tìm x biết:
(x+12) : (10-x) = 10
Tìm x biết : x+2/10^10+x+2/11^11=x+2/12^12+x+2/13^13
Tìm số nguyên x biết: a) 5.x = 10; b) (-15).x = 60; c)12. x + 6 = 30; d) (-10). x + 30 =10
Tìm x biết: \(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\)
\(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\\ \Leftrightarrow\dfrac{x+8}{12}+1+\dfrac{x+9}{11}+1+\dfrac{x+10}{10}+1=0\\ \Leftrightarrow\dfrac{x+20}{12}+\dfrac{x+20}{11}+\dfrac{x+20}{10}=0\\ \Leftrightarrow\left(x+20\right)\left(\dfrac{1}{12}+\dfrac{1}{11}+\dfrac{1}{10}\right)=0\\ \Leftrightarrow x+20=0\Leftrightarrow x=-20\\ KL:...\)
`<=>((x+8)/12+1)+((x+9)/11+1)+((x+10)/10+1)=0`
`<=>(x+20)/12+(x+20)/11+(x+20)/10=0`
`<=>(x+20)(1/12+1/11+1/10)=0`
Vì `1/12+1/11+1/10 ≠ 0`
`=>x+20=0`
`=>x=0-20`
`=>x=-20`
Tìm x biết
x+2/10^10+x+2/11^11=x+2/12^12+x+2/13^13
Tìm x biết
x+1/10+ x+1/10+x+1/12=x+1/13+x+1/14
\(x+\frac{1}{10}+x+\frac{1}{10}+x+\frac{1}{12}=x+\frac{1}{13}+x+\frac{1}{14}\)
\(\Rightarrow3x+\left(\frac{1}{10}+\frac{1}{10}+\frac{1}{12}\right)=2x+\left(\frac{1}{13}+\frac{1}{14}\right)\)
\(\Rightarrow3x+\left(\frac{6}{60}+\frac{6}{60}+\frac{5}{60}\right)=2x+\left(\frac{14}{182}+\frac{13}{182}\right)\)
\(\Rightarrow3x+\frac{17}{60}=2x+\frac{27}{182}\)
\(\Rightarrow3x-2x=\frac{27}{182}-\frac{17}{60}\)(dùng quy tắc chuyển vế)
\(\Rightarrow x=\frac{810}{5460}-\frac{1547}{5460}\)
\(\Rightarrow x=\frac{-737}{5460}\)
bạn nhớ thử lại nhé :)
mk sửa lại đề chút vì x+1/10 fai đến x+1/11 ms đúng
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}+\frac{x+1}{14}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}+\frac{1}{14}\right)=0\)
\(\Leftrightarrow x+1=0\).Do \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}+\frac{1}{14}\ne0\)
\(\Leftrightarrow x=-1\)
tìm X biết ;12+11+10+............+X=12
12 + 11 + 10 +....+ X = 12
11 + 10 + ...+ X = 12 - 12
(X + 11) . n : 2 = 0
X + 11 = 0
X = 0 + 11
X = 11
Vậy X = 11
Tìm x biết
\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}+\frac{x+2}{13^{13}}\)
\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}\frac{x+2}{13^{13}}\)
=> x + 2 = 0
=> x = 0 - 2
=> x = -2
Tìm x biết
chuyển vế rồi phân phối, có 1/10^10+...-1/13^13 khác 0
nên x+2=0
rồi tìm x
Tìm x thuộc Z, biết
( 3x+ 4) :( x-3)
x+1 là ước của 2^2+7
Trình bày ra nhé!!
Đỗ Lê Tú Linh giúp mình đi, mình tick cho!!
tìm x ,biết
a)X-1/2=2/3 c)X:2/5=10
b)Xx5/6=1/27/5-X=12/10
Lời giải:
a.
$x-\frac{1}{2}=\frac{2}{3}$
$x=\frac{2}{3}+\frac{1}{2}=\frac{7}{6}$
b.
$x\times \frac{5}{6}=\frac{1}{2}$
$x=\frac{1}{2}: \frac{5}{6}=\frac{3}{5}$
c.
$x:\frac{2}{5}=10$
$x=10\times \frac{2}{5}=4$
d.
$\frac{7}{5}-x=\frac{12}{10}$
$x=\frac{7}{5}-\frac{12}{10}=\frac{1}{5}$