`@` `\text {Ans}`

`\downarrow`

`c)`

`(34 - 2x)(2x - 6) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`(2019 - x)(3x - 12) = 0`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}.`

`@` `\text {Kaizuu lv uuu}`

giúp mik với

a) \(\left|x-3\right|+\left|2x-6\right|=8\)

\(x-3+2x-6=8\)

\(3x-9=8\)

\(3x=17\)

\(\Rightarrow x=\frac{17}{3}\)

b) Tương tự câu a .

c) \(\left|2x-3\right|=6-\left|3-2x\right|\)

\(2x-3=6-3-2x\)

\(2x-3=x\)

\(-2x=3\)

\(x=\frac{-3}{2}\)

d)  \(\left|3x-2\right|-\left|6-9x\right|=-\left|-16\right|\)

\(3x-2-6-9x=-16\)

\(3x-8-9x=-16\)

\(-6x-8=-16\)

\(-6x=-8\)

\(\Rightarrow x=\frac{8}{6}\)

\(\)

hình như sai rồi đó bạn ạ

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) * ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34-0\\2x=0+6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

\(\left(2019-x\right)\left(3x-12\right)=0\)

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=0+12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy,` x \in {2019; 4}`

^{p/s: Bài này hnhu mk làm r mà ạ?}

\(6^{5x+2}=36^{3x-4}\)

\(\Rightarrow6^{5x+2}=6^{2.\left(3x-4\right)}\)

\(\Rightarrow5x+2=2\left(3x-4\right)\)

\(\Rightarrow5x+2=6x-8\)

\(\Rightarrow-x=-10\)

\(\Rightarrow x=10\)

Vậy x = 10

\(6^{5x+2}=36^{3x-4}\)

\(6^{5x+2}=6^{2.\left(3x-4\right)}\)

\(\Rightarrow5x+2=6x-8\)

\(2+8=6x-5x\Leftrightarrow x=10\)

Chúc bạn học tốt!!!

\(6^{5x+2}=36^{3x-4}\)

\(\Leftrightarrow6^{5x+2}=\left(6^2\right)^{3x-4}\)\(\Leftrightarrow6^{5x+2}=6^{2\left(3x-4\right)}\)

\(\Leftrightarrow6^{5x+2}=6^{6x-8}\)\(\Leftrightarrow5x+2=6x-8\)

\(\Leftrightarrow5x-6x=-2-8\)

\(\Leftrightarrow-x=-10\Leftrightarrow x=10\)

Vậy \(x=10\)

(x²-3x+2)(x²-9x+20) đề thiếu vp

cac cap (x;y) lần lượt là : (1;-16) ; (19;2) ; (-1;22) ; (-19;4)  cách làm hơi khó viết nên mình ko tiện viết ra bạn thông cảm nha

7 + 6 = 113

7 + 6 = 113 nha

10000000000000000000000000% luôn

minh nhanh day 

7 + 6 = 113

= 32 nha

32

32