bằng 4 nha 

1 + 1 + 1 + 1 =4

hok tốt

1+1+1+1=4

k mk nha

= 122 nha

TL :

\(1+1+1-3+5-1-2+120=122\)

Hok tốt

1 + 1 + 1 - 3 + 5 - 1 - 2 + 120 = 122

Kb vs mk nha mn...Ok

hk tốt

toy chư có thi

mk cs nè, bạn cần ko??

\(1+4=5\)

1+4=5 kb với mk nha

hk tốt

Câu hỏi:

1 + 4 = ?

Trả lời:

1 + 4 = 5

Chúc bạn học tốt

3 và e 

k mình nha

1+1+1=3

2+3=5

kb rồi nha \^-^/

2+3 = 5 bn nhé

=246 nha bn,tk nha

Đáp án : 245

Tk nha!!

1+​1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+111+111

=1x22+111x2

=22+222

=244

ta có:  f(x) + g(x) = ( 7 x^6 - 6x ^5 +5x^4 -4x^3 +3x^2 -2x +1) - ( x - 2x^2 +3x^3 - 4x^4 + 5x^5 - 6x^6)

                          \(=7x^6-6x^5+5x^4-4x^3+3x^2-2x+1-x+2x^2-3x^3+4x^4-5x^5+6x^6\)

                      \(=\left(7x^6+6x^6\right)-\left(6x^5+5x^5\right)+\left(5x^4+4x^4\right)-\left(4x^3+3x^3\right)+\left(3x^2+2x^2\right)-\left(2x+x\right)+1\)

\(=13x^6-11x^5+9x^4-7x^3+5x^2-3x+1\)

Chúc bn học tốt !!!!!!

Uhhhhhhhhhhhhhhhhhhhhhhhhhh😥😥😥😥😥😥😥😥😥😥😥????????????...............

 \(a)P=\left(\dfrac{x^2+2}{x^3-1}+\dfrac{x+1}{x^2+x+1}+\dfrac{1}{1-x}\right).\left(\dfrac{x^2}{x+1}+1\right).\left(x\ne1;x\ne-1\right).\\ P=\dfrac{x^2+2+x^2-1-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}.\dfrac{x^2+x+1}{x+1}.\\ P=\dfrac{x^2-x}{x-1}.\dfrac{1}{x+1}.\\ P=\dfrac{x\left(x-1\right)}{x-1}.\dfrac{1}{x+1}.\\ P=x.\dfrac{1}{x+1}.\\ P=\dfrac{x}{x+1}.\)

\(P=\dfrac{1}{4}.\Rightarrow\dfrac{x}{x+1}=\dfrac{1}{4}.\\ \Leftrightarrow4x-x-1=0.\\ \Leftrightarrow3x-1=0.\\ \Leftrightarrow x=\dfrac{1}{3}\left(TM\right).\)