Tìm x, biết :
( 2 + 2 + ...... + 2 ) x 2542 - 2,04 : x =19
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Tìm x :
( 2/31*33 + 2/33*35 + ....... + 2/39*41 ) * 2542 - 2,04 : x = 19
\(\left(\frac{2}{31\times33}+\frac{2}{33\times35}+...+\frac{2}{39\times41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\left(\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{35}+...+\frac{1}{39}-\frac{1}{41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\left(\frac{1}{31}-\frac{1}{41}\right)\times2542-2,04:x=19\)
\(\Rightarrow\frac{10}{1271}\times2542-2,04:x=19\)
\(\Rightarrow20-2,04:x=19\)
\(\Rightarrow2,04:x=20-19\)
\(\Rightarrow2,04:x=1\)
\(\Rightarrow x=2,04:1\)
\(\Rightarrow x=2,04\)
Vậy x = 2,04
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\(\left(\frac{2}{31\text{ x }33}+\frac{2}{33\text{ x }35}+...+\frac{2}{39\text{ x }41}\right)\text{ x }2542-2,04\text{ : }x=19\)
\(\left(\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{35}+...+\frac{1}{39}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=1\)
\(\left(\frac{1}{31}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=1\)
\(\frac{10}{1271}\text{ x }2542-2,04\text{ : }x=1\)
\(20-2,04\text{ : }x=1\)
\(2,04\text{ : }x=20-1\)
\(2,04\text{ : }x=19\)
\(x=2,04\text{ : }19\)
\(x=\frac{51}{475}\)
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\(\left(\frac{2}{31\text{ x }33}+\frac{2}{33\text{ x }35}+...+\frac{2}{39\text{ x }41}\right)\text{ x }2542-2,04\text{ : }x=19\)
\(\left(\frac{1}{31}-\frac{1}{33}+\frac{1}{33}-\frac{1}{35}+...+\frac{1}{39}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=19\)
\(\left(\frac{1}{31}-\frac{1}{41}\right)\text{ x }2542-2,04\text{ : }x=19\)
\(\frac{10}{1271}\text{ x }2542-2,04\text{ : }x=19\)
\(20-2,04\text{ : }x=19\)
\(2,04\text{ : }x=20-19\)
\(2,04\text{ : }x=1\)
\(x=2,04\text{ : }1\)
\(x=2,04\)
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Xem thêm câu trả lời
Tìm x biết : \(\left(\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+....+\frac{2}{19\cdot21}\right)\cdot462-\left(2,04:\left(x+1,05\right)\right):0,12=19\)
(2/11x13 +2/13x15 +...+2/19x21)x426-(2,04:(x+1,05)):0,12=19
tìm x hộ mình nhé
Tìm x, biết:
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right).462-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)
Tìm x biết:
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right).462-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)
Tìm x :
\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+...+\frac{2}{19\times21}\right)\times462-2,04\div\left(x+15\right)+11,02=30\)
\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+...+\frac{2}{19\times21}\right)\times462-2,04\div\left(x+15\right)+11,02=30\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-2,04\div\left(x+15\right)+11,02=30\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-2,04\div\left(x+15\right)=30-11,02\)
\(\frac{10}{231}\times462-2,04\div\left(x+15\right)=18,98\)
\(20-2,04\div\left(x+15\right)=18,98\)
\(2,04\div\left(x+15\right)=20-18,98\)
\(2,04\div\left(x+15\right)=1,02\)
\(x+15=2,04\div1,02\)
\(x+15=2\)
\(x=2-15\)
\(x=-13\)
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(\(\frac{2}{11.13}\)+\(\frac{2}{13.15} +\frac{2}{15.17}+...+\frac{2}{19.21}\)).462-[2,04:(x+1,05)]:0,12=19. Tìm x
Tim x
(2/11.13+2/13.15+...+2/19.21).462-[2,04:(x+1,05)]:0,12=19
Sao mk câu hỏi của bạn dùng mà tốn giấy vậy, tiết kiệm chút đi
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1
a) tìm các chữ số x và y để số 2x7y2 chia hết cho 36 . 0 bé hơn hoặc bằng x,y bé hơn hoặc bằng 9 ; x,y thuộc N
b) tìm số tự nhiên n sao cho 4n-5 chia hết cho 2n-1
c) tìm x biết :( 2 / 11.13 + 2 / 13.15+ ... + 2/ 19.21) . 462 - ( 2,04 : ( x+ 1, 05 ) ) : 0.12=19