Mình nghĩ đề thế này mới tính hợp lí được

2 ) B = \(1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)

B = 47/41 . ( 12/3 : 4/5 ) . 123/235

B = 47/41 . ( 4 : 4/5 ) . 123/235

B = 47/41 . 5 . 123/235

B = \(\frac{47.5.123}{41.235}\)

B = 3

1 ) A = \(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

A = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

A = \(\frac{0}{1+2+3+...+2006}\)

A = 0

\(x=-37\)

y =2(\(\frac{37\cdot10101}{120\cdot10101}\)-\(\frac{37\cdot10101}{6\cdot10101}\)):\(\frac{1}{x}\)=-37

y=2(37/120-37/6):1/x=-37

y=2(37/120-740/120):1/x=-37

y=2.(-703/120):1/x=-37

y=--703/60:1/x=-37

1/x=-703/60:-37

1/x=19/60

x=60/19

A=63*10101*37-37*10101*63

        (2006-1):1+1:2*(2006+1)

A=67*37-37*63

      2013021

A=0

A=63*10101*37-37*10101*63

        (2006-1):1+1:2*(2006+1)

A=67*37-37*63

      2013021

A=0

=   63 . 10101 . 37 - 37 .10101 . 63

       1 + 2 + 3 + ... + 2006

= ( 63 - 63 ) . ( 37 . 37 ) . ( 10101 - 10101 )

        1 + 2 + 3 + ... + 2006

= 0 . 0 . 0

1 + 2 + 3 + ... + 2006

= 0

\(A=-66.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{11}\right)+124.\left(-37\right)+63.\left(-124\right)\)

\(A=-66.\left(\frac{33}{66}-\frac{22}{66}+\frac{6}{66}\right)+\left(-124\right).\left(37+63\right)\)

\(A=-66.\frac{17}{66}+\left(-124\right).100\)

\(A=-17+\left(-12400\right)\)

A = -12417

\(-66\cdot\left[\frac{1}{2}-\frac{1}{3}+\frac{1}{11}\right]+124\cdot\left[-37\right]+63\cdot\left[-1+24\right]\)

\(=-66\cdot\left[\frac{1}{6}+\frac{1}{11}\right]+\left[-4588\right]+63\cdot23\)

\(=-66\cdot\frac{17}{66}+\left[-4588\right]+1449\)

\(=-17+\left[-4588\right]+1449=-4605+1449=-3156\)

Các bạn ủng hộ cho mình nhé

\(=\dfrac{37\times10101\times25-25\times10101\times37}{1+2+...+11}=\dfrac{0}{1+2+...+11}=0\)