a) 13 . 58 . 4 + 32 . 26 . 2 + 52 . 10                  b) 53 . 51 + 4 + 53 . 49 + 91 + 53

= 52 . 58 + 32 . 52 + 52 . 10                              = 53 . 55 + 53 . 145 + 53 . 1

= 52. ( 58 + 32 + 10 )                                        = 53 . ( 55 + 145 + 1 )

= 52 . 100                                                          = 53 . 201

= 52000                                                             =  10653

 ~ Chúc bn hok tốt ~

câu b có đúng ko vậyNguyễn Thanh Vân

\(3^2\left(x+4\right)-5^2=5\cdot2^2\\ 9\left(x+4\right)-25=20\\ 9\left(x+4\right)=20+25\\ 9\left(x+4\right)=45\\ x+4=45:9\\ x+4=5\\ x=5-4\\ x=1\)

\(\dfrac{2^2}{1\times3}\times\dfrac{3^2}{2.4}\times\dfrac{4^2}{3.5}\times\dfrac{5^2}{4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.3.2.4.3.5.4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.2.3.3.4.4.5.2.3}=\dfrac{2^2.3^2.4^2.5^2}{3^3.2^2.4^2.5.1}=\dfrac{5}{3.1}=\dfrac{5}{3}\)

\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot\dfrac{5^2}{4.6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot2\cdot4^2\cdot4^2\cdot5\cdot6}\\ =\dfrac{2\cdot5}{6}=\dfrac{5}{3}\)

Ta có : \(\frac{1}{32}+\frac{1}{42}+\frac{1}{52}+...+\frac{1}{102}< \frac{1}{32}+\frac{1}{32}+\frac{1}{32}+...+\frac{1}{32}\)   (8 số hạng)

\(\Rightarrow\frac{1}{32}+\frac{1}{42}+\frac{1}{52}+...+\frac{1}{102}< \frac{1}{32}.8=\frac{1}{4}< \frac{1}{2}\)

\(\Rightarrow\frac{1}{32}+\frac{1}{42}+\frac{1}{52}+...+\frac{1}{102}< \frac{1}{2}\left(đpcm\right)\)

\(A=\frac{1}{32}+\frac{1}{42}+...+\frac{1}{102}< \frac{1}{32}+\frac{1}{32}+...+\frac{1}{32}=\frac{8}{32}< \frac{16}{32}=\frac{1}{2}\)

Vậy \(A< \frac{1}{2}\)

\(A=\dfrac{7^5}{7+7^2+7^3+7^4}=\dfrac{7^5}{\left(7+7^4\right)+\left(7^2+7^3\right)}=\dfrac{7^5}{7^5+7^5}=7^5\)

\(B=\dfrac{5^5}{5+5^2+5^3+5^4}=\dfrac{5^5}{\left(5+5^4\right)+\left(5^2+5^3\right)}=\dfrac{5^5}{5^5+5^5}=5^5\)

Vì 7 > 5 nên \(7^5>5^5\)

Vậy A > B

(Nhớ cho mik một tick nha cảm ơn bạn nhìu :3)

a) 125.5.(-13).2.8

= ( 125.2) . ( 5.8) . ( -13)

= 250.40.(-13)

=10000.(-13)

= -130000

b) 400-(-71)+176-(175-29)

= 400+71+176- 175+29

= 400+ (71+29) +(176-175)

= 400 +100+1

=501

d) (-2020)+2000+2020+(-2019)

= (-2020+2020)+( -2019+2000)

= 0+ (-19)

= -19

100-3(x-1)²=52

3(x-1)²=100-52

3(x-1)²=48

(x-1)²=48:3

(x-1)²=16

(x-1)²=4²=(-4)²

=> x-1=4 hoặc x-1=-4

TH1: 

x-1=4

x=4+1

x=5

TH2:

x-1=-4

x=-4+1

x=-3

Vậy x=5 hoặc x=-3

100 - 3(x - 1)² = 52

<=> 3(x - 1)² = 48

<=> (x - 1)² = 16

<=> (x - 1)² = 4² = (-4)²

<=> \(\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}}\)

<=> \(\orbr{\begin{cases}x=5\\x=-3\end{cases}}\)

\(100-3\left(x-1\right)^2=52\)

\(3\left(x-1\right)^2=100-52\)

\(3\left(x-1\right)^2=48\)

\(\left(x-1\right)^2=16\)

\(x-1=4^2\)

\(\Rightarrow\orbr{\begin{cases}x-1=4\\x-1=-4\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-3\end{cases}}\)

Vậy x = 5 hoặc x = -3 

Study well 

đi mà, mọi người xin hãy giúp em

mọi người ơi giúp mk đi mà   -_-" ~

=90 x 46 + 89 x 53 + 88

=4140+4717+88

=8857+88

=8945