tìm x
a 13+x/20 = 3/4 b 23-x/25 = 4/5
tìm x biết:
a. 12+x \ 42 = 5/6
b. 25-x \ 40 = 3/8
c. 13+x \ 20 = 3/4
d. 23-x/25 = 4/5
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
tìm x
a. 13+x\20 = 3\4
b.23-x\25 = 4\5
b) \(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=23-\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}=\frac{555}{25}\)
=> x = 555
Mình làm cho bạn sao bạn không tick vậy
tìm x biết
a) \(\frac{13+x}{20}=\frac{3}{4}\)
b)\(\frac{23-x}{25}=\frac{4}{5}\)
a) \(\frac{13+x}{20}=\frac{3}{4}\)
\(\Rightarrow\frac{13+x}{20}=\frac{15}{20}\)
\(\Rightarrow13+x=15\)
\(\Rightarrow\) \(x=15-13\)
\(\Rightarrow\)\(x=2\)
b)\(\frac{23-x}{25}=\frac{4}{5}\)
\(\Rightarrow\frac{23-x}{25}=\frac{20}{25}\)
\(\Rightarrow23-x=20\)
\(\Rightarrow\) \(x=23-20\)
\(\Rightarrow\) \(x=3\)
a, 13+x/20= 3/4
Suy ra: ( 13+x). 4= 20.3
Suy ra: (13+x).4=60
Suy ra: 13+x=60:4
Suy ra: 13+x=15
Suy ra: x=15-13
Suy ra: x=2
Vậy x=2
a\(\frac{13+x}{20}=\frac{3}{4}\Rightarrow\left(13+x\right)\times4=20\times3\)
\(\left(13+x\right)\times4=60\)
\(13+x=60:4=15\)
\(x=15-13=2\)
Vậy x=2
b,\(\frac{23-x}{25}=\frac{4}{5}=\left(23-x\right)\times5=25\times4\)
\(\left(23-x\right)\times5=100\Rightarrow23-x=100:5=20\)
\(x=23-20=3\)
Vậy x = 3
Tim x:
a) \(\dfrac{13+x}{20}=\dfrac{3}{4}\)
b) \(\dfrac{23-x}{25}=\dfrac{4}{5}\)
`(13+x)/20 = 3/4`
`(13+x) xx4=3xx20`
`(13+x)xx4=60`
`13+x=60:4`
`13+x=15`
`x=15-13`
`x=2`
__
`(23-x)/25 =4/5`
`(23-x)xx5=4xx25`
`(23-x)xx5=100`
`23-x=100:5`
`23-x=20`
`x=23-20`
`x=3`
13+X/20=3/4
23-X/25=4/5
13 + x/20 = 3/4
x/20 = 3/4 - 13
x/20 = -49/4
=> x = - 49 x 20 / 4
x = - 245
cái này là theo ý kiến mk nhá !
tk ủng hộ mk nhé !!!!!!
13=x\20=3\4
23-x\25=4\5
Câu 1 sai đề.
Câu 2:
\(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}\)
\(x=555\)
Câu 2:
BÀI 1: Tính
1) -(-10)-(+14)
2) -(+15)-12
3) (-11)-(-13)
4) -(-13)-(-10)
5) -4-(+7)
BÀI 2: Tìm x biết:
1) x+(-5)= -(-7)
2) x-8= -(+10)
3) x-(-12)= 14
4) x-(+3)= -17
5) x+20= -(-23)
BÀI 3: Tính:
1) 17-(-19)-(+25)
2) -[-13]-[15]+(-20)
3) [-17]-(-16)-(+23)
4) -(-25)-[-14]+[-17]
BÀI 1: Tính
1) -(-10)-(+14)=10-14=-4
2) -(+15)-12=-15-12=-27
3) (-11)-(-13)=-11+13=2
4) -(-13)-(-10)=13+10=23
5) -4-(+7)=-4-7=-11
Bài 2 : tìm x:
a)x+(-5)=-(-7)
x=7+(-5)
x=2
vậy x=2
b)x-8=-(+10)
x-8=10
x=10+8
x=18
vậy x=18
c)x-(-12)=14
x+12=14
x=14-12
x=2
vậy x=2
d)x-(+3)=-17
x-3=17
x=17+3
x=20
vậy x=20
e)x+20=-(-23)
x+20=23
x=23-20
x=3
vậy x=3
BÀI 3:tính
a)17-(-9)-(+25)
=17+9-25
=26-25
=1
b)-[-13]-15+(-20)
=13-15-20
=-2-20
=-22
c)-17-(-16)-23
=-17+16-23
=-1-23
=-24
d)-(-25)-(-14)+(-17)
=25+14-17
=39-17
=22
cảm ơn bạn rất nhiều chúc bạn và gia đình mạnh khỏe, vui vẻ bên nhau và cùng đón 1 cái TẾT vui vẻ!
HAPPY NEW YEAR
haha ối giời ơi
bài 1: Quy đồng mẫu số các phân số sau
a) 17/20 , 13/15 và 41/60
b)25/75 , 17/34 và 121/132
bài 2 : Tính
a)5/23 x 17/26 + 5/23 x 9/26
b)3/4 x 7/9 + 7/4 x 3/9
c) 4/20 + 16/42 + 6/15 + 3/5 + 16/20 + 10/21
d) 3/7 x 14/5 x 35/9 x 81/7
bài 3: tìm x
a) x + 3/22 = 27/121 x 11/9
b)8/23 x 46/24 - x = 1/3
các bạn ghi cả cách tính cho mình nha thank nhìu
Bài 2:
a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\)
= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))
= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)
= \(\dfrac{5}{23}\)
b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\) \(\times\) \(\dfrac{3}{9}\)
= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)
= \(\dfrac{14}{12}\)
= \(\dfrac{7}{6}\)
1,a) \(\dfrac{17}{20}=\dfrac{51}{60};\dfrac{13}{15}=\dfrac{52}{60}\)
Bài 2.Tìm x:
a) 2017-(x-17)=169:13
b) [(25-x).3+21]:2-4=23
c)1+3+5+...+x=1600
Ta có : 1 + 3 + 5 + ..... + x = 1600
=> \(\frac{\text{[(x - 1) : 2 + 1](x + 1)}}{2}=1600\)
\(\Rightarrow\left(\frac{1}{2}x-\frac{1}{2}+1\right)\left(x+1\right)=3200\)
\(\Rightarrow\left(\frac{1}{2}x+\frac{1}{2}\right)\left(x+1\right)=3200\)
\(\Rightarrow\left(x+1\right)^2.\frac{1}{2}=3200\)
\(\Rightarrow\left(x+1\right)^2=6400\)
\(\Rightarrow x+1=80\)
=> x = 79