\(1+\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+...+\frac{1}{x}.\left(1+2+3+...+x\right)=115\)

\(\Rightarrow1.\left(\frac{1.2}{2}\right)+\frac{1}{2}.\left(\frac{2.3}{2}\right)+\frac{1}{3}.\left(\frac{3.4}{2}\right)+....+\frac{1}{x}.\left[\frac{x\left(x+1\right)}{2}\right]=115\)

\(\Rightarrow\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+....+\frac{x+1}{2}=115\Rightarrow2+3+...+\left(x+1\right)=230\)

\(\frac{\Rightarrow\left[\frac{\left(x+1-2\right)}{1}+1\right].\left(x+1+2\right)}{2}=\frac{x.\left(x+3\right)}{2}=230\Rightarrow x.\left(x+3\right)=460\)

vì x và x+3 là 2 số tự nhiên cách nhau 3 đơn vị => \(x.\left(x+3\right)=460=20.23\Rightarrow x=20\)

Vậy x=20

Mik ko hieu giai ki hon dc ko

 20 . 2^x + 1 = 10.4^2 + 1 

 20 . 2^x + 1 = 10 . 16 + 1

20 . 2^x + 1 = 161

20 . 2^x = 161 - 1

20 . 2^x = 160

2^x = 8

2^x = 2^3

=> x = 3

Ban co giai dc phan 2 ko ?

( 4 - x : 2 )^3 - 1 = 2 . ( 2^3 - 5 : 2^0 )

( 4 - x : 2 )^3 - 1 = 2 . ( 8 - 5 : 1 )

( 4 - x : 2 )^3 - 1 = 2 . 3

( 4 - x : 2 )^3 - 1 = 6

( 4 - x : 2 )^3  = 7

=> ko tìm đc x

a) \(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)

\(\Rightarrow\frac{3}{2}x-\frac{1}{3}x=-\frac{1}{4}+\frac{2}{5}\)

\(\frac{7}{6}x=\frac{3}{20}\Rightarrow x=\frac{9}{70}\)

b) \(-5^{\frac{1}{2}x+1}=\frac{3}{4}-\frac{7}{6}\)

\(-5^{\frac{1}{2}x}.\left(-5\right)=-\frac{5}{12}\)

\(-5^{\frac{1}{2}x}=\frac{1}{12}\)

mà -5^1/2x mang giá trị âm

1/12 có giá trị dương

=> không tìm được x

c) \(\frac{2x-2}{3}=\frac{7x+3}{2-1}\)

\(\frac{2x-2}{3}=7x+3=\frac{21x+9}{3}\)

=> 2x - 2 = 21x + 9

=> 2x - 21x = 9 + 2

-19x = 11

x = -11/19

phần d bn lm như phần a nha