a) (4600 + 6400) -7.x=3839

      11000  - 7.x=3839

                    7.x=11000-3839

                   7.x=7161

                      x=7161:7

                      x=1023

b) (8x-14) :2-2= 341:31

   (8x-14):2-2=11

(8x-14):2= 11+2

(8x-14):2=13

8x-14=13.2

8x-14=26

8x=26+14

8x=40

x=40:8

x=5

a) x=1023

b)x=5

c)x=38

a) \(\left(4600+6400\right)-7x=3839\Rightarrow11000-7x=3839\)
                                                             \(\Rightarrow-7x=3839-11000\)
                                                              \(\Rightarrow7x=7161\Rightarrow x=1023\)

\(\left(6400+4600\right)-7y=3839\)

\(11000-7y=3839\)

\(7y=11000-3839\)

\(7y=7161\)

\(y=7161:7\)

\(y=1023\)

Vậy \(y=1023\)

Tham khảo nhé~

( 6400 + 4600 ) - 7y = 3839

=> 110000 - 7y = 3839

=> 7y = 110000 - 3839

=> 7y = 7161

=> y = 7161 : 7

=> y = 1023

Vậy y = 1023

Học tốt #

(6400+4600)-7y=3839

7y                   = (6400+4600)-3839

7y                   = 11000 -3839

7y                   =      7161

 y                    =       7161:7

 y                    =       1023

học tốt nhoa!!!

a)(4600 + 6400) - 7.x = 3839

11000-7x=3839

7x=7161

x=1023

Vậy x=1023

b)[(8x - 14 ) : 2 - 2 ]. 31 = 341

(8x - 14 ) : 2 - 2=11

(8x - 14 ) : 2=13

8x - 14 =26

8x=40

x=5

Vậy x=5

c)2.(x - 3) - x = 4.2^3

2.(x - 3) - x=32

2x-6-x=32

x-6=32

x=38

Vậy x=38

Bài 1 : Tìm x

a, ( 4600 + 6400 ) - 7.x = 3839

11000 - 7.x = 3839

7.x = 11000 - 3839

7.x = 7161

x = 7161: 7

x = 1023

b, [ ( 8x - 14 ) : 2 - 2 ] . 31 = 341

( 8x -14 ) : 2 -2 = 11

( 8x -14 ) : 2 = 13

8x -14 = 26

8x = 40

x = 5

c, 2. ( x -3 ) - x = 4. 2³

2x - 6 - x = 32

x - 6 = 32

x = 38

a)1023

b)5

c)38

a) 219 - 7(y + 1) = 100

=> 7(y + 1) = 119

=> y + 1 = 19

=> y = 18

vậy_

a) 219 - 7(y+1) = 100

7(y+1) = 119

y+1 = 17

y = 16

các bài cn lại lm tương tự nha!

a, 219-7(y+1)=100

7(y+1)=219-100

7(y+1)=119

y+1=119:7

y+1=17

y=17-1

y=16

Tổng là:

6400+4600=11000

Đáp số : 11000

6400+4600=11000

6400+ 4600 = 110000

\(\left[\left(4.4+1\right)\sqrt{\frac{3}{2}.2}\right].x=\sqrt{6400}+\sqrt{6400}.2\)

\(\Rightarrow\left[17.\sqrt{3}\right].x=80+80.2\)

\(\Rightarrow17\sqrt{3}.x=240\)

\(\Rightarrow x=\frac{240}{17\sqrt{3}}\)

(2600+6400)-3x=1200

10 000-3x=1200

3x=9000-1200

3x=7 800

x=7800/3

x=2600

(2600+6400)-3x=1200

<=>9000-3x=1200

<=>3x=9000-1200

<=>3x=7800

<=>x=2600

[(6.x-72):2-84].28=5628

(2600 + 6400) – 3x = 1200

9000 – 3x = 1200

3x = 9000 - 1200

3x = 7800

x = 7800 : 3

x = 2600

Vậy x = 2600