tìm x
\(B=|x+1.5|-4.5\)
\(2.|2.x-3|=\frac{1}{2}\)
\(7.5-3.|5-2.x|=-4.5\)
\(|3.x-4|+|3.y+5|=0\)
nhanh hộ mk, cần gấp-..-
3/4-2x|+1|=7/8
7.5-3|5-2x|=-4.5
|x+4/15|+1/2=3.5
Giúp tớ nhanh nhé các cậu, tớ đang cần gấp
(Ai đúng tớ tick nha)
3/4-2x| 1|=7/8
7.5-3|5-2x|=-4.5
|x +4/15|+ 1/2=3.5
Ai giúp mình với, Mình đang cần gấp
(Ai làm nhanh mình k nha)
a.\(\frac{1}{3}\)-\(|\frac{5}{4}-2x|\)=\(\frac{1}{4}\)
b.7.5-3 \(|5-2x|\)= -4.5
c. \(\frac{2}{3}+\frac{4}{5}\)\(|x-\frac{3}{4}|\)=\(\frac{7}{4}\)
d.\(|5x-4|=|x+2|\)
e.\(|2+3x|=|4x-3|\)
f.\(|\frac{7}{8}x+\frac{5}{6}|-|\frac{1}{2}x+5|=0\)
Bạn nào bt giúp mk với
x+2/15=1/3. H,1/3-2/3÷x=1/4. i,x/3+x/4+x/5=x/6 mk cần gấp lắm nha giải hộ mk nhanh nha❤❤❤
\(x+\frac{2}{15}=\frac{1}{3}\)
\(x=\frac{1}{3}-\frac{2}{15}\)
\(x=\frac{1}{5}\)
h, \(h,\frac{1}{3}-\frac{2}{3}:x=\frac{1}{4}\)
\(\frac{2}{3}:x\)= \(\frac{1}{3}-\frac{1}{4}\)
\(\frac{2}{3}:x=\frac{1}{12}\)
\(x=\frac{2}{3}:\frac{1}{12}\)
\(x=8\)
Tìm x biết :
1,(x-1).(y+5)=101
2,(x-2).(-y+5)=12
3,(x-5).(2x+6) < 0
4,(x-3).(2x+8) > 0
Làm nhanh nha . Mk cần gấp
1,(x-1)(y+5)=101
th1:x-1=101
<=>x=102
th2:y+5=101
<=>y=96
2,(x-2)(-y+5)=12
th1:x-2=12
<=>x=14
th2:-y+5=12
<=>-y=7
<=>y=-7
3,(x-5)(2x+6)<0
th1:x-5<0
<=>x<5
th2:2x+6<0
<=>2x<-6
<=>x<-3
Tìm x,y bt
a, (x^2-1)×(x^2-4)×(x^2-7)×(x^2-10)<0
b, (x^3 +5 )×(x^3+10)×(x^3+15)×(x^3+20)<0
Giúp mk vs mk đang cần gấp. Đúng mk tick cho
Tìm x,biết :
a,|x| -2,5 =27,5 b, 3/4+2/5.x=29/60 c,(x-1)^5=-32 d,4/5.x+0,5=4.5
a/|x|-2,5=27,5
=>|x|=27,5+2,5=30
=>x=30 hoặc x=-30
b/\(\dfrac{3}{4}+\dfrac{2}{5}.x=\dfrac{29}{60}\)
=>\(\dfrac{2}{5}.x\)=\(\dfrac{29}{60}-\dfrac{3}{4}\)=\(\dfrac{-4}{15}\)
=>x=\(\dfrac{-4}{15}:\dfrac{2}{5}\)=\(\dfrac{-2}{3}\)
c/(x-1)\(^5\)=-32
=>x-1=-2 vì (-2)\(^5\)=-32
=>x=-2+1=-1
d/\(\dfrac{4}{5}.x+0,5=4.5\)
=>\(\dfrac{4}{5}.x+0,5=20\)
=>\(\dfrac{4}{5}.x=20-0,5=19,5\)
=>\(x=19,5:\dfrac{4}{5}\)=\(\dfrac{195}{8}\)
\(1,\)
\(2x\left(x-3\right)-\left(3-x\right)=0\)
\(\Leftrightarrow2x\left(x-3\right)+\left(x-3\right)=0\)
\(\Leftrightarrow\left(2x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=3\end{cases}}\)
\(2,\)
\(3x\left(x+5\right)-6\left(x+5\right)=0\)
