kết quả là 6596 nhá 
Tick mình nha

5.2^3x+1+2.2^3x+2 - 16 = 0

=> 5.2^3x.2+2.2^3x.2² =16

=> 2^3x ( 10 + 8)   = 16

=> 2^3x  = 16:18 = 8/9

=> x khong co gia tri

Vì \(\left(x+2y-3\right)^{2016}\ge0;\left|2x+3y-5\right|\ge0\forall x;y\)

\(\Rightarrow\left(x+2y-3\right)^{2016}+\left|2x+3y-5\right|\ge0\forall x;y\)

Mà \(\left(x+2y-3\right)^{2016}+\left|2x+3y-5\right|=0\) \(\Leftrightarrow\left(x+2y-3\right)^{2016}=0\) ; \(\left|2x+3y-5\right|=0\)

\(\Rightarrow x+2y-3=0;2x+3y-5=0\)

\(\Leftrightarrow x+2y=3;2x+3y=5\)

\(\Rightarrow x=3-2y\)

\(\Rightarrow2\left(3-2y\right)+3y=5\Leftrightarrow6-4y+3y=5\Leftrightarrow6-y=5\Rightarrow y=1\)

\(\Rightarrow x=3-2.1=1\)

Vậy \(x=1;y=1\)

\(\Leftrightarrow x+y+z-2\sqrt{x}-2\sqrt{y-1}-2\sqrt{z-2}=0\)

\(\Leftrightarrow\left[\left(\sqrt{x}\right)^2-2.\sqrt{x}.1+1^2\right]+\left[\left(\sqrt{y-1}\right)^2+2.\sqrt{y-1}.1+1^2\right]+\left[\left(\sqrt{z-2}\right)^2+2.\sqrt{z-x}.1+1^2\right]-1+1=0\)

\(\Leftrightarrow\left(\sqrt{x}-1\right)^2+\left(\sqrt{y-1}-1\right)^2+\left(\sqrt{z-2}-1\right)^2=0\)

\(\Leftrightarrow\sqrt{x}-1=0\)

\(\sqrt{y-1}-1=0\)

\(\sqrt{z-2}-1=0\)

\(\Leftrightarrow x=1;y=2;z=3\)

Đề bài sai nhé, từ giả thiết chỉ xác định được \(x+y=0\Rightarrow y=-x\)

\(\Rightarrow A=4x^2-x^2+x^2+15=4x^2+15\) ko rút gọn được

hình như mk nhầm thì phải

\(\Leftrightarrow x\left(x-2\right)\left(x^2+x-6\right)\le0\)

\(\Leftrightarrow x\left(x-2\right)^2\left(x+3\right)\le0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\-3\le x\le0\end{matrix}\right.\)