86 : [2 . (2x - 1) ^2 -7 ] + 4^2 = 2 . 3^2
86 : [2 . (2x - 1) ^2 -7 ] + 4^2 = 2 . 3^2
\(86:\left[2\left(2x-1\right)^2-7\right]+4^2=2.3^2\)
\(\Rightarrow86:\left[2\left(2x-1\right)^2-7\right]=18-16=2\)
\(2\left(2x-1\right)^2-7=86:2=43\)
\(\Rightarrow\left(2x-1\right)^2=25\)
\(\Rightarrow\orbr{\begin{cases}2x-1=5\Leftrightarrow x=3\\2x-1=-5\Leftrightarrow x=-2\end{cases}}\)
Tìm x thuộc Z biết:
86 : [ 2 . ( 2x - 1 )^2 - 7 ] + 4^2 = 2 . 3^2
\(86:\left[2.\left(2x-1\right)^2-7\right]+4^2=2.3^2\)
\(86:\left[2.\left(2x-1\right)^2-7\right]+16=2.9\)
\(86:\left[2.\left(2x-1\right)^2-7\right]=2\)
\(2.\left(2x-1\right)^2-7=43\)
\(2.\left(2x-1\right)^2=50\)
\(\left(2x+1\right)^2=25=5^2=\left(-5\right)^2\)
\(\Rightarrow\orbr{\begin{cases}2x+1=5\\2x+1=-5\end{cases}\Rightarrow\orbr{\begin{cases}2x=4\\2x=-6\end{cases}\Rightarrow}\orbr{\begin{cases}x=2\\x=-3\end{cases}}}\)
86:[2.(2x-1)2-7]+42=2.32
mình là hs lớp 5
sorry bạn nha
sorry!!!!!!!!!!!!!!!!!!!!!!
86:[2.(2x-1)2-7]+42=2.32
\(\frac{86}{\left[2.\left(2x-1\right)^2-7\right]}+4^2=2.3^2\Leftrightarrow\frac{86}{\left[2.\left(2x-1\right)^2-7\right]}=2.9-4^2=2\)
\(\frac{86}{2}=\left[2.\left(2x-1\right)^2-7\right]=2.\left(2x-1\right)^2-7\)
\(43=2.\left(2x-1\right)^2-7\Leftrightarrow2.\left(2x-1\right)^2=43+7=50\)
\(\left(2x-1\right)^2=\frac{50}{2}=25=5^2\Rightarrow!2x-1!=5\)
\(\orbr{\begin{cases}2x-1=-5\\2x-1=5\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-4\\2x=6\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=3\end{cases}}}}\)
x=3 hoặc x=-2, cứ tính từ từ rồi chuyển vế.
86:[2.(2x-1)2-7]+42=2.32
86 : [2 . (2x - 1)2 - 7] +42=2.32
86 : [2.(2x-1)2-7] + 16 = 2.9
86 : [2.(2x-1)2-7] +16 = 18
86 : [2.(2x-1)2-7]=18-16
86 : [2.(2x-1)2-7]=2
2.(2x-1)2-7=86:2
2.(2x-1)2-7=43
2.(2x-1)2=43+7
2.(2x-1)2=50
(2x-1)2=50:2
(2x-1)2=25
(2x-1)2=52
=>2x-1=5
2x=5+1
2x=6
x=6:2
x=3
86:(2.(2x-1)2-7)+42=2.32
tìm x thuộc Z biết
a, (/x/ +3 ):5-3 =12
b, 86 : [2.(2x - 1 )2 - 7] +42 = 2.32
a) \(\left(\left|x\right|+3\right):5-3=12\Leftrightarrow\left|x\right|+3=45\Leftrightarrow\orbr{\begin{cases}x=42\\x=-42\end{cases}}\)
b) \(86:\left[2\left(2x-1\right)^2-7\right]+4^2=2\cdot3^2\Leftrightarrow2\left(2x-1\right)^2-7=43\Leftrightarrow\left(2x-1\right)^2=25\Leftrightarrow\orbr{\begin{cases}2x-1=-5\\2x-1=5\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-2\\x=3\end{cases}}\)
a) \(\left(\left|x\right|+3\right)\div5-3=12\)
\(\left(\left|x\right|+3\right)\div5=12+3\)
\(\left(\left|x\right|+3\right)\div5=15\)
\(\left|x\right|+3=15.5\)
\(\left|x\right|+3=75\)
\(\left|x\right|=75-3\)
\(\left|x\right|=72\)
\(\Rightarrow\orbr{\begin{cases}x=72\\x=-72\end{cases}}\)
Vậy \(x\in\left\{72;-72\right\}\)
b) \(86\div\left[2,\left(2x-1\right)^2-7\right]+4^2=2.3^2\)
\(86\div\left[2.\left(2x-1\right)^2-7\right]+16=18\)
\(86\div\left[2.\left(2x-1\right)^2-7\right]=18-16\)
\(86\div\left[2.\left(2x-1\right)^2-7\right]=2\)
\(2.\left(2x-1\right)^2-7=86\div2\)
\(2.\left(2x-1\right)^2-7=43\)
\(2.\left(2x-1\right)^2=43+7\)
\(2.\left(2x-1\right)^2=50\)
\(\left(2x-1\right)^2=50\div2\)
\(\left(2x-1\right)^2=25\)
\(\left(2x-1\right)^2=5^2\)
\(\Rightarrow2x-1=5\)
\(2x=5+1\)
\(2x=6\)
\(x=6\div2\)
\(x=3\)
a, (|x| +3):5-3=12
(|x|+3):5=15
|x|+3=3
|x|=0
=>x=0
a. ( | x | + 3 ) . 15 - 5 = 70
b. 86 : [ 2. (2x -1)2 - 7 ] + 42 = 2 .32
- Tìm x
Bài làm
a. ( | x | + 3 ) . 15 - 5 = 70
( | x | + 3 ) . 15 = 70 + 5
( | x | + 3 ) . 15 = 75
| x | + 3 = 75 : 15
| x | + 3 = 5
| x | = 5 - 3
suy ra | x | = 2 hoặc | x | = -2
vì |2| = 2 ; |-2| = 2
b.86 : [ 2 . ( 2x - 1 )2 - 7 ] + 42 = 2 . 32
86 : [ 2 . ( 2x - 1 )2 - 7 ] + 16 = 2 . 9
86 : [ 2 . ( 2x - 1 )2 - 7 ] + 16 = 18
86 : [ 2 . ( 2x - 1 )2 - 7 ] = 18 - 16
86 : [ 2 . ( 2x - 1 )2 - 7 ] = 2
[ 2 . ( 2x - 1 )2 - 7 ] = 86 : 2
2 . ( 2x - 1 )2 - 7 = 43
2 . ( 2x - 1 ) 2 = 43 + 7
2 . ( 2x - 1 ) 2 = 50
( 2x - 1 ) 2 = 50 : 2
( 2x - 1 ) 2 = 25
( 2x - 1 ) 2 = 52
suy ra ( 2.3 - 1 ) 2 = 52 = 25
a) x/3=y/4=z/5 và 2x + 3y + 5z = 86
b) x/3=y/4; y/6=z/8 và 3x - 2y - z = 13
c) x/3=y/7=z/2 và 2x^2 + y^2+3z^2 = 316