So sánh
\(\left(20^{2006}+11^{2006}\right)^{2007}\)và \(\left(20^{2007}+11^{2007}\right)^{2006}\)
Những câu hỏi liên quan
So sánh (20^2006+11^2006)^2007 và (20^2007+11^2007)^2006
Hãy so sánh:
\((20^{2006}+11^{2006})^{2007}\)và \((20^{2007}+11^{2007})^{2006}\)
Mọi người giúp mình với mình đang cần gấp!!!
so sánh :
a.3^300 +4^300 và 3.24^100
b.(20^2006 + 11^2006)^2007 và (20^2007 +11^2007)^2006
c.(1/2^2-1).(1/3^2-1).(1/4^2-1)..........(1/1000^2-1) và -1/2
Cho tỉ lệ thức \(\frac{a}{b}=\frac{c}{d}\)Chứng minh:
a)\(\frac{\left(20a^{2006}+11b^{2006}\right)^{2007}}{\left(20a^{2007}-11b^{2007}\right)^{2006}^{ }}=\frac{\left(20c^{2006}+11d^{2006}\right)^{2007}}{\left(20c^{2007}-11d^{2007}\right)^{2006}}\)
b)\(\left(4a+5b\right)\left(7c-11d\right)=\left(7a-11b\right)\left(4c+5d\right)\)
Cho frac{a}{b}frac{c}{d}. Chứng minh:a) frac{left(a-bright)^3}{left(c-dright)^3}frac{3a^2+2b^2}{3c^2+2d^2}b)frac{4a^4+5b^4}{4c^4+5d^4}frac{a^2b^2}{c^2d^2}c)left(frac{a-b}{c-d}right)^{2005}frac{2a^{2005}-b^{2005}}{2c^{2005}-d^{2005}}d)frac{2a^{2005}+5b^{2005}}{2c^{2005}+5d^{2005}}frac{left(a+bright)^{2005}}{left(c+dright)^{2005}}e)frac{left(20a^{2006}+11b^{2006}right)^{2007}}{left(20a^{2007}-11b^{2007}right)^{2006}}frac{left(20c^{2006}+11d^{2006}right)^{2007}}{left(20c^{2007}-11d^{2007}right)^{20...
Đọc tiếp
Cho \(\frac{a}{b}=\frac{c}{d}\). Chứng minh:
a) \(\frac{\left(a-b\right)^3}{\left(c-d\right)^3}=\frac{3a^2+2b^2}{3c^2+2d^2}\)
b)\(\frac{4a^4+5b^4}{4c^4+5d^4}=\frac{a^2b^2}{c^2d^2}\)
c)\(\left(\frac{a-b}{c-d}\right)^{2005}=\frac{2a^{2005}-b^{2005}}{2c^{2005}-d^{2005}}\)
d)\(\frac{2a^{2005}+5b^{2005}}{2c^{2005}+5d^{2005}}=\frac{\left(a+b\right)^{2005}}{\left(c+d\right)^{2005}}\)
e)\(\frac{\left(20a^{2006}+11b^{2006}\right)^{2007}}{\left(20a^{2007}-11b^{2007}\right)^{2006}}=\frac{\left(20c^{2006}+11d^{2006}\right)^{2007}}{\left(20c^{2007}-11d^{2007}\right)^{2006}}\)
f)\(\frac{\left(20a^{2007}-11c^{2007}\right)^{2006}}{\left(20a^{2006}+11c^{2006}\right)^{2007}}=\frac{\left(20b^{2007}-11d^{2007}\right)^{2006}}{\left(20b^{2006}+11d^{2006}\right)^{2007}}\)
ừ, bạn bik làm thì giúp mình nha ^^
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Tìm x biết : \(\frac{\left(2006-x\right)^2+\left(2006-x\right)\left(x-2007\right)+\left(x-2007\right)^2}{\left(2006-x\right)^2-\left(2006-x\right)\left(x-2007\right)+\left(x-2007\right)^2}=\frac{19}{49}\)
Đặt x -2006 = y
pt <=> \(\frac{y^2-y\left(y-1\right)+\left(y-1\right)^2}{y^2+y\left(y-1\right)+\left(y-1\right)^2}=\frac{19}{49}\)
<=> \(\frac{y^2-y^2+y+y^2-2y+1}{y^2+y^2-y+y^2-2y+1}=\frac{19}{49}\)
<=> \(\frac{y^2-y+1}{3y^2-3y+1}=\frac{19}{49}\)
<=> \(49y^2-49y+49=57y^2-57y+19\)
<=> \(8y^2-8y-30=0\)
<=> \(4y^2-4y+15=0\)
Giải tiếp nha
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\(\dfrac{1}{2007}.\left(\dfrac{1001}{2006}-2007\right)-\left(\dfrac{1}{2006}-2007\right).\dfrac{1001}{2006}\)=?
Tính :
\(\frac{1}{2007}.\left(\frac{1001}{2006}-2007\right)-\left(\frac{1}{2006}-2007\right).\frac{1001}{2007}\)
\(\frac{1}{2007}.\left(\frac{1001}{2006}-2007\right)-\left(\frac{1}{2006}-2007\right).\frac{1001}{2007}\)
\(=\left(\frac{1001}{2007.2006}-\frac{2007}{2007}\right)-\left(\frac{1001}{2006.2007}-\frac{2007.1001}{2007}\right)\)
\(=\frac{1001}{2007.2006}-\frac{1001}{2006.2007}-1+1001\)
\(=-1+1001\)
\(=1000\)
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Hãy so sánh:
a) \(3^{300}\)+ \(4^{300}\)và \(3.24^{100}\)
b) \((20^{2006}+11^{2006})^{2007}\)và \((20^{2007}+11^{2007})^{2006}\)
c) \(3333^{4444}\)và \(4444^{3333}\)