1=1^2 ;125=5^3 ;-125=-5^3; 27=27^1; -27= -27^1

2: 5^2 25^1 

`@` `\text {Ans}`

`\downarrow`

`-1/27 = ( (-1)^3/(-3)^3) =(-1/3)^3`

`8/729 = ( (2^3)/(9^3) ) = (2/9)^3`

`16/685 = ( (4^2)/( \sqrt {685}) ) = (4/(\sqrt {685}) )^2`

125=5³=

-125=(-5)³

27=3³

-27=(-3)³

125 =5³ - 125=(-5)³ ; 27 =3³; - 27 =(-3)³

0,25 = (0,5)²

\(\dfrac{1}{49}\) = (\(\dfrac{1}{7}\))²

- \(\dfrac{27}{125}\) = (- \(\dfrac{3}{5}\))³

 \(\dfrac{81}{16}\) = ( \(\dfrac{9}{4}\))²

\(\dfrac{169}{196}\) = (\(\dfrac{13}{14}\))²

10=căn 10

27= 3³

64=8²

81=9²

Ta có:  10=2.5= 2¹.5¹

           27=3.3.3=3³

          64=16.4=4².4¹=4³

          81=27.3=3³.3=3⁴

10=2¹.5¹

27=3³

64=4³

81=3⁴=9²

\(\left(\dfrac{1}{27}\right)^5\) = \(\left(\dfrac{1}{3^3}\right)^5\) = \(\left(\dfrac{1}{3}\right)^{15}\)

\(\left(\dfrac{1}{27}\right)^5=\left[\left(\dfrac{1}{3}\right)^3\right]^5=\dfrac{1}{3}^{3.5}=\dfrac{1}{3}^{15}\)

\(\left(\dfrac{1}{27}\right)^5=\left(\dfrac{1}{3^3}\right)^5=\left(3^{-3}\right)^5=3^{-3.5}=3^{-15}\)

D = 27³ . 9⁴ . 243 = 3⁹ . 3⁸ . 3⁵ = 3⁹⁺⁸⁺⁵ = 3²²

\(125=5^3\)

\(-125=\left(-5\right)^3\)

\(27=3^3\)

\(-27=\left(-3\right)^3\)

 ^...^ ^_^

Bài 11: Viết các số sau dưới dạng lũy thừa với số mũ khác 1:

125 = 5³

(-125) = (-5)³

27 = 3³

(-27) = (-3)³

125 = 125^2-1 ; - 125 = - 125^1009-1008 ; 27 = 27^{10000000000-9999999999} ; - 27 = - 27^{\(\infty+1-\infty\)}             :)