8-(21-x)=16

21-x=8-16

21-x=-8

x=21-(-8)

x=29

giúp mk nhanh nhé

Cảm ơn bn nhìu nhé

\(\frac{x-2}{4}=-\frac{16}{2-x}\)

\(\Leftrightarrow x-2=-\frac{64}{2-x}\)

\(\Leftrightarrow\left(x-2\right)\left(2-x\right)=-64\)

\(\Leftrightarrow2x-x^2-4+2x=-64\)

\(\Leftrightarrow4x-x^2-4+64=0\)

\(\Leftrightarrow4x-x^2-60=0\)

\(\Leftrightarrow x^2-4x-60=0\)

\(\Leftrightarrow\left(x-10\right)\left(x+6\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-10=0\\x+6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=10\\x=-6\end{cases}}}\)

Vậy \(x\in\left\{10;-6\right\}\)

\(ĐKXĐ:x\ne2\)

Xong giải như bt bạn nhé!!

a) -x - 84=-16-213

   -x-84=-229

    -84+229=x

        145 =x

b) /x+2/= 316

suy ra x+2=316 hoac x+2=-316

  * x+2 = 316

       x = 314

* x+2 =-316

    x   = -318

vay x=314 hoac x=-318

c) /x+7/=15

suy ra x+7=15 hoac x+7=-15

   x+7=15

     x  = 8

   x+7= -15

     x = -22

vay x= 8 hoac x=-22

d) 19-4=/x-1/

   15=/x-1/

suy ra x-1=15 hoac x-1=-15

x-1=15

   x = 16

x-1=-15

  x= -14

vay x=16 hoac x=-14

\(-\left(x+84\right)+213=-16\)

\(=>-x-84+213=-16\)

\(=>-x=-16+84-213=-145\)

\(=>x=145\)

\(\left|x+2\right|=341+\left(-25\right)\)

\(=>\left|x+2\right|=341-25=316\)

\(=>\orbr{\begin{cases}x+2=316\\x+2=-316\end{cases}}\)

\(=>\orbr{\begin{cases}x=314\\x=-318\end{cases}}\)

\(\left|x+7\right|=\left|-15\right|\)

\(=>\left|x+7\right|=15\)

\(=>\orbr{\begin{cases}x=15-7\\x=-15-7\end{cases}}\)

\(=>\orbr{\begin{cases}x=8\\x=-22\end{cases}}\)

\(19-\left|x-1\right|=4\)

\(=>\left|x-1\right|=19-4=15\)

\(=>\orbr{\begin{cases}x-1=15\\x-1=-15\end{cases}}\)

\(=>\orbr{\begin{cases}x=16\\x=-14\end{cases}}\)

để x+16chia hết cho x+1

=>x+1+15chia hết cho x+1

=>15 chia hết cho x+1 

=>x=1 thuôc Ư(15)={15;1;3;5;-15;-1;-3;-5}

vây x thuộc tập hợp {14;4;2;0;-2;-4;-6;-16}

Ta có : x + 16 \(⋮\)x + 1

\(\Rightarrow\)( x + 1 ) + 15 \(⋮\)x + 1

\(\Rightarrow\)x + 1 \(\in\)Ư_{( 15 )} = { 1 ; 3 ; 5 ; 15 }

Ta lập bảng :

Vậy : x \(\in\){ 0 ; 2 ; 4 ; 14 }

Để \(x+16⋮x+1\)

\(\Rightarrow\left(x+1\right)+15⋮x+1\)

Vì \(x+1⋮x+1\Rightarrow15⋮x+1\Leftrightarrow x+1\inƯ\left(15\right)\Rightarrow x+1\in\left\{1;3;5\right\}\Leftrightarrow x\in\left\{0;2;4\right\}\)

Vậy \(x\in\left\{0;2;4\right\}\)

Lời giải:

a. $9x^2-16-(3x-4)(2x+5)=0$

$\Leftrightarrow [(3x)^2-4^2]-(3x-4)(2x+5)=0$

$\Leftrightarrow (3x-4)(3x+4)-(3x-4)(2x+5)=0$

$\Leftrightarrow (3x-4)(3x+4-2x-5)=0$

$\Leftrightarrow (3x-4)(x-1)=0$

$\Leftrightarrow 3x-4=0$ hoặc $x-1=0$

$\Leftrightarrow x=\frac{4}{3}$ hoặc $x=1$.

b.

$x^2+4x=12$

$\Leftrightarrow x^2+4x-12=0$

$\Leftrightarrow (x^2-2x)+(6x-12)=0$

$\Leftrightarrow x(x-2)+6(x-2)=0$

$\Leftrightarrow (x-2)(x+6)=0$

$\Leftrightarrow x-2=0$ hoặc $x+6=0$

$\Leftrightarrow x=2$ hoặc $x=-6$

c.

$x^2-2x=35$

$\Leftrightarrow x^2-2x-35=0$

$\Leftrightarrow (x^2+5x)-(7x+35)=0$

$\Leftrightarrow x(x+5)-7(x+5)=0$

$\Leftrightarrow (x+5)(x-7)=0$

$\Leftrightarrow x+5=0$ hoặc $x-7=0$

$\Leftrightarrow x=-5$ hoặc $x=7$

a) 9 . x + 2 = 20

=> 9 . x = 20 - 2

=> 9 . x = 18

=> x = 18 : 9

=> x = 2

a} x=2

b}x1=12 , x2=2

c}x=13

a) \(6x+15\times8=12\times\left(19-x\right)\)

\(6x+120=228-12x\)

\(6x+120-228+12x=0\)

\(18x-108=0\)

\(18x=108\)

\(x=6\)

b) \(160-\left(35\div x+3\right)\times15=15\)

\(160-\left(35\div x+3\right)=1\)

\(35\div x+3=159\)

\(35\div x=156\)

\(x=\dfrac{35}{156}\)

c) \(2x-\left(1309\div11-19\right)-2=0\)

\(2x-1309\div11-19=2\)

\(2x-119-19=2\)

\(2x-119=21\)

\(2x=140\)

\(x=70\)

d) \(\left(x-7\right)\times\left(2x-16\right)=0\)

\(x-7=0;2x-16=0\)

\(x=7;2x=16\)

\(x=7;x=8\)

a) $6x+15\times 8=12\times \left(19-x\right)$

$6x+120=228-12x$

$6x+120-228+12x=0$

$18x-108=0$

$18x=108$

$x=6$

b) $160-\left(35÷x+3\right)\times 15=15$

$160-\left(35÷x+3\right)=1$

$35÷x+3=159$

$35÷x=156$

�=35156x=15635​
 

a) -32 -4.(x-5) = 0

<=>4.(x-5)=-32

<=>x-5=(-32):4

<=>x+5=-8

<=>x=-8+5

<=>x=-3

Vậy x=-3

b) 13.(x-5)=-169

<=>x-5=(-169):13

<=>x-5=-13

<=>x=-13+5

<=>x=-8

vậy x=-8

c) (-2).x+5 = (-3).(-3)+8

<=>(-2).x+5=17

<=>(-2).x=17-5

<=>(-2).x=12

<=>x=12:(-2)

<=>x=-6

Vậy x=-6

d) (-8).x = (-10).(-2)-4

<=>(-8).x=16

<=>x=16:(-8)

<=>x=-2

vậy x=-2

e) (-9).x+3 = (-2).(-7)+16

<=>(-9).x+3=30

<=>(-9).x=30-3

<=>(-9).x=27

<=>x=27:(-9)

<=>x=-3

Vậy x=-3