\(\Leftrightarrow\left(3x-6\right)\left(x+5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\x+5=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=-5\end{cases}}\)
\(3,\)
\(x^4-x^2=0\)
\(\Leftrightarrow x^2\left(x^2-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2=0\\x^2-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
\(4,\)
\(x^2-2x=0\)
\(\Leftrightarrow x\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-2=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}\)
\(5,\)
\(x\left(x+6\right)-10\left(x-6\right)=0\)
\(\Leftrightarrow x^2+6x-10x+60=0\)
\(\Leftrightarrow x^2-4x+60=0\)
\(\Leftrightarrow x^2-4x+4+56=0\)
\(\Leftrightarrow\left(x-2\right)^2=-56\)(Vô lý)
=> Phương trình vô nghiệm
1. Tĩm x :
a) \(\frac{11}{2}-\frac{2}{3}:|2x+\frac{-3}{2}|=3\)
b) \(|\frac{2}{7}x-\frac{1}{5}|-|-x+\frac{4}{9}|=0\)
NHANH LÊN NHA MK CẦN GẤP GẤP LẮM LẮM LUÔN LUÔN ĐÓ
AI NHANH MK CHO 1 TICK
1.
a) \(\frac{11}{2}-\frac{2}{3}:\left|2x+-\frac{3}{2}\right|=3\)
\(-\frac{2}{3}:\left|2x+-\frac{3}{2}\right|=3-\frac{11}{2}\)
\(-\frac{2}{3}:\left|2x+-\frac{3}{2}\right|=-\frac{5}{2}\)
\(\left|2x+-\frac{3}{2}\right|=-\frac{2}{3}:\left(-\frac{5}{2}\right)\)
\(\left|2x+-\frac{3}{2}\right|=\frac{4}{15}\)
\(\Rightarrow\left|2x+-\frac{3}{2}\right|\in\text{{}\frac{4}{15};-\frac{4}{15}\)}
Nếu, \(2x+\left(-\frac{3}{2}\right)=\frac{4}{15}\)
\(2x=\frac{53}{30}\)
\(x=\frac{53}{60}\)
Nếu, \(2x+\left(-\frac{3}{2}\right)=-\frac{4}{15}\)
\(2x=\frac{37}{30}\)
\(x=\frac{37}{60}\)
Vậy \(x\in\text{{}\frac{53}{60};\frac{37}{60}\)}
b) \(\left|\frac{2}{7}x-\frac{1}{5}\right|-\left|-x+\frac{4}{9}\right|=0\)
\(\left|\frac{2}{7}x-\frac{1}{5}\right|=\left|-x+\frac{4}{9}\right|\)
\(\Rightarrow\left|\frac{2}{7}x-\frac{1}{5}\right|\in\text{{}-x+\frac{4}{9};-\left(x+\frac{4}{9}\right)\)}
Nếu, \(\frac{2}{7}x-\frac{1}{5}=-x+\frac{4}{9}\)
\(x=\frac{203}{405}\)
Nếu, \(\frac{2}{7}x-\frac{1}{5}=-\left(-x+\frac{4}{9}\right)\)
\(\frac{2}{7}x-\frac{1}{5}=x-\frac{4}{9}\)
\(\frac{2}{7}x-x=\frac{1}{5}-\frac{4}{9}\)
\(-\frac{5}{7}x=-\frac{11}{45}\)
\(x=\frac{77}{225}\)
Vậy \(x\in\text{{}\frac{203}{405};\frac{77}{225}\)}
Tìm x, y biết:
a. (x-1)^2 + (y+3)^2 = 0
b. 2(x-5)^4 + 5|2y-7|^5 = 0
c. 3(x- 2y)^2004 + 4|y+1/2| = 0
d. |x+3y-1| + (2y-1/2)^2000 = 0
nhanh lên mình cần gấp lắm!