)=> x=7

(3)\(\Leftrightarrow\left(x-7\right)^{10}=1\Rightarrow x-7=\pm\sqrt[10]{1}=\pm1\Rightarrow\left[\begin{matrix}x=8\\x=6\end{matrix}\right.\)

Kết luận nghiệm: x={6,7,8}