101²

= (100 + 1)² 
= 100² + 2.100.1 + 1² 
= 10000 + 200 + 1 
= 10201 

a. 101² = 10201

b. 97 x 103 = 9991

c. 77² + 23²  + 77 x 46

= 5929 + 529 + 77 x 46

= 5929 + 529 + 3542

= 6458 + 3542

= 10000

d. 105² - 5 

= 11025 - 5

= 11020

a)101² =10201

b)97x103=9991

c)77² +23² +77x46=3136564

d)105² -5=11020

a) 101²

= (100 + 1)²

= 100² + 2.100 + 1

= 10000 + 200 + 1

= 10201

b) 97.103

= (100 - 3)(100 + 3)

= 100² - 3²

= 10000 - 9

= 9991

c) 77² + 23² + 77.46

= 77² + 2.77.23 + 23²

= (77 + 23)²

= 100²

= 10000

d) 105² - 5²

= (105 - 5)(105 + 5)

= 100.110

= 11000

77² + 23² + 77.46 = 77² + 23² + 2.77.23

= (77 + 23)² = 100² = 10000

a.\(^{101^2}\)= 10201

b.97 x 103 = 9991

c.\(^{77^2}+^{23^2}+77\times46\)=10000

d.\(^{105^5}-^{5^2}\)= 12762815600

a)  101² = (100 - 1)² = 100² - 200 + 1 = 10000 - 200 + 1 = 9801

b)  97 x 103 = (100 - 3)(100 + 3) = 100² - 3² = 10000 - 9 = 9991

c) 77² + 23² + 77*46 = (77 + 23)² = 100² = 10000

d) 105² - 5² = (105 + 5)(105 - 5) = 110 * 100 = 11000

Tìm x biết:

a. (x-2)²-(x-3)(x+3)=6

b. 4(x-3)²-(2x-1)(2x+1)=10

\(a.101^2-99^2=\left(101+99\right)\left(101-99\right)=200.2=400\)

\(b.98.102=98.\left(100+2\right)=9800+196=9996\)

\(c,77^2+23^2+77.46=77^2+23^2+2.77.23=\left(77+23\right)^2=100^2=10000\)

A = 2/1*5 + 2/5*9 + ... + 2/101*105

   = 1/2(4/1*5 + 4/5*9 + ... + 4/101*105)

   = 1/2(1 - 1/5 + 1/5 - 1/9 + ... + 1/101 - 1/105)

   = 1/2(1 - 1/105)

   = 1/2 * 104/105 = 52/105

Sửa câu b. Phân số thứ 2 phải là 4/5*8

B = 4/2*5 + 4/5*8 + ... + 4/47*50

   = 4/3(3/2*5 + 3/5*8 + ... + 3/47*50)

   = 4/3(1/2 - 1/5 + 1/5 - 1/8 + ... + 1/47 - 1/50)

   = 4/3(1/2 - 1/50)

   = 4/3 * 24/50 = 16/25

101² = (100 + 1)² = 100² + 2.100.1 + 1² = 10000 + 200 + 1 = 10201

97 . 103 = (100 - 3)(100 + 3) = 100² - 3² = 10000 - 9 = 9991

77² + 2. 23. 77 + 23² = (77 + 23)² = 100² = 10000

105² - 5² = (105 - 5)(105 + 5) = 100 . 110 = 11000

tick nha

a) \(101^2\)

\(=\left(100+1\right)^2\)

\(=100^2+2.100.1+1^2\)

\(=10000+200+1\)

\(=10200+1\)

\(=10201\)

b) \(97.103\)

\(=\left(100-3\right).\left(100+3\right)\)

\(=100^2-3^2\)

\(=10000-9\)

\(=9991\)

c) \(77^2+23^2+77.46\)

\(=77^2+77.46+23^2\)

\(=77^2+2.77.23+23^2\)

\(=\left(77+23\right)^2\)

\(=100^2\)

\(=10000\)

d) \(105^2-5^2\)

\(=\left(105-5\right)\left(105+5\right)\)

\(=100.110\)

\(=11000\)

lâu lắm r moi lên h24, tớ giúp bn nhé:

*101² = (100+1)² = 10⁴ + 2.100.1 +1² = 10201

*97.103= (100-3)(100+3) = 10² - 3² = 9991

* = 77² + 2.77.23 + 23² = (77+23)² = 10⁴