\(\left(\frac{3}{5}\right)^x.\left(\frac{625}{81}\right)^3=\frac{243}{3125}\)

=>\(\left(\frac{3}{5}\right)^x.\left(\frac{5}{3}\right)^{12}=\left(\frac{3}{5}\right)^5\)

=>\(\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^5:\left(\frac{5}{3}\right)^{12}\)

=>\(\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^{17}\)

=>x=17

\(\left(\frac{3}{5}\right)^x.\left(\frac{625}{81}\right)^3=\frac{243}{3125}\)

\(\Rightarrow\left(\frac{3}{5}\right)^x.\left(\frac{3}{5}\right)^{12}=\left(\frac{3}{5}\right)^5\)

\(\Rightarrow\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^5:\left(\frac{3}{5}\right)^{12}\)

\(\Rightarrow\left(\frac{3}{5}\right)^x=\left(\frac{5}{3}\right)^7\)

\(\Rightarrow x=-7\)

3^ x . 3^ 2= 729

3^ x  . 9        = 729

3^ x               = 729: 9

3^x                 =81 

vậy    x            = 3^3

5^ x . 625 = 3125

5^x           = 3125:625

5^x            =   5

vậy x          = 1

( 2x+1 )^ 3 = 27

( 2x+1) ^ 3 = 3^3

vậy 2x+1 =  3

  vậy x = 0         

\(3125:25< 5^{2n}:125\le625:5^3\)

\(5^5:5^2< 5^{2n}:5^3\le5^4:5^3\)

\(5^3< 5^{2n}:5^3\le5\)

Mà em ơi, em đã hok lũy thừa của một lũy thừa chưa, nói đến đây sợ ko hiểu

avuiadsadasdsdasdasasda osas

2k4

~the end~

3906/3125

\(\dfrac{1}{25}\)+\(\dfrac{1}{625}\)+\(\dfrac{1}{3125}\)=\(\dfrac{125}{3125}\)+\(\dfrac{5}{3125}\)+\(\dfrac{1}{3125}\)

=\(\dfrac{131}{3125}\)

chúc bạn học tốt ạ