CH3COONa + NaOH---CaO,\(t^o\)---> CH4 + Na2CO3

2CH4 --t\(^o=1500^oC,\)làm lạnh nhanh--> C2H2 + 3H2

C2H2 + H2 --\(t^o,xt,Pd\)--> C2H4

C2H4 + H2O --\(t^o,H2SO4\)--> C2H5OH

3C2H5OH + 3C6H6O -> 4C6H6 + 6H2O

C6H6 + HNO3 --\(t^o,H2SO4\)--> C6H5NO2 + H2O

(1) \(2CH_4\rightarrow C_2H_2+2H_2\)

(2) \(C_2H_2+H_2\rightarrow C_2H_4\)

(3) \(C_2H_4+H_2O\rightarrow C_2H_5OH\)

(4) \(C_2H_4+H_2\rightarrow C_2H_6\)

(5) \(C_2H_6+Cl_2\rightarrow HCl+C_2H_5Cl\)

(6) \(3C_2H_2\rightarrow C_6H_6\)

(7) \(C_6H_6+Br_2\rightarrow HBr+C_6H_5Br\)

(8) \(2C_6H_6+15O_2\rightarrow12CO_2+6H_2O\)

Mình viết đoạn văn luôn nha có cả lợi ích lẫn tác hại đó bạn , như vậy mình nghĩ nó sẽ đầy đủ hơn:

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Vitually,Internet is still very necessary for our modern life . But ,use Internet in the right way for good life.

OK rồi đó bạn ạ bài này là bài nói học kì trên lớp của mình đó bạn nhưng đánh máy lâu quá . Chúc bạn học giỏi nnha!

: a) CaCO3, CaO, CaC2, C2H2, C2H4, C2H6, CO2, CO

=> CaCO3-->CaO+CO2

CaO+C-->CaC2+CO

CaC2+H2O-->Ca(OH)2+C2H2

C2H2+H2-->C2H4

C2H4+H2-->C2H6

C2H6+O2-->CO2+H2O

CO2+C-->CO

C)Al+Cl2-->AlCl3

AlCl3+NaoH-->Al(OH)3+NaCl

Al(OH)3-->Al2O3+H2O

Al2o3+C-->Al4C3+CO

Al4C3+H2O-->Al(OH)3+CH4

CH4+H2-->C2H2

a) CaCO3--to-->CaO+CO2

CaO+2C--->CaC+CO

2CaC+2H2O--->Ca(OH)2+C2H2

C2H2+H2--to->C2H4

C2H4+H2--->C2H6

C2H6+7/2O2-->2CO2+3H2O

CO2+C---to->2CO

b) C2H6+Cl2-->C2H5Cl+HCl

C2H5Cl-->C2H4+HCl

C2H4+Br2--->C2H4Br2

C2H4Br+2NaOH-->C2H4(OH)2+2NaBr

c) 2Al+6HCl-->AlCl3+3H2

AlCl3+3NaOH-->Al(OH)3+3NaCl

2Al(OH)3-->Al2O3+3H2O

2Al2O3+9C--->Al4C3+6CO

Al4C3+12H2O--->3CH4+4Al(OH)3

2CH4-->C2H2+3H2

3C2H2-->C6H6

C6H6+CH3Cl--->C6H5CH3+HCl

C6H5CH3+2KMnO4--->H2O+KOH+2MnO2+C6H5COOK

: a) CaCO3, CaO, CaC2, C2H2, C2H4, C2H6, CO2, CO

=> CaCO3-->CaO+CO2

CaO+C-->CaC2+CO

CaC2+H2O-->Ca(OH)2+C2H2

C2H2+H2-->C2H4

C2H4+H2-->C2H6

C2H6+O2-->CO2+H2O

CO2+C-->CO

C)Al+Cl2-->AlCl3

AlCl3+NaoH-->Al(OH)3+NaCl

Al(OH)3-->Al2O3+H2O

Al2o3+C-->Al4C3+CO

Al4C3+H2O-->Al(OH)3+CH4

CH4+H2-->C2H2

\(CH_3COONa+NaOH\underrightarrow{t^o,CaO}Na_2CO_3+CH_4\)

\(2CH_4\underrightarrow{1500^oC,làm.lạnh.nhanh}CH\equiv CH+3H_2\)

\(2CH\equiv CH\underrightarrow{t^o,xt}CH\equiv C-CH=CH_2\)

\(CH\equiv C-CH=CH_2+3H_2\underrightarrow{t^o,Ni}CH_3-CH_2-CH_2-CH_3\)

\(CH_3-CH_2-CH_2-CH_3\underrightarrow{t^o,xt}CH_2=CH_2+CH_3-CH_3\)

\(CH_2=CH_2+H_2O\underrightarrow{H^+,t^o}CH_3-CH_2-OH\)

\(CH_3-CH_2-OH\underrightarrow{H_2SO_4,170^oC}CH_2=CH_2+H_2O\)

\(nCH_2=CH_2\underrightarrow{t^o,p,xt}\left(-CH_2-CH_2-\right)_n\)

a)

\(C_6H_6+Br_2\xrightarrow[t^o]{Fe}C_6H_5Br+HBr\)

CH₄ không phản ứng

b)

\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)

CH₄ không phản ứng

c) 

\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)

\(C_2H_2+2Br_2\rightarrow C_2H_2Br_4\)

d)

\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)

C₆H₁₂ nếu là mạch vòng thì không phản ứng còn nếu là mạch hở (nhánh hoặc thẳng) thì làm mất màu

\(C_6H_{12}+Br_2\rightarrow C_6H_{12}Br_2\)

Trả lời ;

đây ạ chúc anh học tốt