\(M=\frac{1}{1975}.\left(\frac{2}{1975}-1\right)-\frac{1}{1945}.\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}.\frac{1946}{1945}-\frac{3}{1975.1945}\)

Tính giá trị biểu thức

\(M=\frac{1}{1975}.\left(\frac{2}{1975}-1\right)-\frac{1}{1945}.\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}.\frac{1946}{1945}-\frac{3}{1975.1945}\)

Tính giá trị của biểu thức:

\(B=\frac{1}{1975}\left(\frac{2}{1945}-1\right)-\frac{1}{1945}\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}.\frac{1946}{1945}-\frac{3}{1975.1945}\)

Giúp mình với. Ai nhanh cho Like nhé! ^^

Rút gọn biểu thức 

\(B=\frac{1}{1975}.\left(\frac{2}{1945}-1\right)-\frac{1}{1945}.\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}.\frac{1946}{1945}-\frac{3}{1975.1945}\)

Rút gọn biểu thức : \(B=\frac{1}{1975}\times\left(\frac{2}{1945}-1\right)-\frac{1}{1945}\times\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}\times\frac{1946}{1945}-\frac{3}{1975\times1945}\)

Chứng tỏ rằng

\(\frac{1}{1945^2}\)\(+\frac{1}{1946^2}+\frac{1}{1947^2}+...+\frac{1}{1974^2}+\frac{1}{1975^2}\)<1/1944

Tính Q = \(\dfrac{1}{1275}.\left(\dfrac{x}{1945}-1\right)-\dfrac{1}{1945}.\left(1-\dfrac{x}{1975}\right)-\dfrac{1974}{1975}.\dfrac{1946}{1945}-\dfrac{3}{1975.1945}\)

M= 1/1975*(2+1/1945-1)-1/1945*(1-2/1975)-1974/1975*1946/1945-3/1975*1945

Tính M=\(\dfrac{1}{1975}\left(\dfrac{2}{1945}-1\right)-\dfrac{1}{1945}\left(1-\dfrac{2}{1975}\right)+\dfrac{1974}{1975}\times\dfrac{1946}{1945}-\dfrac{3}{1975\times1945}\)