\(\left(\frac{1111111111}{2222222222}+\frac{9999999999}{2222222222}+\frac{5555555555}{2222222222}+\frac{5555555555}{2222222222}\right)\) \(+\) \(90\)

\(=\) \(10+90\)

\(=\) \(100\)

1111111111111111111/22222222222222222222222222222+ggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

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2,2222222e + 19

3,333333333x10²⁰

33333333333x9999999999=3333333332966667

\(A=\frac{\text{9999999999}}{2}-\frac{\text{9999999999}}{3}-\frac{\text{9999999999}}{6}\)

\(A=\text{9999999999}\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=\text{9999999999}.0\)

\(A=0\)

Vậy A = B 

A = 0 nhé bạn tôi thề là đúng luôn

bạn ko cần cảm ơn đâu cho 1 k là ok

\(\frac{9999999999}{2}+\frac{9999999999}{3}+\frac{9999999999}{6}\)

\(=9999999999\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)\)

\(=9999999999\cdot1\)

\(=9999999999\)

Nhân xét biểu thức A, ta thấy:

   \(\frac{9999999999}{2}>\frac{9999999999}{3}>\frac{9999999999}{6}>0\)

=> \(A>0\left(đpcm\right)\)

ta có 9999999999/2=9999999999*3/2*3

9999999999/3=9999999999*2/3*2

suy ra 9999999999*3/2*3 - 9999999999*2/3*2=9999999999*3-9999999999*2/6=9999999999/6

suy ra A=9999999999/6-9999999999/6=0

vậy A=0

\(A=9999999999.\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=9999999999.0=0\)

Vậy A=0

Bằng 19 999 999 998

Bằng 1 999 999 998

=19999999998 nhé

chúc bạn học tốt

19999999998

= 19999999998

19999999998

9999999999x9999999999=99999999980000000001

9999999999 x 9999999999 = 9999999999^2

9999999999 x 9999999999 =9999999999^2