a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.

b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.

c) x :  7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.

d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.

e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.

g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135

Bài làm

a) \(\frac{x}{7}-\frac{3}{7}+\frac{1}{2}=\frac{31}{140}\)

                        \(\frac{x}{7}=\frac{31}{140}-\frac{1}{2}+\frac{3}{7}\)

                        \(\frac{x}{7}=\frac{31}{140}-\frac{70}{140}+\frac{60}{140}\)

                         \(\frac{x}{7}=\frac{21}{140}\)

                          \(\frac{x}{7}=\frac{3}{20}\)

=> \(x.20=3.7\)

=> \(x=\frac{3.7}{20}\)

=> \(x=\frac{21}{20}\)

Vậy \(x=\frac{21}{20}\)

b) \(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)

                             \(\frac{5}{x}=\frac{1}{2}+\frac{1}{8}-\frac{5}{12}\)

                             \(\frac{5}{x}=\frac{12}{24}+\frac{3}{24}-\frac{10}{24}\)

                             \(\frac{5}{x}=\frac{5}{24}\)

=> \(5.24=5.x\)

=> \(x=\frac{5.24}{5}\)

=> \(x=24\)

 Vậy \(x=24\)

# Học tốt #

b. \(\dfrac{45}{100}:3-\dfrac{24,5}{100}:5\)

=\(0,45:3-0,245:5\)

= 0,15 - 0,049

= 0,101

c. 0,56 - \(\dfrac{12}{100}\)+ \(\dfrac{3}{4}-1\)

= 0,56 - 0,12 + 0,75 - 1

= 0,19

d. ( 0,4 x 7 - \(\dfrac{140}{100}\):0,5) x \(\left(\dfrac{2}{100}+\dfrac{4}{100}+\dfrac{6}{100}+...+1\right)\)

= (2,8 - 2,8 ) x (0,02 + 0,04 +0,06 +...+1)

=0

Không có câu A nha!

           Bài làm :

\(a\text{)}...\Leftrightarrow\orbr{\begin{cases}x\div7-7=0\\x.3-12=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x\div7=7\\x.3=12\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=49\\x=4\end{cases}}\)

\(b\text{)}\Leftrightarrow...\Leftrightarrow x\div2=15\Leftrightarrow x=15.2=30\)

\(c\text{)}...\Leftrightarrow100\div x=20\Leftrightarrow x=100\div20=5\)

\(d\text{)}...\Leftrightarrow x\div5=27\Leftrightarrow x=27.5=135\)

a, x=5

b,x=20

c,x=1 hoặc x=-2

d, ko hiểu đề bài

e,x=2

f,x=80

\(a)\left(x-5\right).2=0\)

\(\Rightarrow x-5=0\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

\(b)x.3-13=47\)

\(\Rightarrow x.3=47+13\)

\(\Rightarrow x.3=60\)

\(\Rightarrow x=60:3\)

\(\Rightarrow x=20\)

Vậy \(x=20\)

\(c)\left(x.7-7\right)\left(x.12+24\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x.7-7=0\Rightarrow x.7=7\Rightarrow x=1\\x.12+24=0\Rightarrow x.12=-24\Rightarrow x=-2\end{cases}}\)

Vậy\(x\in\left\{1;-2\right\}\)

\(e)140-10.x=120\)

\(\Rightarrow10.x=140-120\)

\(\Rightarrow10.x=20\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

\(g)x.5-127=273\)

\(\Rightarrow x.5=273+127\)
\(\Rightarrow x.5=400\)

\(\Rightarrow x=400:5\)

\(\Rightarrow x=80\)

Vậy \(x=80\)

\(a)\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)

\(\Leftrightarrow\frac{x}{4}-\frac{1}{35}=\frac{31}{140}\)

\(\Leftrightarrow\frac{x}{4}=\frac{1}{4}\Leftrightarrow x=1\)

\(b)\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{12}\)

\(\Leftrightarrow\frac{5}{x}+\frac{7}{24}=\frac{1}{12}\)

\(\Leftrightarrow\frac{5}{x}=-\frac{5}{24}\Leftrightarrow x=-24\)

\(\frac{2}{5.7}+\frac{5}{7.12}+\frac{8}{12.20}+\frac{3}{140}\)

\(=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{20}+\frac{3}{140}\)

\(=\frac{1}{5}-\frac{1}{20}+\frac{3}{140}\)

\(=\frac{3}{20}+\frac{3}{140}\)

\(=\frac{6}{35}\)

(140 x \(\frac{7}{3}\) - 138 x \(\frac{5}{12}\)) : \(\frac{49}{6}\)=

=\(:\frac{49}{6}\)

=  (\(\frac{1960}{6}-\frac{345}{6}\)  ) :\(\frac{49}{6}\)

=\(\frac{1615}{6}:\frac{49}{6}\)

=\(\frac{1615}{49}\)