3x+17=12
-13*x=-26
Hộ mk
3x+17=12
/x-1/=0
-13*/x/=-26
giupmk nha ai tra loi chinh xac mk k cho
3x+17=12
=>3x=12-17
=>3x=-5
=>x=-5:3
=> x=-5/3
vậy x=-5/3
|x-1|=0
=>x-1=0
=>x=0+1
=>x=1
-13.|x|=-26
=>||x|=-26:-13=2
=> x thuộc tập hợp các số -2 hoặc 2
vậy x=2;-2
K nha
257-(3x+25)=157
x-140:35=270
23-(x:13)=18
9(x+5)-13=671
9(4x)-13=24
(x-5)-34:17=1
.(2x-7). 3=3 dấu chấm là nhân nhé
(3x-5):2=4.5
9.(x+3)-20=5+4.5
70-(2x-50)=0
8.5-(x+7)=3.10
17-(x:12)=17
32.9-8x=100.2
9.(x+5)-13=671
5.(x+5)-2.24=2.26
4.(x+1)-28=3.4
giúp mk mk tích cho
\(257-\left(3x+25\right)=157\)
\(3x+25=257-157\)
\(3x+25=100\)
\(3x=75\)
\(x=25\)
vay \(x=25\)
\(x-140:35=270\)
\(x-4=270\)
\(x=274\)
vay \(x=274\)
\(23-\left(x:13\right)=18\)
\(\frac{x}{13}=5\)
\(\frac{x}{13}=\frac{65}{13}\)
\(\Rightarrow x=65\)
vay \(x=65\)
\(9\left(x+5\right)-13=671\)
\(9x+45=684\)
\(9x=639\)
\(x=71\)
vay \(x=71\)
\(9\left(4x\right)-13=24\)
\(36x=37\)
\(x=\frac{37}{36}\)
vay \(x=\frac{37}{36}\)
\(\left(x-5\right)-34:17=1\)
\(\left(x-5\right)-2=1\)
\(x-5=3\)
\(x=8\)
vay \(x=8\)
\(\left(2x-7\right).3=3\)
\(2x-7=1\)
\(2x=8\)
\(x=4\)
vay \(x=4\)
\(\left(3x-5\right):2=4.5\)
\(\left(3x-5\right):2=20\)
\(3x-5=10\)
\(3x=15\)
\(x=5\)
vay \(x=5\)
con lai lam tuong tu
mk moi tay roi nen ban tu lam vay
Tìm x :
a, ( 4x - 13 ) - (3x + 17) = -19 - (-12)
a, ( 4x - 13 ) - (3x + 17) = -19 - (-12)
=> 4x - 13 - 3x - 17 = -19 + 12
=> x = -19 + 12 + 13 + 17 = 23
( 4x - 13 ) - (3x + 17) = -19 - (-12)
4x - 13- 3x - 17= -7
(4x-3x)-13=-7
x-13=-7
x=-7 +13
x=6
-4/13 x 5/17 + -12/13 x 4/17 + 4/13
thực hiện phép tính
mn giúp vs mk đag rất gấp
\(-\dfrac{4}{13}.\dfrac{5}{17}+-\dfrac{12}{17}.\dfrac{4}{13}+\dfrac{4}{13}\)
= \(-\dfrac{4}{13}.\dfrac{5}{17}+-\dfrac{12}{17}.\dfrac{4}{13}+\dfrac{4}{13}.1\)
=\(\dfrac{4}{13}.\left(\dfrac{-5}{17}+\dfrac{-12}{17}+1\right)\)
= \(\dfrac{4}{13}.\left(-1+1\right)\)
= \(\dfrac{4}{13}.0\)
= 0
3x+17=12
/x-1/=0
-13*/x/=-26
tìm x, biết:
3x+17=12
|x-1|=0
-13.|x|=-26
3x+17=12
=>3x=12-17
=>3x=-5
=>x=-5:3
=>x=-1,66
/x-1/=0
=>x-1=0
=>x =0+1
=>x =1
-13./x/=-26
=>/x/=-26:(-13)
=>/x/=2
=>x=-2 hoặc x=2
Bài 1 Tính
a, 12/21-3/7+-2/3
b,(-25/13)+(-9/17)+12/13+(-25/17)
c,5/9.7/13+5/9.9/13-5/9.3/13
Bài 2 tìm x
a,2/3x+5/7=3/10
b,x:5/2-1/2=-2/3
c,|x-3/4|-1/2=0
Bài 1 :
a) \(\frac{12}{21}-\frac{3}{7}+\left(-\frac{2}{3}\right)=\frac{4}{7}-\frac{3}{7}+\left(-\frac{2}{3}\right)=\frac{1}{7}-\frac{2}{3}=-\frac{11}{21}\)
b) \(\left(-\frac{25}{13}\right)+\left(-\frac{9}{17}\right)+\frac{12}{13}+\left(-\frac{25}{17}\right)\)
\(=\left[\left(-\frac{25}{13}\right)+\frac{12}{13}\right]+\left[\left(-\frac{9}{17}\right)+\left(-\frac{25}{17}\right)\right]\)
\(=-1+\left(-2\right)=-1-2=-3\)
c) \(\frac{5}{9}\cdot\frac{7}{13}+\frac{5}{9}\cdot\frac{9}{13}-\frac{5}{9}\cdot\frac{3}{13}=\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)=\frac{5}{9}\cdot1=\frac{5}{9}\)
Bài 2 :
a) \(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
=> \(\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}=-\frac{29}{70}\)
=> \(x=\left(-\frac{29}{70}\right):\frac{2}{3}=\left(-\frac{29}{70}\right)\cdot\frac{3}{2}=-\frac{87}{140}\)
b) \(x:\frac{5}{2}-\frac{1}{2}=-\frac{2}{3}\)
=> \(x:\frac{5}{2}=-\frac{2}{3}+\frac{1}{2}=-\frac{1}{6}\)
=> \(x=\left(-\frac{1}{16}\right)\cdot\frac{5}{2}=-\frac{5}{32}\)
c) Bạn chỉ cần xét hai trường hợp âm và dương thôi :>
a) 2x+(-31)-(-42)=-3x-45
b) (-12)-(13-2x)=15-(-17)-x
a) 2x - 31 + 42 = - 3x - 45
2x + 11 = - 3x - 45
2x + 3x = - 45 - 11
5x = - 56
x = - 56/5
b) - 25 + 2x = 15 + 17 - x
2x + x = 32 + 25
3x = 57
x = 19
Tìm x thuộc Z để :
Amax = 13/17-x
Cmax = 40-3x/13-x
Bmin= 3/x-7
Dmin= 20-x/x-12