\(A=\left(3\sqrt{2}+\sqrt{6}\right)\sqrt{\frac{9-2.3\sqrt{3}+3}{2}}=\frac{\sqrt{2}\left(3+\sqrt{3}\right)}{\sqrt{2}}.\sqrt{\left(3-\sqrt{3}\right)^2}=\left(3+\sqrt{3}\right)\left(3-\sqrt{3}\right)=9-3=6\)

a) \(5\frac{3}{7}+\frac{7}{29}-0,7-\frac{3}{17}+\frac{22}{19}-2,3\)

\(=\frac{38}{7}+\frac{7}{29}-\frac{7}{10}-\frac{3}{17}+\frac{22}{19}-\frac{23}{10}\)

\(=\left(-\frac{7}{10}-\frac{23}{10}\right)+\frac{38}{7}+\frac{7}{29}-\frac{3}{17}+\frac{22}{19}\)

\(=\left(-3\right)+\frac{38}{7}+\frac{7}{29}-\frac{3}{17}+\frac{22}{19}\)

\(=\frac{17}{7}+\frac{7}{29}-\frac{3}{17}+\frac{22}{19}\)

\(=\frac{8605}{3451}+\frac{22}{19}\)

\(\approx4.\)

d) \(\sqrt{0,36}-\sqrt{0,81}+\sqrt{0,49}\)

\(=0,6-0,9+0,7\)

\(=\left(-0,3\right)+0,7\)

\(=0,4.\)

Chúc bạn học tốt!

\(\sqrt{50}-3\sqrt{98}+2\sqrt{8}+3\sqrt{32}-5\sqrt{18}\)

\(=5\sqrt{2}-21\sqrt{2}+4\sqrt{2}+12\sqrt{2}-15\sqrt{12}\)

\(=-15\sqrt{2}\)

\(\frac{5}{a}+\frac{3}{a+4}=\frac{5.\left(a+4\right)+3a}{a.\left(a+4\right)}=\frac{5a+20+3a}{a^2+4a}\)

                          \(=\frac{8a+20}{a^2+4a}\)

\(\frac{4}{c-5}+\frac{2}{2c+3}\) \(=\frac{4\left(2c+3\right)+2\left(c-5\right)}{\left(c-5\right)\left(2c+3\right)}\)

                                        \(=\frac{8c+12+2c-10}{2c^2+3c-10c-15}\)

                                         \(=\frac{10c-2}{2c^2-7c-15}\)

câu còn lại tương tự nha

mk phải đi học rồi

\(\frac{2^{4+6}}{2^{5.2}}-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}=\frac{2^{10}}{2^{10}}-\frac{2^5.3^3.5^3}{2^5.3^3.5^2}=1-5=-4\)

bn hoc gioi thiet

câu này dễ chưa từng thấy luôn

\(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\)

=\(\sqrt{4}.\sqrt{3}+2\sqrt{9}.\sqrt{3}+3\sqrt{25}.\sqrt{3}-9\sqrt{16}.\sqrt{3}\)

=\(2\sqrt{3}+6\sqrt{3}+15\sqrt{3}-36\sqrt{3}\)

=\(\left(2+6+15-36\right)\sqrt{3}\)

=\(-13\sqrt{3}\)