a) \(\frac{x}{27}=-\frac{2}{3}.6\)

      \(\frac{x}{27}=-4\)

      \(x:27=-4\)

       \(x=-4.27\)

        \(x=-108\)

Rồi tương tự nha

-0,52:x=-9.36:16.38

=-0,52:x=769,5

=>x=-0,52:769,5

=>x=-26/38475

-0,52:x=-9.36:16.38

=-0,52:x=769,5

=>x=-0,52:769,5

=>x=-26/38475

-0,52:x=-9.36:16.38

=-0,52:x=769,5

=>x=-0,52:769,5

=>x=-26/38475

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\Rightarrow\left(x+1\right)\left(x+3\right)=\left(0,5x+2\right)\left(2x+1\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+0,5x+4x+2\)

\(\Rightarrow x^2+3x+x-x^2-0,5x-4x=2-3\)

\(\Rightarrow-\frac{1}{2}x=-1\)

\(\Rightarrow x=2\)

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)

\(\Rightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)

\(\Rightarrow x^2+3x+x+3=x^2+4x+0,5x+2\)

\(\Rightarrow x^2+3x+x+3-x^2-4x-0,5x-2=0\)

\(\Rightarrow1-0,5x=0\)

\(\Rightarrow\frac{1}{2}x=1\Leftrightarrow x=2\)

\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(x+3\right)\)

\(\Leftrightarrow x^2+4x+3=x^2+4.5x+2\)

\(\Leftrightarrow0.5x+2=3\Leftrightarrow0.5x=1\Leftrightarrow x=2\)

\(\frac{x+1}{2x+1}\)\(=\)\(\frac{0,5x+2}{x+3}\)

  => (x+1).(x+3) = (2x+1).(0,5x+2)

  => x²+4x+3 = x²+4,5x+2

  => x²+4x-x²-4,5x = 2-3

  => -0,5x = -1

 =>  x      = -1:-0,5

 =>  x      = 2 

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)

\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=\left(0,5x+2\right)\left(2x+1\right)\)

\(\Leftrightarrow x^2+3x+x+3=x^2+0,5x+4x+2\)

\(\Leftrightarrow x^2+4x+3=x^2+4,5x+2\)

\(\Leftrightarrow4x+3=4,5x+2\)

\(\Leftrightarrow0,5x=-1\)

\(\Leftrightarrow x=-2\)

Tíck cho mìk vs nha Vân Nguyễn!

       \(\frac{1}{3}x-0,5x=0,75\)

\(\Leftrightarrow-\frac{1}{6}x=0,75\)

\(\Leftrightarrow\)\(x=-\frac{9}{2}\)

1/3x -0.5x = 0.75

(1/3 - 0.5)x = 0.75

-1/6x        =0.75

x              =0.75 : -1/6

x             =-9/2

tk mình nha .thank bạn nhiều:))

x. (1/3 - 0,5) = 0,75

x. (-1/6) = 3/4

x = 3/4 : (-1/6)

x = -9/2

1,3x+2/5x+7 =3x-1/5x+1

<=> 1,3x+2/5x-3x+1/5x = 1-7

<=> (1,3+2/5-3+1/5)x = -6

<=> -11/10x=-6

<=> x= -6 : (-11/10)

<=> x= 60/11

2.x+1/2x+1 = 0,5x+2/x +3

<=> 2x+1/2x-0,5x-2/1x = 3-1

<=> x(2+1/2-0,5-2 ) =2

<=>0x =2

<=> x=0 

Hinh nhu minh thay ban Kunzy Nguyen giai hoi sai

1,3x o dau ra ???????????????

 Hình như bạn Kunzy Nguyễn ghi nhầm 3x thành 1,3x nhỉ ?!!! 

1) áp dụng tính chất của dãy tỉ số bằng nhau ta có:

\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}=\frac{\left(3x+2\right)-\left(3x-1\right)}{\left(5x+7\right)-\left(5x+1\right)}=\frac{3x+2-3x+1}{5x+7-5x-1}=\frac{3}{6}=\frac{1}{2}\)

suy ra :

\(\frac{3x-1}{5x+1}=\frac{1}{2}\Rightarrow\left(5x+1\right).1=\left(3x-1\right).2\)

=> 5x+1=6x-2

5x-6x=-2-1

-x=-3

x=3

2)áp dụng tính chất của dãy tỉ số bằng nhau ta có;

\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}=\frac{\left(x+1\right)-2.\left(0,5x+2\right)}{\left(2x+1\right)-2.\left(x+3\right)}=\frac{x+1-x-4}{2x+1-2x-6}=\frac{-3}{-5}=\frac{3}{5}\)

suy ra:

\(\frac{x+1}{2x+1}=\frac{3}{5}\Rightarrow\left(2x+1\right).3=\left(x+1\right).5\)

=>6x+3=5x+5

6x-5x=5-3

x=2

 chỉ có làm mới có ăn

Tham khảo :

   ảnh lazi

  Ps: nhớ k 

                                                                                                                                                      # Aeri #