x^3 - x + 3x^2y + 3xy^2 + y^3 - y

=x³+y³+3x²y+3xy²-x-y

=(x+y)(x²-xy+y²)+3xy(x+y)-(x+y)

=(x+y)(x²-xy+y²+3xy-1)

=(x+y)(x²+2xy+y²-1)

=(x+y)[(x+y)²-1]

=(x+y)(x+y-1)(x+y+1)

x^2 + 5x - 6

=x²-x+6x-6

=x.(x-1)+6.(x-1)

=(x-1)(x+6)

\(x^2+y^2-x^2y^2+xy-x-y\)\(=\left(xy-x\right)+\left(y^2-y\right)-\left(x^2y^2-x^2\right)\)

\(=x\left(y-1\right)+y\left(y-1\right)-x^2\left(y^2-1\right)\)\(=\left(y-1\right)\left[x+y-x^2\left(y+1\right)\right]\)

\(=\left(y-1\right)\left(x+y-x^2y-x^2\right)\)\(=\left(y-1\right)\left[x\left(1-x\right)+y\left(1-x^2\right)\right]\)

\(=\left(y-1\right)\left(1-x\right)\left[x+y\left(1+x\right)\right]=\left(y-1\right)\left(1-x\right)\left(xy+x+y\right)\)

4x⁴ - 21 x²y² + y⁴ 

= (4x⁴ + 4x²y² + y⁴) - 25x²y² 

=  [(2x²)² + 2x² . 2 . y² + (y²)²] - 25x²y²

= (2x² + y²) - 25x²y² 

= (2x² + y² - 5xy) (2x² + y² + 5xy)

a) 7xy^2+5x^2y

= xy(7y+5x)

b) x^2+2xy+y^2-11x-11y

= (x^2+2xy+y^2)-(11x+11y)

=(x+y)^2-11(x+y)

=(x+y)(x+y-11)

a) 7xy² + 5x²y

= xy ( 7y + 5x )

b) x² + 2xy + y² - 11x - 11y

= ( x² + 2xy + y² ) - ( 11x + 11y )

= ( x + y )² - 11 ( x + y )

= ( x + y )( x + y - 11 )

3x² - 7x - 10

= 3x² + 3x - 10x - 10

= (3x² + 3x) - (10x + 10)

= 3x(x + 1) - 10(x + 1)

= (3x - 10)(x + 1)

5x³ - 5x²y - 10x² + 10xy

= 5x(x² - xy - 2x + 2y)

= 5x[(x² - xy) - (2x - 2y)]

= 5x[x(x - y) - 2(x - y)]

= 5x(x - 2)(x - y)

chúc bn hok tốt

nhớ ủng hộ tik cho mik nhé! ko lần sau mik ko giúp đâu

có j ko hiểu thì bn cứ bình luận ở dưới nhé

Đây là 1 hay 2 phần z bn

Trình bày cái đề cho đàng hoàng giúp.

x²-xy-2y²

= x²-2xy+xy-2y²

=x(x-2y)+y(x-2y)

=(x-2y)(x+y)