(x+4).(23-x)=0
a) 37 ( x - 15 ) = 0
b) ( x - 17 ) . 23 = 23
c) ( x - 2 ) ( x -4 ) = 0
d) ( x + 12 ) . 53 = 1060
e) 4 . ( x - 50 ) + 160
f) ( 17 -x ) : 6 = 2
a) 37 (x-15)=0
x-15 =0
x =15
b) (x-17).23=23
x-17 =1
x =1+17
x =18
c) (x-2) (x-4)=0
Th1: x-2=0
x =0+2
x =2
TH2: x-4=0
x =0+4
x =4
Vậy x=2 hoặc x=4
d) (x+12) . 53=1060
x+12 =1060:53
x+12 =20
x =20-12
x =8
e) 4 . (x-50) = 160
x-50 =160:4
x-50 =40
x =40+50
x =90
f) (17-x) : 6=2
17-x =2 . 6
17-x =12
x =17-12
x =5.
Chúc học tốt!
b) 1500.(x – 7) = 0
c) (2.x – 4).(48 – 12.x) = 0
d) (x + 12).(x – 1) =0
Bài 2: Tìm x biết:
a) 128- 3(x+ 4) = 23
b) [(14x+ 26). 3+ 55]: 5= 35
d) 720: [41- (2x- 5)]= 23. 5
b. 1500(x-7)=0
x-7=0
x=7
c. (2x-4)(48-12x)=0
2x-4=0 hoặc 48-12x=0
x=2 hoặc x=4
d. (x+12)(x-1)=0
x+12=0 hoặc x-1=0
x=-12 hoặc x=1
bài 2 :
a . 128-3(x+4)=23
3(x+4)=105
x+4=35
x=31
b. [(14X+26).3+55]:5=35
(14x+26).3+55=175
(14x+26).3=120
14x+26=40
14x=14
x=1
d. 720:[41-(2X-5)]=23.5
41-(2x-5)=720:(23.5)
41-(2x-5)=144/23
2x-5=799/23
2x=914/23
x=457/23
b, 1500.(x – 7) = 0
<=>1500x-10500=0
<=>1500x=10500
<=>x=7
Vậy x=7
c,(2.x – 4).(48 – 12.x) = 0
\(\Leftrightarrow\)\(\left\{{}\begin{matrix}2x-4=0\\48-12x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\12x=48\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
Vậy x=2 hoặc x=4
d, (x + 12).(x – 1) =0
\(\Leftrightarrow\left\{{}\begin{matrix}x+12=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-12\\x=1\end{matrix}\right.\)
Vậy x=-12 hoặc x=1
Bài 2:
a) 128- 3(x+ 4) = 23
\(\Leftrightarrow\)128-(3x+12)=23
\(\Leftrightarrow\)128-3x-12=23
\(\Leftrightarrow\)116-3x=23
\(\Leftrightarrow\)3x=116-23
\(\Leftrightarrow\)3x=93
\(\Leftrightarrow\)x=31
Vậy x=31
b) [(14x+ 26). 3+ 55]: 5= 35
\(\Leftrightarrow\)(14x+ 26). 3+ 55=175
\(\Leftrightarrow\)42x+78+55=175
\(\Leftrightarrow\)42x+133=175
\(\Leftrightarrow\)42x=175-133
\(\Leftrightarrow\)42x=42
\(\Leftrightarrow\)x=1
Vậy x=1
d, 720: [41- (2x- 5)]= 23. 5
\(\Leftrightarrow\)720: 41- (2x- 5)=115
\(\Leftrightarrow\)41-(2x- 5)=720:115
\(\Leftrightarrow\)41-(2x- 5)=\(\dfrac{144}{23}\)
\(\Leftrightarrow\)2x-5=\(\dfrac{799}{23}\)
\(\Leftrightarrow\)2x=\(\dfrac{914}{23}\)
\(\Leftrightarrow\)x=\(\dfrac{457}{23}\)
Vậy x=\(\dfrac{457}{23}\)
a) x.0=0
b) 23(x-4)=23
c) 12x+ 40= 76
Lê Hoàng Khả Nhi
a, x.0 = 0
=> x = 0
b, 23( x -4) = 23
=> x -4 = 23/23
=> x -4 = 1
=> x = 1 + 4
=> x = 5
c, 12x + 40 = 76
=> 12x = 76 -40
=> 12x = 36
=> x = 36/12
=> x = 3
a) \(x.0=0\)
\(=>x\)có vô số nghiệm
b) \(23\left(x-4\right)=23\)
\(23x-92=23\)
\(23x=115\)
\(x=5\)
vậy \(x=5\)
c) \(12x+40=76\)
\(12x=36\)
\(x=3\)
vậy \(x=3\)
a) x.0=0
=> x \(\varepsilon\)N
b) 23(x-4)=23
x-4 = 23-23
x-4 =0
x = 0+4
x = 4
c) 12x +40=76
12x = 76-40
12x = 36
x = 36:12
x = 3
Ung ho mk nha cac bn!
(x+4).(23-x)=0
ta co : (x+4).(23-x)=0
Ta chia bài trên ra làm 2 fan là x+4=4 va 23-x=0
TH1 :
x+4=0
x = 0-4
x =-4
TH2:
23-x=0
x = 23-0
x =23
Vay x=-4 hoac 23
(x+4).(23-x)=0
(x+4).(23-x)=0
=>x+4=0 hoặc 23-x=0
=>x=-4 hoặc x=23
( x + 4 ) . ( 23 - x ) = 0 tìm x
2 TH
TH1 : x + 4 = 0 => x = -4
TH2 : 23 - x = 0 => x = 23
vậy x = -4 và x = 23
a)(x + 5) . (x – 4) = 0
b) (x – 1) . (x - 3) = 0
c) (3 – x) . ( x – 3) = 0
d) x.(x + 1) = 0
e) 4 – (27 – 3) = x – (13 – 4)
f) 8 – (x – 10) = 23 – (- 4 +12)
A)(x+5)(x-4)=0
=)x+5=0 hoặc x-4=0
=)x=-5 hoặc x=4
Nếu đề là tìm x thì làm như sau :
a) (x+5).(x-4)=0
\(\Rightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-5\\x=4\end{cases}}\)
Vậy x\(\in\){-5;4}
Câu b, c và d tương tự
e) 4-(27-3)=x-(13-4)
x-(13-4)=-20
x-9=-20
x=-20+9
x=-11
Vậy x=-11
f) 8-(x-10)=23-(-4+12)
8-(x-10)=15
x-10=8-15
x-10=-7
x=-7+10
x=3
Vậy x=3.
Lần sau bạn nhớ ghi yêu cầu đề bài nhé!
tìm x
(x+4).(23-x)=0
(x+4).(23-x)=0
=>Hoặc x+4 =0 =>x=-4
Hoặc 23-x=0 =.x=23
Vậy x=-4 ; x=23
(x+4). (x-23)=0
tim x=
(x+4)(x-23)=0
=>x+4=0 hoặc x-23=0
x+4= 0 => x =-4
x-23=0=>x=-23