2003/2004=1 - 1/2004

2002/2003= 1- 2003

Vì: 1/2004< 1/2003 => 1- 1/2004> 1-2003

=> 2003/2004> 2002/2003

Ta có công thức (a^m)ⁿ=a^m.n

Ta có 3¹⁵¹ > 3¹⁵⁰

=> 3¹⁵⁰ = (3²)⁷⁵ = 9⁷⁵

=> 2²²⁵ = (2³)⁷⁵ = 8⁷⁵

=> 3¹⁵⁰ > 2²²⁵             (Vì  9⁷⁵ > 8⁷⁵)

Mà 3¹⁵¹ > 3¹⁵⁰ >2²²⁵

Vậy 3¹⁵¹ > 2²²⁵

Ta có công thức (a^m)ⁿ=a^m.n

Ta có 3¹⁵¹ > 3¹⁵⁰

=> 3¹⁵⁰ = (3²)⁷⁵ = 9⁷⁵

=> 2²²⁵ = (2³)⁷⁵ = 8⁷⁵

=> 3¹⁵⁰ > 2²²⁵             (Vì  9⁷⁵ > 8⁷⁵)

Mà 3¹⁵¹ > 3¹⁵⁰ >2²²⁵

Vậy 3¹⁵¹ > 2²²⁵

Ta có công thức (a^m)ⁿ=a^m.n

Ta có 3¹⁵¹ > 3¹⁵⁰

=> 3¹⁵⁰ = (3²)⁷⁵ = 9⁷⁵

=> 2²²⁵ = (2³)⁷⁵ = 8⁷⁵

=> 3¹⁵⁰ > 2²²⁵             (Vì  9⁷⁵ > 8⁷⁵)

Mà 3¹⁵¹ > 3¹⁵⁰ >2²²⁵

Vậy 3¹⁵¹ > 2²²⁵

\(^{2^{225}>3^{151}^{ }}\)

Có : 3^151 > 3^150 = (3^2)&65 = 9^75

2^225 = (2^3)^75 = 8^75

Vì 8^75 < 9^75 => 2^225 < 3^150

=> 2^225 < 3^151

Tk mk nha

Bn nao lam d minh t cho

2²²⁵=(2³)⁷⁵=8⁷⁵

3¹⁵¹>3¹⁵⁰=(3²)⁷⁵=9⁷⁵

vì 9⁷⁵>8⁷⁵=>2²²⁵<3¹⁵¹

CHTT 

tick nhìu nha mọi người

CHTT nha bạn ! 

2225 = 23.75 = (23)75 = 875

3150 = 32.75 = (32)75=975

8 < 9 ⇒ 875 < 975

Vậy : 2225 < 3150

Bài 8:

a) \(2^{225}=\left(2^3\right)^{75}=8^{75}\)

\(3^{150}=\left(3^2\right)^{75}=9^{75}\)

Vì \(8^{75}< 9^{75}\Rightarrow2^{225}< 3^{150}\)

b) \(2^{91}=\left(2^{13}\right)^7=8192^7\)

\(5^{35}=\left(5^5\right)^7=3125^7\)

Vì \(8192^7>3125^7\Rightarrow2^{91}>5^{35}\)

c) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\)

2²²⁵ = (2³)⁷⁵ = 8⁷⁵

3¹⁵¹ > 3¹⁵⁰ = (3²)⁷⁵ = 9⁷⁵

=> 3¹⁵¹ > 9⁷⁵ > 8⁷⁵

=> 3¹⁵¹ > 2²²⁵

4n - 5 chia hết cho 2n - 1

=> 4n - 2 - 3 chia hết cho 2n - 1

=> 2.(2n - 1) - 3 chia hết cho 2n - 1

Do 2.(2n - 1) chia hết cho 2n - 1 => 3 chia hết cho 2n - 1

Mà n thuộc N => 2n - 1 > hoặc = -1

=> 2n - 1 thuộc {-1 ; 1 ; 3}

=> 2n thuộc {0 ; 2 ; 4}

=> n thuộc {0 ; 1 ; 2}

2²²⁵ = (2³)⁷⁵ = 8⁷⁵

3¹⁵¹ > 3¹⁵⁰ = (3²)⁷⁵ = 9⁷⁵

=> 3¹⁵¹ > 9⁷⁵ > 8⁷⁵

=> 3¹⁵¹ > 2²²⁵

\(1,\\ a,2^x=16=2^4\Rightarrow x=4\\ b,3^{x+1}=9^x=3^{2x}\\ \Rightarrow x+1=2x\Rightarrow x=1\\ c,2^{3x+2}=4^{x+5}=2^{2\left(x+5\right)}\\ \Rightarrow3x+2=2x+10\Rightarrow x=8\\ d,3^{2x-1}=243=3^5\\ \Rightarrow2x-1=5\Rightarrow x=3\\ 2,\\ a,2^{225}=8^{75}< 9^{75}=3^{150}\\ b,2^{91}=\left(2^{13}\right)^7=8192^7>3125^7=\left(5^5\right)^7=5^{35}\\ c,99^{20}=\left(99^2\right)^{10}< \left(99\cdot101\right)^{10}=9999^{10}\\ 3,\\ a,12^8\cdot9^{12}=2^{16}\cdot3^8\cdot3^{24}=2^{16}\cdot3^{32}=\left(2\cdot3^2\right)^{16}=18^{16}\\ b,75^{20}=\left(3\cdot5^2\right)^{20}=3^{20}\cdot5^{40}=\left(3^{20}\cdot5^{10}\right)\cdot5^{30}=\left(3^2\cdot5\right)^{10}\cdot5^{30}=45^{10}\cdot5^{30}\)

Bài 1:

a) \(\Rightarrow2^x=2^4\Rightarrow x=4\)

b) \(\Rightarrow3^{x+1}=3^{2x}\Rightarrow x+1=2x\Rightarrow x=1\)

c) \(\Rightarrow2^{3x+2}=2^{2x+10}\Rightarrow3x+2=2x+10\Rightarrow x=8\)

d) \(\Rightarrow3^{2x-1}=3^5\Rightarrow2x-1=5\Rightarrow x=3\)

Bài 2:

a) \(2^{225}=\left(2^3\right)^{75}=8^{75}< 9^{75}=\left(3^2\right)^{75}=3^{150}\)

b) \(2^{91}=\left(2^{13}\right)^7=8192^7>3125^7=\left(5^5\right)^7=5^{35}\)

c) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\)

Bài 3:

a) \(12^8.9^{12}=\left(4.3\right)^8.9^{12}=4^8.3^8.9^{12}=2^{16}.9^4.9^{12}=2^{16}.9^{16}=\left(2.9\right)^{16}=18^{16}\)

b) \(75^{20}=\left(75^2\right)^{10}=5625^{10}=\left(45.125\right)^{10}=45^{10}.125^{10}=45^{10}.5^{30}\)