Bài giải

Ta có : 

\(\frac{2^{27}\cdot9^4}{6^9\cdot8^5}=\frac{2^{27}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^9\cdot\left(2^3\right)^5}=\frac{2^{27}\cdot3^8}{3^9\cdot2^9\cdot2^{15}}=\frac{2^{27}\cdot3^8}{3^9\cdot2^{24}}=\frac{2^{24}\cdot3^8\cdot2^3}{2^{24}\cdot3^8\cdot3}=\frac{2^3}{3}=\frac{8}{3}\)

                                                               Bài giải

Ta có : 

\(\frac{2^{27}\cdot9^4}{6^9\cdot8^5}=\frac{2^{27}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^9\cdot\left(2^3\right)^5}=\frac{2^{27}\cdot3^8}{3^9\cdot2^9\cdot2^{15}}=\frac{2^{27}\cdot3^8}{3^9\cdot2^{24}}=\frac{2^3}{3}=\frac{8}{3}\)

\(\frac{2^{27}.9^4}{6^9.8^5}=\frac{2^{27}.\left(3^2\right)^4}{\left(2.3\right)^9.\left(2^3\right)^5}=\frac{2^{27}.3^8}{2^9.3^9.2^{15}}=\frac{2^{27}.3^8}{2^{24}.3^9}=\frac{2^{27}}{2^{24}}.\frac{3^8}{3^9}=2^3.\frac{1}{3}=8.\frac{1}{3}=\frac{8}{3}\)

K^o tính dc vì ra số âm -58³

a)\(\dfrac{27^4.4^3}{9^5.8^2}\)

=\(\dfrac{3^{12}.2^6}{3^{10}.2^6}\)

=3\(^2\)=9

b)\(\dfrac{3^{29}.4^{16}}{27^9.8^{11}}\)

=\(\dfrac{3^{29}.2^{32}}{3^{27}.2^{33}}\)

=\(\dfrac{9}{2}\)

\(\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=\dfrac{3^{12}}{3^{10}}=3^2=9\)

_________

\(\dfrac{3^{29}.4^{16}}{27^9.8^{11}}=\dfrac{3^{29}.\left(2^2\right)^{16}}{\left(3^3\right)^9.\left(2^3\right)^{11}}=\dfrac{3^{29}.2^{32}}{3^{27}.2^{33}}=\dfrac{1}{3^2.2}=\dfrac{1}{9.2}=\dfrac{1}{18}\)

Mình sửa phần cuối câu 2:

\(...=\dfrac{3^2}{2}=\dfrac{9}{2}\)

các bạn ơi giúp đỡ mình với ạ 

Kết quả của phép tính 3^29.4^16/27^9.8^11 bằng :

A . 6

B . 2/9

C . 9/2

D . 1/6

a ) \(\frac{-5}{9}:\frac{-7}{18}+1\frac{2}{7}\)

\(=\frac{-5}{9}.-\frac{18}{7}+\frac{9}{7}\)

\(=\frac{-5.-18}{9.7}+\frac{9}{7}\)

\(=\frac{10}{7}+\frac{9}{7}\)

\(=\frac{10+9}{7}\)

\(=\frac{19}{7}\)

\(\frac{2^{27}\times9^4}{6^9\times8^5}=\frac{2^{27}\times\left(3^2\right)^4}{\left(2\times3\right)^9\times\left(2^3\right)^5}=\frac{2^{27}\times3^8}{2^9\times3^9\times2^{15}}=\frac{2^3}{3}=\frac{8}{3}\)

\(\sqrt{13^2}-5^2+\sqrt{3^2+4^2}-\sqrt{\left(-7\right)^2}=13-25+\sqrt{9+16}-\sqrt{49}=13-25+5-7=-14\)

Mấy câu này bạn bấm máy tính là ra thui

\(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)

\(=\frac{1}{1}+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)

\(=\frac{81}{81}+\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\)

\(=\frac{121}{81}\)

37,52 + 4,7 x 2,3 - 9,8

= 37,52 + 10,81 - 9,8

= 26,71 - 9,8

= 16,91

\(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)

\(=1+\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\)

\(=\frac{81}{81}+\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\)

\(=\frac{121}{81}\)