tính giá trị biểu thức ;1\1*2*3+1\2*3*4+..............................+1\2017*2018*2019
Tinh gia tri bieu thuc [m + n ]:p neu m=5,n=19 va p=3 .Vay gia tri bieu thuc la:
cho a R b =a*b/ a+b . Tinh gia tri bieu thuc cua : 13R7 - 12r4 . TINH gia tri cua bieu thuc tren ( 30 giay )
\(\frac{31}{20}\)đáp số đúng 1000000000000000000000000000000000000000000000000000% đó nha
h and kb nhé
cho x+y =1 . tinh gia tri cua bieu thuc A=x^3+y^3+3xy
chox-y=1. tinh gia tri cua bieu thuc B=x^3-y^3-3xy
cho x+y=1 . tinh gia tri cua bieu thuc C=x^3+y^3+3xy(x^2+y^2)+6x^2*y^2(x+y)
Câu 1: Ta có: A = \(x^3+y^3+3xy=x^3+y^3+3xy\times1=x^3+y^3+3xy\left(x+y\right)\)
\(=\left(x+y\right)^3=1^3=1\)
Câu 2: Ta có: \(B=x^3-y^3-3xy=\left(x-y\right)\left(x^2+xy+y^2\right)-3xy\)
\(=x^2+xy+y^2-3xy=x^2-2xy+y^2=\left(x-y\right)^2=1^2=1\)
Câu 3: Ta có: \(C=x^3+y^3+3xy\left(x^2+y^2\right)-6x^2.y^2\left(x+y\right)\)
\(=x^3+y^3+3xy\left(x^2+2xy+y^2-2xy\right)+6x^2y^2\)
\(=x^3+y^3+3xy\left(x+y\right)^2-3xy.2xy+6x^2y^2\)
\(=x^3+y^3+3xy.1-6x^2y^2+6x^2y^3\)
\(=x^3+y^3+3xy\left(x+y\right)=\left(x+y\right)^3=1^3=1\)
cho bieu thuc A=2,45*(a+64,36)-45
a tinh gia tri bieu thuc A khi a=35,64
b tim gia tri cua A de bieu thuc A =126,5
b. Neu A =126.5 thì 126.5=2.45 x (a+64.36) -45
= 2.45 x (a+64.36) 126.5 + 45
= 2.45 x (a+64.36) = 171.5
= a+64.36 = 171.5 : 24.5
a+64.36 = 70
a = 70 - 64.36
a = 5.64
a,thay a=35,64vào bthuc đã cho ta đc:
A= 2,45x(35,64 +64,36)-45=2,45x100-45=200
b,để A=126,5 thì 2,45x(a+64,36)-45=126,5
=>2,45a+157,682-45=126,5
=>2,45a=13,818
=>a=5,64
cistian ronaldo
bai 1 tinh gia tri cua bieu thuc 78 x m + 22 x m voi m =135
bai 2 tinh gia tri cua bieu thuc 78 x m + 42 x m -20 x m voi m =1035
bai 3 cho bieu thuc B = 119 x n - n x 9 bieu thuc B co gia tri bang 8470 khi n =............
Cau 9 : Cho bieu thuc : A= 2002 - 1998 \ [ a - 16 ] /316 + 6,84 \ 0,01 . Tinh gia tri bieu thuc a de bie thuc A co gia tri nho nhat ?
CHO bieu thuc
B=17,58*43+57*17,58/293*A
a)tim gia tri cua bieu thuc Bkhi a=2
b)tinh gia tri a khi B=2
c)tim gia tri so tu nhien ad biet bieu thuc B co gia tri lon nhat ,gia tri lon do la bao nhieu
Cho bieu thuc A = \(^{x2+4x+3}\)
a Tinh gia tri bieu thuc tai x= \(\frac{-1}{2}\)
b Tinh gia tri x de bieu thuc A bang 0
a. Tại x=\(\frac{-1}{2}\), ta có:
\(\left(\frac{-1}{2}\right)^2+4.\left(\frac{-1}{2}\right)+3=\frac{1}{4}+\left(-2\right)+3=\frac{5}{4}\)
b. Ta có:
\(x^2+4x+3=0\)
\(\Rightarrow x^2+x+3x+3=0\)
\(\Rightarrow\left(x^2+x\right)+\left(3x+3\right)=0\)
\(\Rightarrow x\left(x+1\right)+3\left(x+1\right)=0\)
\(\Rightarrow\left(x+1\right)\left(x+3\right)=0\)
\(\Rightarrow\hept{\begin{cases}x+1=0\\x+3=0\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\x=-3\end{cases}}}\)
Vậy \(x=-1;x=-3\)
tinh gia tri bieu thuc ;a+a+a+a+a+b+b+b+b+b.biet a + b=105
gia tri cua bieu thuc tren la...
=(a+b)+(a+b)+(a+b)+(a+b)+(a+b)
=(a+b)*5
=105*5
=525
TINH GIA TRI BIEU THUC ko tim n tinh bieu thuc
125.(-61):(-2)^3:(-1)^2n (nTHUOC N*)