TH1 :2x-3=0

=>2x=3

=>x\(\frac{3}{2}\)

TH2: 6-2x=0

=>2x=6

=>x=3

em moi hoc lop 5 thoi nen thong cam nhe  tri nhan bao 

Còn nữa: Tính x2011

Ta có:

x₁ + x₂ + x₃ + ... + x_{2008 +} x₂₀₀₉ + x₂₀₁₀

= (x₁ + x₂ + x₃) + ... + (x_{2008 +} x₂₀₀₉ + x₂₀₁₀)

= 1 + 1 + 1 + ... + 1(670 số 1)

= 670

\(\Rightarrow\) x₁ + x₂ + x₃ + ... + x_{2009 +} x₂₀₁₀ + x₂₀₁₁ = 670 + x₂₀₁₁ = 0

\(\Rightarrow\) x₂₀₁₁ = -670

M = x³ + x²y - 2x² - xy - y² + 3y + x + 2017

M = (x³ + x²y - 2x²) - (xy + y² - 2y) + (x + y - 2) + 2019

M = x². (x + y - 2) - y(x + y - 2) + (x + y - 2) + 2019 = 2019

\(M = x^3 + x^2y - 2x^2 - xy - y^2 + 3y + x + 2017.\)

\(M=(x^3+x^2y-2x^2)-(xy-y^2+2y)+(x+y-2)+2019\)

\(M=x^2.(x+y-2)-y.(x-y+2)+(x+y-2)+2019\)

\(M=x^2.0-y.0+0+2019\)

\(M=0-0+0+2019\)

\(M=2019\)

$M={}^{}+{}^{}y-2{}^{}-xy-{}^{}+3y+x+2017.$

$M=({}^{}+{}^{}y-2{}^{})-(xy-{}^{}+2y)+(x+y-2)+2019$

$M={}^{}.(x+y-2)-y.(x-y+2)+(x+y-2)+2019$

$M={}^{}.0-y.0+0+2019$

vì \(x^4+2x^2+1=\left(x^2+1\right)^2\) mà \(x^2\ge0\Rightarrow x^2+1>0\Rightarrow\left(x^2+1\right)^2>0\)với mọi x.Nên x-3=0 .Từ đó suy ra x=3

(2x-3)(x+\(\frac{1}{4}\))=0

\(\Leftrightarrow\orbr{\begin{cases}2x-3=0\\x+\frac{1}{4}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-1}{4}\end{cases}}}\)

Bài làm

Ta có: \(\left(2x-3\right)\left(x+\frac{1}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-3=0\\x+\frac{1}{4}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{1}{4}\end{cases}}}\)

Vậy x = 3/2 hoặc x = -1/4 

\(\left(2x-3\right)\left(x+\frac{1}{4}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-3=0\\x+\frac{1}{4}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{1}{4}\end{cases}}\)

Ta có \(\frac{2.3.4+2.3.4.2018+2.3.4.2019-2.3.4.2020}{5.6.7+5.6.7.2018+5.6.7.2019-5.6.7.2020}\)

\(=\frac{2.3.4\left(1+2018+2019-2020\right)}{5.6.7.\left(1+2018+2019-2020\right)}=\frac{2.3.4}{5.6.7}=\frac{4}{35}\)

(2x+1)+(3-x)=0

=>2x+1=-3+x

=>2x+1-x=-3

=>x+1=-3

=>x=-3-1=-4

Vậy x=-4

a)(2x+1)+(3-x)=0

 2x+1+3-x=0

x+4=0

x=-4

vậy x=-4

(2x+1)+(3-x)=0

=>x = -4