Tìm số nguyên x, biết:
-{-3x+2[45-x-3(3x+7)-2x]+4x}=55
Tìm số nguyên x :
{- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
{-3x + 2. [ 45 - x - 9x -21 - 2x ] + 4x } = 55
suy ra { - 3x +2.[24 - 12x] + 4x } = 55
suy ra x+ 48 - 24x = 55
suy ra - 23x=7
suy ra x= - 7/23
Tìm số nguyên x:
a,-2x+15<3x-7<19-x
b,-2x +3.{12-2[3x-(20+2x)-4x]+1}=45
c,{-3x+2.[45-x-3(3x 7)-2x] 4x}=55
Ai làm nhanh và đúng, mik tick
mong các bn giúp mik, mik đag cần gấp
Tìm số nguyên x biết:
a,{-3x+2.[45-x-3.(3x+7)-2x]+4x}=55
b,103-57:[-2.(2x-1)2-(-9)0)=-106
Bài 1: Tìm số nguyên x:
{-3x+2.[45-x-3(3x+7)-2x]+4x}=55-103
-57:[-2.(2x+1)^2-(-9)^0=-106
\(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103\)
\(\left\{-3x+2\left[45-x-9x-21-2x\right]+4x\right\}=-48\)
\(-3x+90-2x-18x-42-4x+4x=-48\)
\(-3x-2x-18x-4x+4x=-48-90+42\)
\(-23x=-96\Leftrightarrow x=\frac{96}{23}\)
đag rảnh nên ... lm nốt
\(-57:\left[-2\left(2x+1\right)^2-\left(-9\right)^0\right]=-106\)
\(-2\left(2x+1\right)^2+1=57\)
\(-2\left(2x+1\right)^2=56\)
\(\left(2x+1\right)^2=-28\)
\(\Rightarrow\orbr{\begin{cases}2x+1=-2\sqrt{7}\\2x+1=2\sqrt{7}\end{cases}\Rightarrow\orbr{\begin{cases}2x=-1-2\sqrt{7}\\2x=-1+2\sqrt{7}\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-1-2\sqrt{7}}{2}\\x=\frac{-1+2\sqrt{7}}{2}\end{cases}}\)
Tìm số nguyên x:
a) -2x -(x-17)=34 -(-x+25)
b) 17x -(16x-37)=2x+43
c) -2x - 3.(x-17)=34-2(-x+25)
d) 17x + 3.(-16-37)=2x + 43 -4x
e) {-3x + 2.[45 - x - 3(3x + 7)-2x] + 4x}=55
Giúp mik vs:33
a,-2x -(x-17)=34-(-x+25)
-2x-x+17=34+x-25
-3x+17=9+x
-3x-x=9-17
-4x=-8
-->4x=8
x=8:4
x=2
Vậy x=2
b,17-(16x-37)=2x+43
17-16x+37=2x+43
20-16x=2x+43
-16x-2x=43-20
-18x=23
x=23:(-18)
x=23/-18
Mà x là số nguyên nên --> x thuộc tập rỗng
c,-2x-3.(x-17)=34-2(-x+25)
-2x-3x+51=34-2.(-x)-25
-5x+51=9-(-2).x
-5x+(-2).x=9-51
-7x=-42
7x=42
x=42:7
x=6
Vậy x=6
3x+2{45-x-3[3x+7]-2x}+4x=55
3x+2{45-x-3[3x+7]-2x}+4x=55
<=>3x+2[45-x-9x-27-2x]+4x=55
<=>3x+90-2x-18x-54-4x+4x=55
<=>36-17x=55
<=>17x=-19
<=>x=-19/17
Vậy x=-19/17
3x+2{45-x-3[3x+7]-2x}+4x=55
=> 7x+2{45-x-9x-21-2x}=55
=>7x+2{24-12x}=55
=>7x+48-24x=55
=>-17x=7
=> x=\(\frac{-7}{17}\)
3x + 2{45-x-9x -21 - 2x } + 4x = 55
suy ra 3x + 2{24-12x}+4x=55
suy ra 3x + 48 - 24x + 4x = 55
suy ra 17x=-7
suy ra x=-7/17
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
ko chép lại đề bài
<=> {(-3x+4x)+2[ 45-(x+2x)-9x-21]}=55
<=> {x+2[(45-21)-(3x+9x)]}=55
<=> x+2[24-12x]=55
<=> x+48-24x=55
<=> 48-23x=55
<=>23x=48-55=-7
<=>x=\(\frac{-7}{23}\)
B) 17X - ( -16X - 37 ) + 2x + 43
C) -2x -3.( x-17) = 34 -2 (-2x +25)
D) 17x+ 3. ( -16x -37) = 2x +43 -4x
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
F) -103 - 57 : [ -2 ( 2x -1 )2 - ( -9 )0 ] - 106
G) -2x + 3. { 12-2 [ 3x - ( 20 + 2x ) - 4x ] + 1} = 45
{-3+2.[45-x-3(3x+7)-2x]+4x}=55-103-57:[-2(2X-1)^2-(-9)^0]=-106