\(\left(\frac{5}{7}+\frac{2}{3}\right).\frac{7}{11}\)

C1:\(=\frac{29}{21}.\frac{7}{11}=\frac{29}{33}\)(tính trong ngoặc rồi mới nhân)

C2:\(=\frac{5}{7}.\frac{7}{11}+\frac{2}{3}.\frac{7}{11}=\frac{5}{11}+\frac{14}{33}=\frac{29}{33}\)(dùng tính chất phân phối)

Những câu khác bn tự làm nha

ai giúp mk làm hết mk tích nhiều cho nhé

ai giúp tui làm cả bài này đi tui tịk mỗi ngày cho

ông xem qua bà xem lại giúp cho con đi mà hu hiu hu

a)x-5=7

=> x=9

b)2.x+6=24

=>2x=18

=>x=9

Tìm x :

a) \(x-5=49:7\)

\(\Leftrightarrow x-5=7\)

\(\Leftrightarrow x=7+5\)

\(\Leftrightarrow x=12\)

Vậy : \(x=12\)

b) \(2x+6=24\)

\(\Leftrightarrow2x=24-6=18\)

\(\Leftrightarrow x=18:2\)

\(\Leftrightarrow x=9\)

Vậy : \(x=9\)

c) \(\frac{1}{3}:x+\frac{1}{2}=5\)

\(\Leftrightarrow\frac{1}{3}:x=5-\frac{1}{2}=\frac{9}{5}\)

\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{5}\)

\(\Leftrightarrow x=\frac{5}{27}\)

Vậy : \(x=\frac{5}{27}\)

d) \(\frac{1}{6}.x-\frac{1}{3}=2\)

\(\Leftrightarrow\frac{1}{6}.x=2-\frac{1}{3}=\frac{5}{3}\)

\(\Leftrightarrow x=\frac{5}{3}:\frac{1}{6}\)

\(\Leftrightarrow x=10\)

Vậy : \(x=10\)

e) \(\frac{x}{27}=\frac{3}{x}\)

\(\Leftrightarrow x.x=27.3\)

\(\Leftrightarrow x^2=81\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=9\end{matrix}\right.\) mà \(x\in N\)

\(\Rightarrow x=9\)

Vậy : \(x=9\)

g) \(1200:24-\left(17-x\right)=36\)

\(\Leftrightarrow50-17+x=36\)

\(\Leftrightarrow33+x=36\)

\(\Leftrightarrow x=36-33\)

\(\Leftrightarrow x=3\)

Vậy : \(x=3\)

h) \(674-\left(12+x\right)=427\)

\(\Leftrightarrow12+x=674-427=247\)

\(\Leftrightarrow x=247-12\)

\(\Leftrightarrow x=230\)

Vậy : \(x=230\)

k) \(36.\left(x-9\right)=900\)

\(\Leftrightarrow x-9=900:36\)

\(\Leftrightarrow x-9=25\)

\(\Leftrightarrow x=25+9\)

\(\Leftrightarrow x=34\)

m) \(1,2:x+3,8:x=2,5\)

\(\Leftrightarrow\left(1,2-3,8\right):x=2,5\)

\(\Leftrightarrow-2,6:x=2,5\)

\(\Leftrightarrow x=\frac{-2,6}{2,5}=-\frac{26}{25}\)

Vậy : \(x=-\frac{26}{25}\)

n) \(\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}\right).x=\frac{1}{3}\)

\(\Leftrightarrow\frac{1}{2}.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}\right).x=\frac{1}{3}\)

\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}\right)\right].x=\frac{1}{3}\)

\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{10}\right)\right].x=\frac{1}{3}\)

\(\Leftrightarrow\frac{1}{2}.\frac{9}{10}.x=\frac{1}{3}\)

\(\Leftrightarrow\frac{9}{20}.x=\frac{1}{3}\)

\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{20}\)

\(\Leftrightarrow x=\frac{20}{27}\)

Vậy : \(x=\frac{20}{27}\)

c)\(\frac{2}{27}\)

d)21

e)81

g)3

k)34

m)2

n)\(\frac{5}{3}\)

Đề bài j kì zịa?

(x-1,3)+(x+2,5)+(x-3,8)=1,9

viết thiếu hihi

(x - 1,3) + (x + 2,5) + (x - 3,8) = 1,9

<=>  x - 1,3 + x + 2,5 + x - 3,8 = 1,9

<=>  3x - 2,6 = 1,9

<=> 3x = 4,5

<=> x = 1,5

Vậy...

ta có:

Thầy làm chi tiết giúp em được ko ạ ?

Tl

a =x-1,3-2,5+x

=-3,8

b,D=x+3 và 1/2+x - 3 và 1/2

=2x

c,A=-x +1/7-x-5/5+4/5=1/7+1/5=12/35

Hok tốt

a)

\((3x-7)^5=0\Rightarrow 3x-7=0\Rightarrow x=\frac{7}{3}\)

b)

\(\frac{1}{4}-(2x-1)^2=0\)

\(\Leftrightarrow (2x-1)^2=\frac{1}{4}=(\frac{1}{2})^2=(-\frac{1}{2})^2\)

\(\Rightarrow \left[\begin{matrix} 2x-1=\frac{1}{2}\\ 2x-1=\frac{-1}{2}\end{matrix}\right.\Rightarrow \Rightarrow \left[\begin{matrix} x=\frac{3}{4}\\ x=\frac{1}{4}\end{matrix}\right.\)

c)

\(\frac{1}{16}-(5-x)^3=\frac{31}{64}\)

\(\Leftrightarrow (5-x)^3=\frac{1}{16}-\frac{31}{64}=\frac{-27}{64}=(\frac{-3}{4})^3\)

\(\Leftrightarrow 5-x=\frac{-3}{4}\)

\(\Leftrightarrow x=\frac{23}{4}\)

d)

\(2x=(3,8)^3:(-3,8)^2=(3,8)^3:(3,8)^2=3,8\)

\(\Rightarrow x=3,8:2=1,9\)

e)

\((\frac{27}{64})^9.x=(\frac{-3}{4})^{32}\)

\(\Leftrightarrow [(\frac{3}{4})^3]^9.x=(\frac{3}{4})^{32}\)

\(\Leftrightarrow (\frac{3}{4})^{27}.x=(\frac{3}{4})^{32}\)

\(\Leftrightarrow x=(\frac{3}{4})^{32}:(\frac{3}{4})^{27}=(\frac{3}{4})^5\)

f)

\(5^{(x+5)(x^2-4)}=1\)

\(\Leftrightarrow (x+5)(x^2-4)=0\)

\(\Leftrightarrow \left[\begin{matrix} x+5=0\\ x^2-4=0\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x+5=0\\ x^2=4=2^2=(-2)^2\end{matrix}\right.\)

\(\Rightarrow \left[\begin{matrix} x=-5\\ x=\pm 2\end{matrix}\right.\)

g)

\((x-2,5)^2=\frac{4}{9}=(\frac{2}{3})^2=(\frac{-2}{3})^2\)

\(\Rightarrow \left[\begin{matrix} x-2,5=\frac{2}{3}\\ x-2,5=\frac{-2}{3}\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=\frac{19}{6}\\ x=\frac{11}{6}\end{matrix}\right.\)

h)

\((2x+\frac{1}{3})^3=\frac{8}{27}=(\frac{2}{3})^3\)

\(\Rightarrow 2x+\frac{1}{3}=\frac{2}{3}\Rightarrow x=\frac{1}{6}\)